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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#99513#6329. Colorful GraphSorting#WA 513ms7552kbC++5.3kb2023-04-22 20:01:152023-04-22 20:01:19

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-22 20:01:19]
  • 评测
  • 测评结果:WA
  • 用时:513ms
  • 内存:7552kb
  • [2023-04-22 20:01:15]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std ;
typedef long long ll ;
typedef unsigned long long ull ;
typedef pair < int , int > pii ;
typedef vector<int> vi;
#define fi first
#define se second
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());

#define MAXN 15007
#define inf 1000000007

namespace flow {
    int n ;
    int source ;
    int sink ;
    struct tuhla {
        int to ;
        int flow , cap ;
        int rev ;
        tuhla ( ) { to = flow = cap = rev = 0 ; }
        tuhla ( int _to , int _cap , int _rev ) {
            to = _to , cap = _cap , flow = 0 , rev = _rev ;
        }
    };
    vector < tuhla > v[ MAXN ] ;
    int sz[ MAXN ] ;
    int lvl[ MAXN ] ;
    int pos[ MAXN ] ;
    void add_edge ( int x , int y , int cap ) {
        v[ x ].push_back ( tuhla ( y , cap , sz[ y ] ) ) ;
        v[ y ].push_back ( tuhla ( x , 0 , sz[ x ] ) ) ;
        ++ sz[ x ] , ++ sz[ y ] ;
    }
    bool bfs ( int st ) {
        queue < int > q ;
        for ( int i = 1 ; i <= n ; ++ i ) {
            lvl[ i ] = pos[ i ] = 0 ;
        }
        lvl[ st ] = 1 ;
        q.push ( st ) ;
        while ( !q.empty ( ) ) {
            int x = q.front ( ) ;
            q.pop ( ) ;
            for ( int i = 0 ; i < sz[ x ] ; ++ i ) {
                if ( lvl[ v[ x ][ i ].to ] == 0 && v[ x ][ i ].flow != v[ x ][ i ].cap ) {
                    lvl[ v[ x ][ i ].to ] = lvl[ x ] + 1 , q.push ( v[ x ][ i ].to ) ;
                }
            }
        }
        return ( lvl[ sink ] != 0 ) ;
    }
    int dfs ( int vertex , int curr ) {
        if ( curr == 0 || vertex == sink ) { return curr ; }
        for ( ; pos[ vertex ] < sz[ vertex ] ; ++ pos[ vertex ] ) {
            if ( lvl[ v[ vertex ][ pos[ vertex ] ].to ] == lvl[ vertex ] + 1 ) {
                int aux = dfs ( v[ vertex ][ pos[ vertex ] ].to , min ( curr , v[ vertex ][ pos[ vertex ] ].cap - v[ vertex ][ pos[ vertex ] ].flow ) ) ;
                v[ vertex ][ pos[ vertex ] ].flow += aux ;
                v[ v[ vertex ][ pos[ vertex ] ].to ][ v[ vertex ][ pos[ vertex ] ].rev ].flow -= aux ;
                if ( aux > 0 ) { return aux ; }
            }
        }
        return 0 ;
    }
    long long maxflow ( ) {
        long long maxflow = 0 ;
        while ( bfs ( source ) == true ) {
            while ( 1 ) {
                int flow = dfs ( source , inf ) ;
                if ( flow == 0 ) { break ; }
                maxflow += flow ;
            }
        }
        return maxflow ;
    }
}


int n , m ;
vector < int > gr[ MAXN ] , rv[ MAXN ] ;
int used[ MAXN ] , scc[ MAXN ] ;

stack < int > st ;

void dfs ( int x ) {
    used[ x ] = 1 ;
    for ( auto y : gr[ x ] ) {
        if ( used[ y ] == 0 ) {
            dfs ( y ) ;
        }
    }
    st.push ( x ) ;
}

void rev_dfs ( int x , int id ) {
    scc[ x ] = id ;
    for ( auto y : rv[ x ] ) {
        if ( scc[ y ] == 0 ) {
            rev_dfs ( y , id ) ;
        }
    }
}

set < int > s[ MAXN ] ;

int prv[ MAXN ] , rnk[ MAXN ] ;

int get ( int x ) {
    if ( prv[ x ] == -1 ) { return x ; }
    int y = get ( prv[ x ] ) ;
    prv[ x ] = y ;
    return y ;
}

void unite ( int x , int y ) {
    int k1 = get ( x ) , k2 = get ( y ) ;
    if ( k1 == k2 ) { return ; }
    if ( rnk[ k1 ] >= rnk[ k2 ] ) {
        rnk[ k1 ] += ( rnk[ k1 ] == rnk[ k2 ] ) ;
        prv[ k2 ] = k1 ;
    }
    else {
        prv[ k1 ] = k2 ;
    }
}

map < int , int > col ;

void solve ( ) {
    cin >> n >> m ;
    for ( int i = 1 , x , y ; i <= m ; ++ i ) {
        cin >> x >> y ;
        gr[ x ].push_back ( y ) ;
        rv[ y ].push_back ( x ) ;
    }
    for ( int i = 1 ; i <= n ; ++ i ) {
        if ( used[ i ] == 0 ) {
            dfs ( i ) ;
        }
    }
    int tp = 0 ;
    while ( st.empty ( ) == false ) {
        int x = st.top ( ) ; st.pop ( ) ;
        if ( scc[ x ] > 0 ) { continue ; }
        rev_dfs ( x , ++ tp ) ;
    }
    for ( int i = 1 ; i <= n ; ++ i ) {
        for ( auto j : gr[ i ] ) {
            if ( scc[ i ] != scc[ j ] && s[ scc[ i ] ].find ( scc[ j ] ) == s[ scc[ i ] ].end ( ) ) {
                s[ scc[ i ] ].insert ( scc[ j ] ) ;
            }
        }
    }
    flow :: n = flow :: sink = 2 * tp + 2 ;
    flow :: source = 2 * tp + 1 ;
    for ( int i = 1 ; i <= tp ; ++ i ) {
        flow :: add_edge ( flow :: source , i , 1 ) ;
        flow :: add_edge ( tp + i , flow :: sink , 1 ) ;
        for ( auto j : s[ i ] ) {
            flow :: add_edge ( i , j , inf ) ;
            flow :: add_edge ( i , tp + j , 1 ) ;
        }
    }
    ll ans = flow :: maxflow ( ) ;
    // cout << tp - ans << "\n" ;
    for ( int i = 1 ; i <= tp ; ++ i ) {
        prv[ i ] = -1 , rnk[ i ] = 0 ;
    }
    for ( int i = 1 ; i <= tp ; ++ i ) { 
        for ( auto e : ( flow :: v[ i ] ) ) {
            if ( e.flow > 0 && ( tp < e.to && e.to <= 2 * tp ) ) {
                unite ( i , e.to - tp ) ;
            }
        }
    }
    int mxcol = 0 ;
    for ( int i = 1 ; i <= tp ; ++ i ) {
        int root = get ( i ) ;
        if ( col[ root ] == 0 ) {
            col[ root ] = ++ mxcol ;
        }
    }
    for ( int i = 1 ; i <= n ; ++ i ) {
        cout << col[ get ( scc[ i ] ) ] << " " ;
    }
    cout << "\n" ;
}

int main ( ) {
    ios_base :: sync_with_stdio ( false ) ;
    cin.tie ( NULL ) ;
    int t = 1 ; // cin >> t ; 
    while ( t -- ) { solve ( ) ; }
    return 0 ;
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 5156kb

input:

5 5
1 4
2 3
1 3
2 5
5 1

output:

1 1 1 2 1 

result:

ok AC

Test #2:

score: 0
Accepted
time: 1ms
memory: 5276kb

input:

5 7
1 2
2 1
4 3
5 1
5 4
4 1
4 5

output:

2 2 1 1 1 

result:

ok AC

Test #3:

score: 0
Accepted
time: 2ms
memory: 5136kb

input:

8 6
6 1
3 4
3 6
2 3
4 1
6 4

output:

4 4 4 4 3 4 2 1 

result:

ok AC

Test #4:

score: -100
Wrong Answer
time: 513ms
memory: 7552kb

input:

7000 6999
4365 4296
2980 3141
6820 4995
4781 24
2416 5844
2940 2675
3293 2163
3853 5356
262 6706
1985 1497
5241 3803
353 1624
5838 4708
5452 3019
2029 6161
3849 4219
1095 1453
4268 4567
1184 1857
2911 3977
1662 2751
6353 6496
2002 6628
1407 4623
425 1331
4445 4277
1259 3165
4994 1044
2756 5788
5496 ...

output:

1750 153 153 153 1383 1749 1748 153 153 153 1342 373 1747 157 153 1746 153 1745 153 153 153 153 135 153 153 1744 1743 996 153 1742 153 153 1741 1740 153 153 153 1739 111 1738 153 153 1737 153 1736 153 1735 1060 1734 1733 153 1732 153 355 153 153 850 1731 153 1730 153 564 1484 1205 153 1729 57 554 15...

result:

wrong answer 10 and 3 are not connected