QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#94926 | #6128. Flippy Sequence | George_Plover# | AC ✓ | 128ms | 5472kb | C++14 | 1.0kb | 2023-04-08 12:38:15 | 2023-04-08 12:38:17 |
Judging History
answer
#include <map>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define MAXN 1100000
using namespace std;
int T,n;
map<int,int> S;
char s[MAXN],t[MAXN];
int main(){
scanf("%d",&T);
while(T--){
scanf("%d",&n);
scanf("%s%s",s,t);
S.clear();
int l,j=0;
for(int i=0;i<n;i++){
if(s[i]!=t[i]){
if(!j){
j=1;
l=i;
}
}
else{
if(j){
S[l]=i-1;
j=0;
}
}
if(S.size()==3)break;
}
if(j){
S[l]=n-1;
}
if(S.size()>=3){
puts("0");
}
else if(S.size()==0){
printf("%lld\n",1ll*n*(n+1)/2);
}
else if(S.size()==1){
printf("%lld\n",2ll*(n-1));
}
else{
printf("6\n");
}
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3596kb
input:
3 1 1 0 2 00 11 5 01010 00111
output:
0 2 6
result:
ok 3 number(s): "0 2 6"
Test #2:
score: 0
Accepted
time: 128ms
memory: 5472kb
input:
126648 1 0 0 1 1 0 2 01 01 2 01 11 2 10 11 2 11 00 3 011 011 3 010 110 3 011 001 3 111 001 3 001 000 3 101 000 3 011 000 3 111 000 4 1111 1111 4 1110 0110 4 0010 0110 4 1011 0111 4 1001 1011 4 0100 1110 4 0000 0110 4 0111 1001 4 1001 1000 4 1011 0010 4 0001 0100 4 1000 0101 4 0100 0111 4 1101 0110 4...
output:
1 0 3 2 2 2 6 4 4 4 4 6 4 4 10 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 15 8 8 8 8 6 8 8 8 6 6 6 8 6 8 8 8 6 6 6 6 0 6 6 8 6 6 6 8 6 8 8 21 10 10 10 10 6 10 10 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 6 0 0 0 6 0 6 6 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 28 12 12 12 12 6 12 12 1...
result:
ok 126648 numbers