QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#97615#6309. AqreayerszWA 2ms3408kbC++202.2kb2023-04-17 15:31:232023-04-17 15:31:25

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-17 15:31:25]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3408kb
  • [2023-04-17 15:31:23]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

int solve();

int main() {
    int t;
    cin >> t;
    while (t--) {
        solve();
    }
    return 0;
}

const int N = 1005;

int ans[N][N];
int n, m;
int cnt;

const int d[5] = {0, 4, 2, 3, 1};

void print() {
    cnt = 0;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            cnt += ans[i][j];
        }
    }
    cout << cnt << "\n";
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            cout << ans[i][j];
        }
        cout << "\n";
    }
}

int solve() {
    cin >> n >> m;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            ans[i][j] = 0;
        }
    }
    if (n <= 3 && m <= 3) {
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                ans[i][j] = 1;
            }
        }
        print();
        return 0;
    }
    if ((n == 3 && m == 4) || (n == 4 && m == 3)) {
        for (int i = 1; i <= 3; i++) {
            for (int j = 1; j <= 3; j++) {
                ans[i][j] = 1;
            }
        }
        print();
        return 0;
    }
    if (n <= 2) {
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                if (j % 2 == 1) {
                    ans[i][j] = 1;
                } else {
                    if (((j / 2) % 2 == 0 && i == 1) ||
                        ((j / 2) % 2 == 1 && i == n)) {
                        ans[i][j] = 1;
                    }
                }
            }
        }
        print();
        return 0;
    }
    if (m <= 3) {
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                if (((i / 2) % 2 == 0 && j == 1) ||
                    ((i / 2) % 2 == 1 && j == m)) {
                    ans[i][j] = 1;
                }
            }
        }
        print();
        return 0;
    }
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            int x = (i - 1) % 4 + 1, y = (j - 1) % 4 + 1;
            if (d[x] != y) {
                ans[i][j] = 1;
            }
        }
    }
    print();
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 2ms
memory: 3288kb

input:

3
2 2
3 4
3 8

output:

4
11
11
9
1110
1110
1110
18
11101110
10111011
11011101

result:

ok ok (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3408kb

input:

361
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 12
2 13
2 14
2 15
2 16
2 17
2 18
2 19
2 20
3 2
3 3
3 4
3 5
3 6
3 7
3 8
3 9
3 10
3 11
3 12
3 13
3 14
3 15
3 16
3 17
3 18
3 19
3 20
4 2
4 3
4 4
4 5
4 6
4 7
4 8
4 9
4 10
4 11
4 12
4 13
4 14
4 15
4 16
4 17
4 18
4 19
4 20
5 2
5 3
5 4
5 5
5 6
5 7
5 8
5 9
5 1...

output:

4
11
11
6
111
111
6
1011
1110
8
10111
11101
9
101110
111011
11
1011101
1110111
12
10111011
11101110
14
101110111
111011101
15
1011101110
1110111011
17
10111011101
11101110111
18
101110111011
111011101110
20
1011101110111
1110111011101
21
10111011101110
11101110111011
23
101110111011101
1110111011101...

result:

wrong answer ans finds a larger answer (test case 25)