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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#142811 | #4564. Digital Circuit | APROHACK# | 0 | 33ms | 25524kb | C++14 | 2.5kb | 2023-08-19 23:12:06 | 2024-07-04 02:40:26 |
Judging History
answer
#include "circuit.h"
#include <cstring>
#include <vector>
#define ll long long
#define ff first
#define ss second
#define pb push_back
using namespace std;
int n, m;
vector<int>child[100001];
bool state[100001];
ll encen[100001][2]; // encendido y apagado
const int MOD = 1000002022;
int past[2002][2002];
void generate(int node);
int parent[100001];
void init(int N, int M, std::vector<int> P, std::vector<int> A) {
n = N;
m = M;
for(int i = 0 ; i < n+m ; i ++){
if(P[i] != -1){
child[P[i]].pb(i);
}
parent[i] = P[i];
}
for(int i = N ; i <= N+M ; i ++)state[i] = A[i-N];
memset(past, -1, sizeof past);
generate(0);
}
ll mem[2002][2002];
int currentIt = -1;
void newDp(){
currentIt++;
}
ll dp(int parent, int i, int k){
if(k < 0)return 0;
if(i == child[parent].size() and k > 0)return 0;
else if(i == child[parent].size()) return 1;
if(past[i][k] == currentIt)return mem[i][k];
past[i][k] = currentIt;
return mem[i][k] = (dp(parent, i+1, k-1) * encen[child[parent][i]][0] + dp(parent, i+1, k) * encen[child[parent][i]][1])%MOD;
}
void generate(int node){
if(node >= n){
if(state[node]){
encen[node][0] = 1;
encen[node][1] = 0;
}else{
encen[node][0] = 0;
encen[node][1] = 1;
}
return ;
}
for(int i = 0 ; i < child[node].size() ; i ++){
generate(child[node][i]);
}
newDp();
ll enc = 0;
for(int i = 1 ; i <= child[node].size() ; i ++){
enc += dp(node, 0, i) * i;
enc %= MOD;
}
ll allWays = 1;
for(int i = 0 ; i < child[node].size() ; i ++){
allWays *= (encen[child[node][i]][0] + encen[child[node][i]][1]);
allWays %= MOD;
}
allWays *= child[node].size();
allWays %= MOD;
encen[node][0] = enc;
encen[node][1] = ((allWays - enc) + MOD) % MOD;
//cout << "for node " << node << " there are " << encen[node][0] << ", " << encen[node][1] << "\n";
}
void recargar(int node){
if(node >= n){
if(state[node]){
encen[node][0] = 1;
encen[node][1] = 0;
}else{
encen[node][0] = 0;
encen[node][1] = 1;
}
return ;
}
newDp();
ll enc = 0;
for(int i = 1 ; i <= child[node].size() ; i ++){
enc += dp(node, 0, i) * i;
enc %= MOD;
}
ll allWays = 1;
for(int i = 0 ; i < child[node].size() ; i ++){
allWays *= (encen[child[node][i]][0] + encen[child[node][i]][1]);
allWays %= MOD;
}
allWays *= child[node].size();
allWays %= MOD;
encen[node][0] = enc;
encen[node][1] = ((allWays - enc) + MOD) % MOD;
if(parent[node] != -1)recargar(parent[node]);
}
int count_ways(int L, int R) {
ll ans = 0;
for(int i = L ; i <= R ; i ++){
state[i] = !state[i];
}
if(L == R)recargar(L);
else generate(0);
return encen[0][0];
}
详细
Subtask #1:
score: 0
Wrong Answer
Test #1:
score: 0
Wrong Answer
time: 2ms
memory: 25392kb
input:
1 2 -1 0 0 0 0 1 1 2 2 1 2 2 2 1 2 -1 -1 -2 -2
output:
0 0 0 0 1
result:
wrong answer 3rd lines differ - expected: '1', found: '0'
Subtask #2:
score: 0
Wrong Answer
Test #9:
score: 0
Wrong Answer
time: 2ms
memory: 25524kb
input:
1 2 -1 0 0 0 0 1 1 2 2 1 2 2 2 1 2 -1 -1 -2 -2
output:
0 0 0 0 1
result:
wrong answer 3rd lines differ - expected: '1', found: '0'
Subtask #3:
score: 0
Skipped
Dependency #1:
0%
Subtask #4:
score: 0
Wrong Answer
Test #43:
score: 0
Wrong Answer
time: 33ms
memory: 24312kb
input:
32767 32768 -1 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50...
output:
394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 394586018 ...
result:
wrong answer 3rd lines differ - expected: '431985922', found: '394586018'
Subtask #5:
score: 0
Skipped
Dependency #4:
0%
Subtask #6:
score: 0
Skipped
Dependency #2:
0%
Subtask #7:
score: 0
Skipped
Dependency #3:
0%
Subtask #8:
score: 0
Skipped
Dependency #1:
0%