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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#577787 | #9319. Bull Farm | 333zhan | TL | 64ms | 25280kb | C++20 | 4.2kb | 2024-09-20 14:48:18 | 2024-09-20 14:48:18 |
Judging History
answer
#include <bits/stdc++.h>
#define int long long
using namespace std;
inline int read () {
int w = 1, s = 0; char ch = getchar ();
for (; ! isdigit (ch); ch = getchar ()) if (ch == '-') w = -1;
for (; isdigit (ch); ch = getchar ()) s = (s << 1) + (s << 3) + (ch ^ 48);
return s * w;
}
constexpr int N = 2000;
void solve () {
int n, l, q;
cin >> n >> l >> q;
vector <vector <pair <int, int>>> edge (l);
for (int i = 0; i < l; i ++) {
string s;
cin >> s;
vector <int> t (n);
for (int j = 0; j < 2 * n; j += 2) {
t[j / 2] = (s[j] - 48) * 50 + (s[j + 1] - 48) - 1;
}
int sum2 = 0;
bool ok = true;
vector <int> cnt (n);
for (int j = 0; j < n; j ++) {
cnt[t[j]] ++;
if (cnt[t[j]] > 2) {
ok = false;
} else if (cnt[t[j]] == 2) {
sum2 ++;
}
}
if (sum2 > 1 || !ok) {
continue;
}
int zero = 0;
for (int j = 0; j < n; j ++) {
if (cnt[j] == 0) {
zero = j;
break;
}
}
if (sum2) {
for (int j = 0; j < n; j ++) {
if (cnt[t[j]] == 2) {
edge[i].push_back ({j, zero});
}
}
} else {
for (int j = 0; j < n; j ++) {
edge[i].push_back ({j, t[j]});
}
}
}
vector <vector <array <int, 3>>> qry (l);
vector <int> ans (q);
for (int i = 0; i < q; i ++) {
string s;
cin >> s;
array <int, 3> arr;
for (int j = 0; j < 6; j += 2) {
arr[j / 2] = (s[j] - 48) * 50 + (s[j + 1] - 48) - 1;
}
auto [a, b, c] = arr;
if (c >= 0) {
qry[c].push_back ({a, b, i});
} else {
if (a == b) {
ans[i] = 1;
}
}
}
vector <vector <int>> e (n);
for (int c = 0; c < l; c ++) {
for (auto [x, y] : edge[c]) {
e[x].push_back (y);
}
int ts = 0, cnt = 0;
vector <int> stk;
vector <int> dfn (n, -1), low (n, -1), id (n, -1);
auto tarjan = [&] (auto &&self, int x) -> void {
dfn[x] = low[x] = ++ ts;
stk.push_back (x);
for (auto y : e[x]) {
if (dfn[y] == -1) {
self (self, y);
low[x] = min (low[x], low[y]);
} else if (id[y] == -1) {
low[x] = min (low[x], dfn[y]);
}
}
if (low[x] == dfn[x]) {
int y;
do {
y = stk.back ();
stk.pop_back ();
id[y] = cnt;
} while (y != x);
cnt ++;
}
};
for (int i = 0; i < n; i ++) {
if (dfn[i] == -1) {
tarjan (tarjan, i);
}
}
set <pair <int, int>> ok;
vector <vector <int>> adj (cnt);
for (int x = 0; x < n; x ++) {
for (auto y : e[x]) {
if (id[x] != id[y]) {
if (ok.find ({id[x], id[y]}) == ok.end ()) {
ok.insert ({id[x], id[y]});
adj[id[x]].push_back (id[y]);
}
}
}
}
vector <bitset <N>> bit (cnt);
for (int i = 0; i < cnt; i ++) {
bit[i][i] = 1;
}
for (int x = cnt - 1; x >= 0; x --) {
for (auto y : adj[x]) {
bit[x] |= bit[y];
}
}
for (auto [a, b, i] : qry[c]) {
if (bit[id[a]][id[b]]) {
ans[i] = 1;
}
}
}
for (auto x : ans) {
cout << x;
}
cout << '\n';
}
signed main () {
ios::sync_with_stdio (false);
cin.tie (nullptr);
int T = 1;
cin >> T;
// T = read ();
while (T --) {
solve ();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3832kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3588kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: 0
Accepted
time: 49ms
memory: 3844kb
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...
result:
ok 200 lines
Test #4:
score: 0
Accepted
time: 64ms
memory: 25280kb
input:
1 2000 1 1000000 M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...
output:
000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...
result:
ok single line: '000101000101100010001000000010...0101000101000000000010101001000'
Test #5:
score: -100
Time Limit Exceeded
input:
1 2000 2000 1000000 FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...