#include <bits/stdc++.h>
using namespace std;

const int N = 2010;
const long long MOD = 2147483647;

using coord = long double;
coord EPS = 1e-8;
namespace basic {
    #define X real()
    #define Y imag()
    using point = complex<coord>;
    int signal(coord x) {
        return (x > EPS) - (x < -EPS);
    }
    point rotate90(point p) {
        return p * point(0, 1);
    }
    coord dot(point a, point b) {
        return (conj(a) * b).X;
    }
    coord cross(point a, point b) {
        return (conj(a) * b).Y;
    }

    struct line {
        point p;
        coord c;
        line(point a, point b): p(rotate90(b - a)), c(dot(p, a)) {}
    };
    bool intersects(line l1, line l2) {
        return signal(cross(l1.p, l2.p));
    }
    point intersection(line l1, line l2) {
        if (!intersects(l1, l2)) throw 1;
        point p(cross({l1.c, l1.p.Y}, {l2.c, l2.p.Y}), cross({l1.p.X, l1.c}, {l2.p.X, l2.c}));
        return p / cross(l1.p, l2.p);
    }

    struct circle {
        point c;
        coord r;
    };
    bool contains(circle c, point p) {
        return abs(p - c.c) <= c.r + EPS;
    }
    circle create(point u, point v, point w) {
        point mv = (u + v) / 2.0L;
        point mw = (u + w) / 2.0L;
        line s(mv, mv + rotate90(v - u));
        line t(mw, mw + rotate90(w - u));
        point c = intersection(s, t);
        coord r = abs(c - u);
        return {c, r};
    }
};
using namespace basic;

pair<point, long long> next(long long x) {
    long long y = (233811181ll * x + 1) % MOD;
    point p = {(long double)x, (long double)y};
    return {p, (233811181ll * y + 1) % MOD};
}

long double dp[N][N], cost[N][N];
vector<int> pos[N];

void calc(vector<point> &p) {
    int n = p.size();
    for (int l = 0; l < n; l++) {
        int i, j, k;
        circle c = {p[l], 0};
        for (i = l; i < n; i++) {
            if (contains(c, p[i])) {
                cost[l][i] = c.r;
                continue;
            };
            for (c = {p[i], 0}, j = l; j < i; j++) {
                if (contains(c, p[j])) continue;
                for (c = {(p[i] + p[j]) / 2.0L, abs(p[i] - p[j]) / 2}, k = l; k < j; k++) {
                    if (contains(c, p[k])) continue;
                    c = create(p[i], p[j], p[k]);
                }
            }
            cost[l][i] = c.r;
        }
    }
}

int main() {
    long long n, K, x; scanf("%lld %lld %lld", &n, &K, &x);
    vector<point> p(n);
    for (int i = 0; i < n; i++) {
        auto pp = next(x);
        x = pp.second;
        p[i] = pp.first;
    }
    calc(p);
    for (int i = 0; i < n; i++) {
        dp[i][1] = cost[0][i];
    }
    for (int i = 0; i < n; i++) {
        long double last = cost[0][i];
        for (int j = 1; j <= i; j++) {
            long double nc = cost[j][i];
            if (nc + EPS < last) {
                last = nc;
                pos[i].push_back(j);
            }
        }
    }
    for (int k = 2; k <= K; k++) {
        for (int i = 0; i < n; i++) {
            dp[i][k] = cost[0][i];
            for (int j = 0; j < pos[i].size(); j++) {
                int pp = pos[i][j];
                dp[i][k] = min(dp[i][k], dp[pp - 1][k - 1] + cost[pp][i]);
            }
        }
    }
    printf("%.10lf\n", (double)dp[n - 1][K]);
}