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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#434526#4800. Oscar's Round Must Have a Constructive Problemship2077WA 18ms3928kbC++14824b2024-06-08 16:29:292024-06-08 16:29:33

Judging History

你现在查看的是最新测评结果

  • [2024-06-08 16:29:33]
  • 评测
  • 测评结果:WA
  • 用时:18ms
  • 内存:3928kb
  • [2024-06-08 16:29:29]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
mt19937 mt(time(NULL));
constexpr int M=1e5+5;
int n,cnt,num,p[M],per[M];
int read(){
	int x=0;char ch=getchar();
	while (!isdigit(ch)) ch=getchar();
	while (isdigit(ch)) x=x*10+ch-48,ch=getchar();
	return x;
}
int rnd(int l,int r){return mt()%(r-l+1)+l;}
void solve(){ n=read();num=0;
	for (int i=1;i<=n;i++) p[i]=read();
	for (int i=1;i<=n;i++) num+=p[i]==p[1];
	if (num==n) return puts("NO"),void();
	iota(per+1,per+n+1,1);
	cnt=0;while (1){ bool flag=0;
		for (int i=1;i<n;i++)
			if (per[i]==p[i]) flag=1,
				swap(per[i],per[rnd(i+1,n)]);
		if (per[n]==p[n]) swap(per[n],per[rnd(1,n-1)]);
		cnt++; if (!flag) break;
	} puts("YES");
	for (int i=1;i<=n;i++) printf("%d%c",per[i]," \n"[i==n]);
}
int main(){int T=read();while (T--) solve();return 0;}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3904kb

input:

3
3
3 3 3
3
3 2 1
6
1 1 4 5 1 4

output:

NO
YES
1 3 2
YES
5 2 3 4 6 1

result:

ok ok

Test #2:

score: -100
Wrong Answer
time: 18ms
memory: 3928kb

input:

50069
1
1
2
1 1
2
1 2
2
2 1
2
2 2
3
1 1 1
3
1 1 2
3
1 1 3
3
1 2 1
3
1 2 2
3
1 2 3
3
1 3 1
3
1 3 2
3
1 3 3
3
2 1 1
3
2 1 2
3
2 1 3
3
2 2 1
3
2 2 2
3
2 2 3
3
2 3 1
3
2 3 2
3
2 3 3
3
3 1 1
3
3 1 2
3
3 1 3
3
3 2 1
3
3 2 2
3
3 2 3
3
3 3 1
3
3 3 2
3
3 3 3
4
1 1 1 1
4
1 1 1 2
4
1 1 1 3
4
1 1 1 4
4
1 1 2 1
...

output:

NO
NO
YES
2 1
YES
1 2
NO
NO
YES
2 3 1
YES
2 3 1
YES
3 1 2
YES
2 1 3
YES
3 1 2
YES
2 1 3
YES
3 2 1
YES
3 1 2
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 3 2
NO
YES
1 3 2
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 2 3
YES
1 2 3
YES
3 2 1
YES
1 3 2
YES
2 3 1
YES
1 3 2
YES
1 2 3
YES
1 2 3
NO
NO
YES
2 3 4 1
YES
4 2 3 1...

result:

wrong answer P_1 == A_1.