QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#641300 | #8720. BFS 序 0 | neetman | WA | 94ms | 37896kb | C++14 | 3.0kb | 2024-10-14 19:42:58 | 2024-10-14 19:43:03 |
Judging History
answer
#include<algorithm>
#include<iostream>
#include<cstdio>
using namespace std;
const int N = 3e5 + 5;
int n, m, q, tot, top;
int fa[N][20], head[N], dep[N], idx[N];
int vis[N], sta[N*2], maxn[N];
struct edge{
int u, v;
}e[N];
int cnt;
void addedge(int x, int y){
e[++cnt].u = head[x];
e[cnt].v = y;
head[x] = cnt;
}
void dfs(int x){
for(int i = 1; fa[x][i] = fa[fa[x][i-1]][i-1]; i ++);
for(int i = head[x]; i; i = e[i].u){
int to = e[i].v;
dep[to] = dep[x] + 1;
dfs(to);
}
idx[x] = ++tot;
}
int lca(int x, int y){
if(dep[x] != dep[y]){
if(dep[x] < dep[y]) swap(x, y);
for(int i = 19; ~i; i --){
if(dep[fa[x][i]] >= dep[y])
x = fa[x][i];
}
}
if(x == y) return x;
for(int i = 19; ~i; i --)
if(fa[x][i] != fa[y][i]){
x = fa[x][i];
y = fa[y][i];
}
return fa[x][0];
}
int main(){
ios::sync_with_stdio(0),cin.tie(0);
cin >> n;
for(int i = 2; i <= n; i ++){
cin >> fa[i][0];
addedge(fa[i][0], i);
}
dep[1] = 1;
dfs(1);
cin >> q;
bool jud;
while(q --){
cin >> m; jud = 1;
for(int i = 1; i <= m; i ++){
cin >> sta[i];
maxn[sta[i]] = dep[sta[i]];
if(vis[sta[i]])
jud = 0;
vis[sta[i]] = 1;
}
top = m;
// cout << "q = " << q << " jud = " << jud << '\n';
for(int i = m - 1; i; i --){
int LCA = lca(sta[i], sta[top]);
// cout << "TEST!! " << sta[i] << " " << sta[top] << " " << maxn[sta[i]] << " " << maxn[sta[top]] << '\n';
if(LCA == sta[i]){
sta[++top] = sta[i];
continue;
}
if(LCA == sta[top]){
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
maxn[sta[top]] = maxn[sta[i]];
}
else{
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
sta[++top] = LCA;
maxn[sta[top]] = maxn[sta[i]];
}
}
if(jud) cout << "Yes\n";
else cout << "No\n";
for(int i = 1; i <= top; i ++)
maxn[sta[i]] = vis[sta[i]] = 0;
// sort(sta + 1, sta + 1 + m, [](int x, int y){
// return idx[x] < idx[y];
// });
// siz = m;
// for(int i = 1; i < m; i ++){
// int LCA = lca(sta[i], sta[i + 1]);
// if(!is[LCA]){
// sta[++siz] = LCA;
// is[LCA] = 1;
// }
// if(!nex[sta[i]])
// }
// for(int i = 1; i <= siz; i ++){
// is[sta[i]] = nex[sta[i]] = L[sta[i]] = R[sta[i]] = in[sta[i]] = 0;
// }
}
return 0;
}
/*
6
1 1 3 2 4
10
4 3 6 2 5
1 4
3 2 4 5
5 2 5 4 6 3
3 1 4 2
3 5 6 3
5 4 5 2 6 1
4 4 3 2 5
4 4 6 2 3
3 3 2 6
*/
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 2ms
memory: 9736kb
input:
6 1 1 3 2 4 10 4 3 6 2 5 1 4 3 2 4 5 5 2 5 4 6 3 3 1 4 2 3 5 6 3 5 4 5 2 6 1 4 4 3 2 5 4 4 6 2 3 3 3 2 6
output:
No Yes Yes No No No No No No Yes
result:
ok 10 token(s): yes count is 3, no count is 7
Test #2:
score: -100
Wrong Answer
time: 94ms
memory: 37896kb
input:
300000 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1...
output:
No No No No No No No No No No Yes Yes No Yes No Yes Yes Yes No No No No Yes No No Yes No No No No Yes Yes No No No Yes No No No No No No No Yes No Yes No Yes No No No No No Yes Yes No No Yes No No No No No Yes Yes No No No No No No No No Yes No No No Yes No No Yes No No Yes No Yes No No No Yes No No...
result:
wrong answer expected YES, found NO [2nd token]