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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#95571 | #5470. Hasty Santa Claus | PetroTarnavskyi# | TL | 0ms | 0kb | C++17 | 2.3kb | 2023-04-10 15:50:22 | 2023-04-10 15:50:27 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define SZ(a) (int)a.size()
#define ALL(a) a.begin(), a.end()
#define FOR(i, a, b) for (int i = (a); i<(b); ++i)
#define RFOR(i, b, a) for (int i = (b)-1; i>=(a); --i)
#define MP make_pair
#define PB push_back
#define F first
#define S second
typedef long long LL;
typedef pair<int, int> PII;
typedef vector<int> VI;
const int N = 1047;
vector<string> g;
int dis[N][N];
PII from[N][N];
int h, w;
bool super[N][N];
PII ls[N][N];
PII dir[4] = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}};
bool ok(int x, int y)
{
return 0 <= x && x < 2 * h + 1 && 0 <= y && y < 2 * w + 1;
}
void dfs(int x, int y, int d, int px = -1, int py = -1)
{
from[x][y] = {px, py};
dis[x][y] = d;
for (int i = 0; i < 4; i++)
{
int nx = x + dir[i].first * 2;
int ny = y + dir[i].second * 2;
if (nx == px && ny == py) continue;
if (ok(nx, ny) && g[x + dir[i].first][y + dir[i].second] == '.')
dfs(nx, ny, d + 1, x, y);
}
}
void sup()
{
int x = 2 * h;
int y = 2 * w;
while (x != -1)
{
super[x][y] = 1;
int x2 = from[x][y].first;
y = from[x][y].second;
x = x2;
}
}
void dfs2(int x, int y, int sx = -1, int sy = -1, int px = -1, int py = -1)
{
if (super[x][y]) sx = x, sy = y;
ls[x][y] = {sx, sy};
for (int i = 0; i < 4; i++)
{
int nx = x + dir[i].first * 2;
int ny = y + dir[i].second * 2;
if (nx == px && ny == py) continue;
if (ok(nx, ny) && g[x + dir[i].first][y + dir[i].second] == '.')
dfs2(nx, ny, sx, sy, x, y);
}
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> h >> w;
g.resize(2 * h + 1);
FOR(i, 0, 2 * h + 1)
{
cin >> g[i];
}
dfs(1, 1, 0);
sup();
dfs2(1, 1);
int ans = dis[2 * h][2 * w];
FOR(x, 0, h)
{
FOR(y, 0, w)
{
FOR(k, 0, 4)
{
int nx = x + dir[k].first * 2;
int ny = y + dir[k].second * 2;
if (ok(nx, ny) && g[x + dir[k].first][y + dir[k].second] != '.')
{
PII s1 = ls[x][y];
PII s2 = ls[nx][ny];
if (dis[s1.first][s1.second] >= dis[s2.first][s2.second])
continue;
int d1 = dis[x][y] + 1;
int d2 = dis[nx][ny] - dis[s2.first][s2.second];
int d3 = dis[2 * h][2 * w] - dis[s2.first][s2.second] + 1;
ans = max(ans, d1 + d2 + d3);
}
}
}
}
cout << ans << '\n';
return 0;
}
详细
Test #1:
score: 0
Time Limit Exceeded
input:
5 1 23 25 23 27 24 25 25 25 25 26