QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#99464 | #6309. Aqre | rgnerdplayer# | WA | 29ms | 3476kb | C++20 | 5.7kb | 2023-04-22 17:07:18 | 2023-04-22 17:07:20 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
// #include <ext/pb_ds/priority_queue.hpp>
// #include <ext/pb_ds/assoc_container.hpp>
// using namespace __gnu_pbds;
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update>
/* ordered_set notes:
.order_of_key(k): Number of items strictly smaller than k
.find_by_order(k): k-th element in a set
*/
#define X first
#define Y second
template <typename A, typename B> istream& operator >> (istream& o, pair<A, B> &a) {
return o >> a.X >> a.Y;
}
template <typename A, typename B> ostream& operator << (ostream& o, pair<A, B> a) {
return o << '(' << a.X << ", " << a.Y << ')';
}
#ifdef cychien
#define DE(...) do {\
fprintf(stderr, "%s - %d : (%s) = ", __PRETTY_FUNCTION__, __LINE__, #__VA_ARGS__);\
_DO(__VA_ARGS__);\
}while(0)
template<typename I> void _DO(I&&x) {cerr << x << '\n';}
template<typename I, typename ...T> void _DO(I&&x,T&&...tail) {cerr << x << ", "; _DO(tail...);}
#define IOS
#define debug(v) {cerr << #v << " = ["; for(auto it = (v).begin(); it != (v).end(); it++){cerr << *it; if (next(it) != (v).end()) cerr << ", "; } cerr << "]\n";}
#else
#define DE(...)
#define debug(v)
#define IOS ios_base::sync_with_stdio(0);cin.tie(0)
#endif
#define W(v) {for(auto it = (v).begin(); it != (v).end(); it++)cout << *it << " \n"[next(it) == (v).end()];}
#define pb emplace_back
#define mp make_pair
#define rsz resize
#define SZ(x) (ll)x.size()
#define AI(x) (x).begin(),(x).end()
#define SORT(x) sort(AI(x))
template<class T> bool chmin(T &a, T b) { return b < a && (a = b, true); }
template<class T> bool chmax(T &a, T b) { return a < b && (a = b, true); }
typedef long long int ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vll;
const int NF = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const ll MOD = 1e9 + 7;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int Rand(){
return uniform_int_distribution<int>(INT_MIN, INT_MAX)(rng);
}
/*
#include <atcoder/all>
using namespace atcoder;
*/
/* LazySegtree
// Example for range linear transfromation & range sum
// Monoid Property: op(F(a), F(b)) == F(op(a, b))
// Declaration: lazy_segtree<S, op, e, F, mapping, composition, id> seg(n);
struct S { // Node
mint sum;
int len;
};
S op(S x, S y){ // pull
return S{x.sum + y.sum, x.len + y.len};
}
S e(){ // e s.t. op(x, e) == x
return S{0, 1};
}
struct F {
mint a, b;
};
S mapping(F t, S x){ // push
return S{t.a * x.sum + t.b * x.len, x.len};
}
F composition(F f, F g){ // f o g
return F{f.a * g.a, f.a * g.b + f.b};
}
F id() { // id s.t. composition(F, id) == F
return F{1, 0};
}
*/
void solve(){
int n, m; cin >> n >> m;
string ans;
if (n <= 3 && m <= 3){
for (int i = 0; i < n; i++){
for (int j = 0; j < m; j++){
ans += '1';
}
ans += '\n';
}
}
else if (n == 1){
for (int j = 0; j < m; j++){
ans += "01"[j < 3];
}
ans += '\n';
}
else if (m == 1){
for (int i = 0; i < n; i++){
ans += "01"[i < 3];
ans += '\n';
}
}
else {
vector<string> pat = {"1110", "1011", "1101", "0111"};
function<bool(int, int)> valid = [&](int x, int y){
return x >= 0 && x < n && y >= 0 && y < m;
};
function<bool(vector<vector<char>>&)> connected = [&](vector<vector<char>>& v){
int tot = 0;
for (int i = 0; i < n; i++)
for (int j = 0; j < m; j++)
tot += (v[i][j] == '1');
vector<pii> d = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
for (int i = 0; i < n; i++){
for (int j = 0; j < m; j++){
if (v[i][j] == '1'){
vector<vector<bool>> vis(n, vector<bool>(m));
int cnt = 0;
queue<pii> q;
q.push(mp(i, j));
vis[i][j] = 1;
while (!q.empty()){
++cnt;
auto [x, y] = q.front(); q.pop();
for (int b = 0; b < 4; b++){
auto [dx, dy] = d[b];
if (valid(x + dx, y + dy) && !vis[x + dx][y + dy] && v[x + dx][y + dy] == '1'){
q.push(mp(x + dx, y + dy));
vis[x + dx][y + dy] = 1;
}
}
}
return cnt == tot;
}
}
}
return true;
};
for (int s = 0; s < 4; s++){
for (int h = 0; h < 4; h++){
string tmp;
vector<vector<char>> v(n, vector<char>(m));
for (int i = 0; i < n; i++){
for (int j = 0; j < m; j++){
tmp += pat[(i + s) % 4][(j + h) % 4];
v[i][j] = pat[(i + s) % 4][(j + h) % 4];
}
tmp += '\n';
}
if (connected(v) && count(AI(tmp), '1') > count(AI(ans), '1')){
ans = tmp;
}
}
}
}
cout << count(AI(ans), '1') << '\n' << ans;
}
int main() {
IOS;
int T; cin >> T;
while (T--) solve();
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 2ms
memory: 3412kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1110 1011 1101 18 11101110 10111011 11011101
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 29ms
memory: 3476kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 6 111 111 6 1110 1011 8 11101 10111 9 111011 101110 11 1110111 1011101 12 11101110 10111011 14 111011101 101110111 15 1110111011 1011101110 17 11101110111 10111011101 18 111011101110 101110111011 20 1110111011101 1011101110111 21 11101110111011 10111011101110 23 111011101110111 1011101110111...
result:
wrong answer ans finds a larger answer (test case 25)