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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#569200 | #9319. Bull Farm | KobicGend | TL | 155ms | 19420kb | C++20 | 2.6kb | 2024-09-16 21:15:59 | 2024-09-16 21:16:00 |
Judging History
answer
#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <array>
#include <numeric>
#include <unordered_map>
#include <unordered_set>
#include <queue>
#include <stack>
#include <bitset>
using namespace std;
using ll = long long;
#include <vector>
#include <numeric>
struct DSU {
vector<int> p, siz;
DSU() {}
DSU(int n) {
init(n);
}
void init(int n) {
p.resize(n + 1);
iota(p.begin(), p.end(), 0);
siz.assign(n + 1, 1);
}
int find(int x) {
while (x != p[x]) x = p[x] = p[p[x]]; // 路径压缩
return x;
}
bool same(int x, int y) {
return find(x) == find(y);
}
bool uno(int x, int y) {
x = find(x), y = find(y);
if (same(x, y)) return false;
siz[x] += siz[y];
p[y] = x;
return true;
}
int size(int x) {
return siz[find(x)];
}
};
int read() {
char u, v;
cin >> u >> v;
return (u - 48) * 50 + v - 48;
}
void eachT() {
int n, l, q;
cin >> n >> l >> q;
vector<vector<pair<int, int>>> E(n + 1);
DSU dsu(n);
for (int i = 1; i <= l; ++i) {
vector<int> t(n + 1), cnt(n + 1);
for (int j = 1; j <= n; ++j) {
t[j] = read();
cnt[t[j]] += 1;
}
int mul = -1, zero = -1, ok = 1;
for (int j = 1; j <= n; ++j) {
if (cnt[j] == 2) {
if (mul == -1) mul = j;
else ok = 0;
}
if (cnt[j] == 0) {
if (zero == -1) zero = j;
else ok = 0;
}
}
if (!ok) continue;
if (mul == -1) {
for (int j = 1; j <= n; ++j) {
//if (dsu.uno(j, t[j])) {
E[j].emplace_back(i, t[j]);
//E[t[j]].emplace_back(i, j);
//}
}
}
else for (int j = 1; j <= n; ++j) {
if (cnt[t[j]] == 2) {
E[j].emplace_back(i, zero);
}
}
}
vector<vector<int>> ans(n + 1, vector<int>(n + 1, 0x3f3f3f3f));
for (int s = 1; s <= n; ++s) {
vector<int> vis(n + 1);
ans[s][s] = 0;
priority_queue<pair<int, int>, vector<pair<int, int>>, greater<>> Q;
Q.push({ 0, s });
while (!Q.empty()) {
auto [d, u] = Q.top(); Q.pop();
if (vis[u]) continue;
vis[u] = 1;
for (auto& [w, v] : E[u]) {
if (ans[s][v] > max(ans[s][u], w)) {
ans[s][v] = max(ans[s][u], w);
Q.push({ ans[s][v], v });
}
}
}
}
for (int i = 0; i < q; ++i) {
int a = read(), b = read(), c = read();
if (ans[a][b] <= c) cout << '1';
else cout << '0';
}
cout << '\n';
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int T = 1;
cin >> T;
while (T--) {
eachT();
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3828kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3876kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: 0
Accepted
time: 62ms
memory: 3676kb
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...
result:
ok 200 lines
Test #4:
score: 0
Accepted
time: 155ms
memory: 19420kb
input:
1 2000 1 1000000 M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...
output:
000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...
result:
ok single line: '000101000101100010001000000010...0101000101000000000010101001000'
Test #5:
score: -100
Time Limit Exceeded
input:
1 2000 2000 1000000 FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...