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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#641300 | #8720. BFS 序 0 | neetman | WA | 94ms | 37896kb | C++14 | 3.0kb | 2024-10-14 19:42:58 | 2024-10-14 19:43:03 |
Judging History
answer
#include<algorithm>
#include<iostream>
#include<cstdio>
using namespace std;
const int N = 3e5 + 5;
int n, m, q, tot, top;
int fa[N][20], head[N], dep[N], idx[N];
int vis[N], sta[N*2], maxn[N];
struct edge{
int u, v;
}e[N];
int cnt;
void addedge(int x, int y){
e[++cnt].u = head[x];
e[cnt].v = y;
head[x] = cnt;
}
void dfs(int x){
for(int i = 1; fa[x][i] = fa[fa[x][i-1]][i-1]; i ++);
for(int i = head[x]; i; i = e[i].u){
int to = e[i].v;
dep[to] = dep[x] + 1;
dfs(to);
}
idx[x] = ++tot;
}
int lca(int x, int y){
if(dep[x] != dep[y]){
if(dep[x] < dep[y]) swap(x, y);
for(int i = 19; ~i; i --){
if(dep[fa[x][i]] >= dep[y])
x = fa[x][i];
}
}
if(x == y) return x;
for(int i = 19; ~i; i --)
if(fa[x][i] != fa[y][i]){
x = fa[x][i];
y = fa[y][i];
}
return fa[x][0];
}
int main(){
ios::sync_with_stdio(0),cin.tie(0);
cin >> n;
for(int i = 2; i <= n; i ++){
cin >> fa[i][0];
addedge(fa[i][0], i);
}
dep[1] = 1;
dfs(1);
cin >> q;
bool jud;
while(q --){
cin >> m; jud = 1;
for(int i = 1; i <= m; i ++){
cin >> sta[i];
maxn[sta[i]] = dep[sta[i]];
if(vis[sta[i]])
jud = 0;
vis[sta[i]] = 1;
}
top = m;
// cout << "q = " << q << " jud = " << jud << '\n';
for(int i = m - 1; i; i --){
int LCA = lca(sta[i], sta[top]);
// cout << "TEST!! " << sta[i] << " " << sta[top] << " " << maxn[sta[i]] << " " << maxn[sta[top]] << '\n';
if(LCA == sta[i]){
sta[++top] = sta[i];
continue;
}
if(LCA == sta[top]){
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
maxn[sta[top]] = maxn[sta[i]];
}
else{
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
sta[++top] = LCA;
maxn[sta[top]] = maxn[sta[i]];
}
}
if(jud) cout << "Yes\n";
else cout << "No\n";
for(int i = 1; i <= top; i ++)
maxn[sta[i]] = vis[sta[i]] = 0;
// sort(sta + 1, sta + 1 + m, [](int x, int y){
// return idx[x] < idx[y];
// });
// siz = m;
// for(int i = 1; i < m; i ++){
// int LCA = lca(sta[i], sta[i + 1]);
// if(!is[LCA]){
// sta[++siz] = LCA;
// is[LCA] = 1;
// }
// if(!nex[sta[i]])
// }
// for(int i = 1; i <= siz; i ++){
// is[sta[i]] = nex[sta[i]] = L[sta[i]] = R[sta[i]] = in[sta[i]] = 0;
// }
}
return 0;
}
/*
6
1 1 3 2 4
10
4 3 6 2 5
1 4
3 2 4 5
5 2 5 4 6 3
3 1 4 2
3 5 6 3
5 4 5 2 6 1
4 4 3 2 5
4 4 6 2 3
3 3 2 6
*/
詳細信息
Test #1:
score: 100
Accepted
time: 2ms
memory: 9736kb
input:
6 1 1 3 2 4 10 4 3 6 2 5 1 4 3 2 4 5 5 2 5 4 6 3 3 1 4 2 3 5 6 3 5 4 5 2 6 1 4 4 3 2 5 4 4 6 2 3 3 3 2 6
output:
No Yes Yes No No No No No No Yes
result:
ok 10 token(s): yes count is 3, no count is 7
Test #2:
score: -100
Wrong Answer
time: 94ms
memory: 37896kb
input:
300000 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1...
output:
No No No No No No No No No No Yes Yes No Yes No Yes Yes Yes No No No No Yes No No Yes No No No No Yes Yes No No No Yes No No No No No No No Yes No Yes No Yes No No No No No Yes Yes No No Yes No No No No No Yes Yes No No No No No No No No Yes No No No Yes No No Yes No No Yes No Yes No No No Yes No No...
result:
wrong answer expected YES, found NO [2nd token]