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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#178098#5377. $N$ 门问题zhoukangyang#0 1ms8056kbC++111.9kb2023-09-13 17:57:582024-07-04 01:56:29

Judging History

你现在查看的是最新测评结果

  • [2024-07-04 01:56:29]
  • 评测
  • 测评结果:0
  • 用时:1ms
  • 内存:8056kb
  • [2023-09-13 17:57:58]
  • 提交

answer

#include<bits/stdc++.h>
#define L(i, j, k) for(int i = (j); i <= (k); i++)
#define R(i, j, k) for(int i = (j); i >= (k); i--)
#define ll long long
#define ull unsigned long long 
#define sz(a) ((int) a.size())
#define vi vector<int>
#define me(a, x) memset(a, x, sizeof(a))
using namespace std;
const int N = 1 << 21, L = 5e5, mod = 998244353;

double f[N];

ll n;

int k;
ll a[N], b[N];
ll rd() {
	cin >> k;
	L(i, 1, k) {
		cin >> a[i] >> b[i];
	}
	n = 0;
	while(true) {
		int win = 1;
		L(i, 1, k) {
			if(n % b[i] != a[i]) {
				win = 0;
				break;
			}
		}
		if(win) break;
		++n;
		if(n > 200) {
			n = -1;
			break;
		}
	}
	return n;
}

map < vector < double >, double > MP[10];
double slv(vector < double > a, int cur) { 
	if(sz(a) == 2) {
		return cur == 0;
	}
	if(cur > 1) 
		swap(a[1], a[cur]), cur = 1;
	sort(a.begin() + 2, a.end());
	if(MP[cur].count(a)) return MP[cur][a];
	double win = 1;
	L(p, 1, sz(a) - 1) if(p != cur) {
		double sum1 = 0, sum2 = 0;
		L(i, 0, sz(a) - 1) if(i != cur) {
			sum1 += a[i];
			if(i != p) sum2 += a[i];
		}
		sum1 /= sum2;
		vector < double > b;
		L(i, 0, sz(a) - 1) {
			if(i == cur) b.emplace_back(a[i]);
			else if(i != p) b.emplace_back(a[i] * sum1);
		}
		
		double mx = 0;
		L(i, 0, sz(b) - 1) {
			mx = max(mx, b[i]);
		}
		
		int total = 0;
		double sum = 0;
		L(i, 0, sz(b) - 1) {
			if(fabs(b[i] - mx) <= 1e-9) {
				total += 1;
				sum += slv(b, i);
			}
		}
		
		sum /= total;
		
		win = min(win, sum);
	}
	return MP[cur][a] = win;
}

int main () { 
	ios :: sync_with_stdio(false);
	cin.tie (0); cout.tie (0);
	n = rd();
	if(n < 2) {
		cout << "error\n";
		return 0;
	}
	vector < double > f(n);
	L(i, 0, n - 1) {
		f[i] = 1;
	}
	double ans = n > 13 ? (slv(f, 0) + slv(f, 1) * (n - 1)) / n : 0;
	cout.precision(6); cout << fixed;
	cout << ans << '\n';
	return 0;
}

/*
(n-1)/(n-2) 1 [(n-1)/(n-2)] (n-1)/(n-2) (n-1)/(n-2) x 
*/

Details

Tip: Click on the bar to expand more detailed information

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 8044kb

input:

1
2 3

output:

0.000000

result:

wrong answer 1st lines differ - expected: '0.500000', found: '0.000000'

Subtask #2:

score: 0
Wrong Answer

Test #6:

score: 10
Accepted
time: 1ms
memory: 7632kb

input:

8
1 160005726539569
1 233
0 1
1 2947295521
1 686719856393
1 54289
1 12649337
1 37281334283719577

output:

error

result:

ok single line: 'error'

Test #7:

score: -10
Wrong Answer
time: 1ms
memory: 8056kb

input:

10
2 64
0 2
2 512
2 4
2 32
2 16
2 256
0 1
2 8
2 128

output:

0.000000

result:

wrong answer 1st lines differ - expected: '0.500000', found: '0.000000'

Subtask #3:

score: 0
Skipped

Dependency #2:

0%

Subtask #4:

score: 0
Skipped

Dependency #3:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

0%

Subtask #6:

score: 0
Wrong Answer

Test #57:

score: 0
Wrong Answer
time: 1ms
memory: 7696kb

input:

15
15 17
2 3
5 31
4 5
12 29
38 41
3 11
44 47
16 23
11 19
6 13
3 37
1 2
21 43
5 7

output:

error

result:

wrong answer 1st lines differ - expected: '0.000000', found: 'error'

Subtask #7:

score: 0
Skipped

Dependency #1:

0%