QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#94952 | #6128. Flippy Sequence | 2000805113# | AC ✓ | 53ms | 5884kb | C++17 | 969b | 2023-04-08 14:15:02 | 2023-04-08 14:15:03 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
using pll = pair<ll,ll>;
int T;
ll n;
string s1, s2;
vector<pll> ve;
void solve() {
ve.clear();
cin >> n;
cin >> s1 >> s2;
for(int i = 0; i < n; i++){
if(s1[i] != s2[i]){
int j = i;
while(j < n && s1[j] != s2[j]){
j++;
}
ve.push_back({i, j});
i = j;
}
}
if(ve.size() == 0){
cout << n * (n + 1) / 2 << '\n';
}else if(ve.size() == 1){
auto [l, r] = ve[0];
cout << 2 * ((l) + (n - 1 - r) + (r - l)) << '\n';
}else if(ve.size() == 2){
auto [l1, r1] = ve[0];
auto [l2, r2] = ve[1];
cout << 6 << '\n';
}else{
cout << 0 << '\n';
}
}
int main() {
ios :: sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> T;
while(T--) solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 2ms
memory: 3512kb
input:
3 1 1 0 2 00 11 5 01010 00111
output:
0 2 6
result:
ok 3 number(s): "0 2 6"
Test #2:
score: 0
Accepted
time: 53ms
memory: 5884kb
input:
126648 1 0 0 1 1 0 2 01 01 2 01 11 2 10 11 2 11 00 3 011 011 3 010 110 3 011 001 3 111 001 3 001 000 3 101 000 3 011 000 3 111 000 4 1111 1111 4 1110 0110 4 0010 0110 4 1011 0111 4 1001 1011 4 0100 1110 4 0000 0110 4 0111 1001 4 1001 1000 4 1011 0010 4 0001 0100 4 1000 0101 4 0100 0111 4 1101 0110 4...
output:
1 0 3 2 2 2 6 4 4 4 4 6 4 4 10 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 15 8 8 8 8 6 8 8 8 6 6 6 8 6 8 8 8 6 6 6 6 0 6 6 8 6 6 6 8 6 8 8 21 10 10 10 10 6 10 10 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 6 0 0 0 6 0 6 6 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 28 12 12 12 12 6 12 12 1...
result:
ok 126648 numbers