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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#94858 | #5661. Multi-Ladders | pedroteosousa# | AC ✓ | 2ms | 3752kb | C++14 | 1.2kb | 2023-04-08 00:41:32 | 2023-04-08 00:41:34 |
Judging History
answer
#include <bits/stdc++.h>
#define mod 1'000'000'007
#define ll long long
using namespace std;
int v[100100];
struct mat {
ll M[2][2];
mat operator*(mat a){
mat ret;
for(int i=0;i<2;i++)
for(int j=0;j<2;j++){
ret.M[i][j] = 0;
for(int k=0;k<2;k++)
ret.M[i][j] += M[i][k] * a.M[k][j];
ret.M[i][j] %= mod;
}
return ret;
}
};
mat id;
mat exp(mat A,ll k){
if(k == 0) return id;
mat aux = exp(A,k/2);
aux = aux * aux;
if(k%2 == 1)
aux = aux * A;
return aux;
}
ll exp(ll a,ll b){
if(b == 0) return 1;
ll k = exp(a,b/2);
k = (k*k) % mod;
if(b%2 == 1)
k = (k*a) % mod;
return k;
}
main(){
int nt;
scanf("%d",&nt);
while(nt--){
ll n,k,lam;
scanf("%lld%lld%lld",&n,&k,&lam);
id.M[0][0] = id.M[1][1] = 1;
mat A;
A.M[0][0] = 0;
A.M[1][0] = 1;
A.M[0][1] = lam-1;
A.M[1][1] = lam-2;
A = exp(A,k-1);
ll D = A.M[0][1];
D *= lam;
D %= mod;
ll line = ( (lam-1)*(lam-1) - (lam-2)) % mod;
ll qtd_lines = ( k * (n-1)) % (mod-1);
ll borda = exp(line,qtd_lines);
ll ans = (D * borda) % mod;
printf("%lld\n",ans);
}
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3752kb
input:
1 2 3 3
output:
162
result:
ok single line: '162'
Test #2:
score: 0
Accepted
time: 2ms
memory: 3508kb
input:
20 2 3 3 1 3 3 10 3 0 10 3 2 1 21 2 1 22 0 2000 15000 2000 12000 30000 200000 1000000000 3 3 2 1000000000 3 2 3 100000000 1000000000 1000000000 10 1000000000 3 100000000 2 1000000000 100000000 1 1000000000 10 1 1000000000 100000000 1 1000 100000000 1000000000 1000000000 0 1000000000 1000000000 1 100...
output:
162 6 0 0 0 0 349400141 243010659 52489881 53690844 176686901 218103365 558243892 991895211 693053429 883715672 80402569 0 0 311752813
result:
ok 20 lines