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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#569200#9319. Bull FarmKobicGendTL 155ms19420kbC++202.6kb2024-09-16 21:15:592024-09-16 21:16:00

Judging History

你现在查看的是最新测评结果

  • [2024-09-16 21:16:00]
  • 评测
  • 测评结果:TL
  • 用时:155ms
  • 内存:19420kb
  • [2024-09-16 21:15:59]
  • 提交

answer

#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <array>
#include <numeric>
#include <unordered_map>
#include <unordered_set>
#include <queue>
#include <stack>
#include <bitset>
using namespace std;
using ll = long long;
#include <vector>
#include <numeric>

struct DSU {
	vector<int> p, siz;

	DSU() {}
	DSU(int n) {
		init(n);
	}

	void init(int n) {
		p.resize(n + 1);
		iota(p.begin(), p.end(), 0);
		siz.assign(n + 1, 1);
	}

	int find(int x) {
		while (x != p[x]) x = p[x] = p[p[x]]; // 路径压缩
		return x;
	}

	bool same(int x, int y) {
		return find(x) == find(y);
	}

	bool uno(int x, int y) {
		x = find(x), y = find(y);
		if (same(x, y)) return false;
		siz[x] += siz[y];
		p[y] = x;
		return true;
	}

	int size(int x) {
		return siz[find(x)];
	}
};

int read() {
	char u, v;
	cin >> u >> v;
	return (u - 48) * 50 + v - 48;
}

void eachT() {
	int n, l, q;
	cin >> n >> l >> q;

	vector<vector<pair<int, int>>> E(n + 1);
	DSU dsu(n);
	for (int i = 1; i <= l; ++i) {
		vector<int> t(n + 1), cnt(n + 1);
		for (int j = 1; j <= n; ++j) {
			t[j] = read();
			cnt[t[j]] += 1;
		}
		int mul = -1, zero = -1, ok = 1;
		for (int j = 1; j <= n; ++j) {
			if (cnt[j] == 2) {
				if (mul == -1) mul = j;
				else ok = 0;
			}
			if (cnt[j] == 0) {
				if (zero == -1) zero = j;
				else ok = 0;
			}
		}
		if (!ok) continue;
		if (mul == -1) {
			for (int j = 1; j <= n; ++j) {
				//if (dsu.uno(j, t[j])) {
					E[j].emplace_back(i, t[j]);
					//E[t[j]].emplace_back(i, j);
				//}
			}
		}
		else for (int j = 1; j <= n; ++j) {
			if (cnt[t[j]] == 2) {
				E[j].emplace_back(i, zero);
			}
		}
	}

	vector<vector<int>> ans(n + 1, vector<int>(n + 1, 0x3f3f3f3f));
	for (int s = 1; s <= n; ++s) {
		vector<int> vis(n + 1);
		ans[s][s] = 0;
		priority_queue<pair<int, int>, vector<pair<int, int>>, greater<>> Q;
		Q.push({ 0, s });
		while (!Q.empty()) {
			auto [d, u] = Q.top(); Q.pop();
			if (vis[u]) continue;
			vis[u] = 1;
			for (auto& [w, v] : E[u]) {
				if (ans[s][v] > max(ans[s][u], w)) {
					ans[s][v] = max(ans[s][u], w);
					Q.push({ ans[s][v], v });
				}
			}
		}
	}

	for (int i = 0; i < q; ++i) {
		int a = read(), b = read(), c = read();
		if (ans[a][b] <= c) cout << '1';
		else cout << '0';
	}
	cout << '\n';
}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	int T = 1;
	cin >> T;

	while (T--) {
		eachT();
	}

	return 0;
}






Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3828kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3876kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: 0
Accepted
time: 62ms
memory: 3676kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

ok 200 lines

Test #4:

score: 0
Accepted
time: 155ms
memory: 19420kb

input:

1
2000 1 1000000
M=:]A@8UAY7W2JJ4KEHIA[HSCQ1ENSC`JXR;F3PJ:_@41P9Z=9HR8P<<:DUXRR9^WOQFL?NZP6S@=J0^WE32=6;\U0?88]Q_RNPUMT6YU<4<S]H?:7OCQYOT4YAV1^764ENWSDBED>M7A:BI>KSIR48JQ9B=N\5T3N4A2aF0@>3TI81<G7;YE>W`NMP<:IT4CI3D0=GZC3I\CLQJQBA9BDIS9SAM55KaVA<Z@D=>:Y?CQHUQ5U3a6UVI8OKX9_FAF^7=5M85;<0;8YPAM<7Z7PP7A=N...

output:

000101000101100010001000000010010110000001000001001100000000010000100001000000101100000000010000001000000001110000010110100000111100100000001000000000011001010001000001001000100000000100011001100110010000010000101100000011111000000010000101010010000000010101000001010111100000100000000000000101000100...

result:

ok single line: '000101000101100010001000000010...0101000101000000000010101001000'

Test #5:

score: -100
Time Limit Exceeded

input:

1
2000 2000 1000000
FVAaH7GRPO;_11Da5J18@3SMG==\G8E8S^6:M4L0JH>MN5IXT>2<7WJ3U8LVJS=;;3F13>0D0>VOIIU@EPHG6ABL6;K?T1PXDERLG07]5C9^GDKG<SBMIW;`4W8P3=469TIPKH0O34523_J5C2MJ17D25Z@=K8H@M>WK<CMK7EO]BPD7B6AW741J5YIHIa1:ERSG>L3N2^F3<4F`DLE@2AA5=8GZK6:192FB736[WMV7:^DA2C:<LK040VJBM3M]WXU50`407TR_?PLF@5VL7OSL...

output:


result: