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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#577787#9319. Bull Farm333zhanTL 64ms25280kbC++204.2kb2024-09-20 14:48:182024-09-20 14:48:18

Judging History

你现在查看的是最新测评结果

  • [2024-09-20 14:48:18]
  • 评测
  • 测评结果:TL
  • 用时:64ms
  • 内存:25280kb
  • [2024-09-20 14:48:18]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long

using namespace std;

inline int read () {
    int w = 1, s = 0; char ch = getchar ();
    for (; ! isdigit (ch); ch = getchar ()) if (ch == '-') w = -1;
    for (; isdigit (ch); ch = getchar ()) s = (s << 1) + (s << 3) + (ch ^ 48);
    return s * w;
}

constexpr int N = 2000;

void solve () {
    int n, l, q;
    cin >> n >> l >> q;

    vector <vector <pair <int, int>>> edge (l);
    for (int i = 0; i < l; i ++) {
        string s;
        cin >> s;

        vector <int> t (n);
        for (int j = 0; j < 2 * n; j += 2) {
            t[j / 2] = (s[j] - 48) * 50 + (s[j + 1] - 48) - 1;
        }

        int sum2 = 0;
        bool ok = true;
        vector <int> cnt (n);
        for (int j = 0; j < n; j ++) {
            cnt[t[j]] ++;
            if (cnt[t[j]] > 2) {
                ok = false;
            } else if (cnt[t[j]] == 2) {
                sum2 ++;
            }
        }

        if (sum2 > 1 || !ok) {
            continue;
        }

        int zero = 0;
        for (int j = 0; j < n; j ++) {
            if (cnt[j] == 0) {
                zero = j;
                break;
            }
        }
        if (sum2) {
            for (int j = 0; j < n; j ++) {
                if (cnt[t[j]] == 2) {
                    edge[i].push_back ({j, zero});
                }
            }
        } else {
            for (int j = 0; j < n; j ++) {
                edge[i].push_back ({j, t[j]});
            }
        }
    }

    vector <vector <array <int, 3>>> qry (l);

    vector <int> ans (q);
    for (int i = 0; i < q; i ++) {
        string s;
        cin >> s;

        array <int, 3> arr;
        for (int j = 0; j < 6; j += 2) {
            arr[j / 2] = (s[j] - 48) * 50 + (s[j + 1] - 48) - 1;
        }

        auto [a, b, c] = arr;
        if (c >= 0) {
            qry[c].push_back ({a, b, i});
        } else {
            if (a == b) {
                ans[i] = 1;
            }
        }
    }

    vector <vector <int>> e (n);

    for (int c = 0; c < l; c ++) {
        for (auto [x, y] : edge[c]) {
            e[x].push_back (y);
        }

        int ts = 0, cnt = 0;
        vector <int> stk;
        vector <int> dfn (n, -1), low (n, -1), id (n, -1);
        
        auto tarjan = [&] (auto &&self, int x) -> void {
            dfn[x] = low[x] = ++ ts;
            stk.push_back (x);
            for (auto y : e[x]) {
                if (dfn[y] == -1) {
                    self (self, y);
                    low[x] = min (low[x], low[y]);
                } else if (id[y] == -1) {
                    low[x] = min (low[x], dfn[y]);
                }
            }
            if (low[x] == dfn[x]) {
                int y;
                do {
                    y = stk.back ();
                    stk.pop_back ();
                    id[y] = cnt;
                } while (y != x);
                cnt ++;
            }
        };
        for (int i = 0; i < n; i ++) {
            if (dfn[i] == -1) {
                tarjan (tarjan, i);
            }
        }
        set <pair <int, int>> ok;
        vector <vector <int>> adj (cnt);
        for (int x = 0; x < n; x ++) {
            for (auto y : e[x]) {
                if (id[x] != id[y]) {
                    if (ok.find ({id[x], id[y]}) == ok.end ()) {
                        ok.insert ({id[x], id[y]});
                        adj[id[x]].push_back (id[y]);
                    }
                }
            }
        }

        vector <bitset <N>> bit (cnt);
        for (int i = 0; i < cnt; i ++) {
            bit[i][i] = 1;
        }
        for (int x = cnt - 1; x >= 0; x --) {
            for (auto y : adj[x]) {
                bit[x] |= bit[y];
            }
        }

        for (auto [a, b, i] : qry[c]) {
            if (bit[id[a]][id[b]]) {
                ans[i] = 1;
            }
        }
    }

    for (auto x : ans) {
        cout << x;
    }
    cout << '\n';
} 

signed main () {
	ios::sync_with_stdio (false);
    cin.tie (nullptr);
    
	int T = 1; 
	cin >> T;
	// T = read ();

	while (T --) {
		solve ();
	}
	
	return 0;
} 

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3832kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3588kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 49ms
memory: 3844kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 64ms
memory: 25280kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: