QOJ.ac

QOJ

ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#434526	#4800. Oscar's Round Must Have a Constructive Problem	ship2077	WA	18ms	3928kb	C++14	824b	2024-06-08 16:29:29	2024-06-08 16:29:33

Judging History

你现在查看的是最新测评结果

[2024-06-08 16:29:33]
评测

测评结果：WA
用时：18ms
内存：3928kb

查看

[2024-06-08 16:29:29]
提交

answer

#include<bits/stdc++.h>
using namespace std;
mt19937 mt(time(NULL));
constexpr int M=1e5+5;
int n,cnt,num,p[M],per[M];
int read(){
	int x=0;char ch=getchar();
	while (!isdigit(ch)) ch=getchar();
	while (isdigit(ch)) x=x*10+ch-48,ch=getchar();
	return x;
}
int rnd(int l,int r){return mt()%(r-l+1)+l;}
void solve(){ n=read();num=0;
	for (int i=1;i<=n;i++) p[i]=read();
	for (int i=1;i<=n;i++) num+=p[i]==p[1];
	if (num==n) return puts("NO"),void();
	iota(per+1,per+n+1,1);
	cnt=0;while (1){ bool flag=0;
		for (int i=1;i<n;i++)
			if (per[i]==p[i]) flag=1,
				swap(per[i],per[rnd(i+1,n)]);
		if (per[n]==p[n]) swap(per[n],per[rnd(1,n-1)]);
		cnt++; if (!flag) break;
	} puts("YES");
	for (int i=1;i<=n;i++) printf("%d%c",per[i]," \n"[i==n]);
}
int main(){int T=read();while (T--) solve();return 0;}

源文件, 语言: C++14

詳細信息

Test #1:

score: 100

Accepted

time: 0ms

memory: 3904kb

input:

3
3
3 3 3
3
3 2 1
6
1 1 4 5 1 4

output:

NO
YES
1 3 2
YES
5 2 3 4 6 1

result:

ok ok

Test #2:

score: -100

Wrong Answer

time: 18ms

memory: 3928kb

input:

output:

NO
NO
YES
2 1
YES
1 2
NO
NO
YES
2 3 1
YES
2 3 1
YES
3 1 2
YES
2 1 3
YES
3 1 2
YES
2 1 3
YES
3 2 1
YES
3 1 2
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 3 2
NO
YES
1 3 2
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 3 2
YES
2 3 1
YES
1 3 2
YES
1 2 3
YES
1 2 3
NO
NO
YES
2 3 4 1
YES
4 2 3 1...

result:

wrong answer P_1 == A_1.