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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#94852#5668. Cell Nuclei Detectionpedroteosousa#AC ✓4837ms192480kbC++203.2kb2023-04-08 00:08:492023-04-08 00:08:51

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-08 00:08:51]
  • 评测
  • 测评结果:AC
  • 用时:4837ms
  • 内存:192480kb
  • [2023-04-08 00:08:49]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

const int M = 2010;
const int N = 112345;

struct rect {
    int x1, y1, x2, y2, index;
    int a() {
        if (x2 <= x1 || y2 <= y1) return 0;
        return (x2 - x1) * (y2 - y1);
    }
    rect inter(rect o) {
        int xx1 = max(o.x1, x1);
        int yy1 = max(o.y1, y1);
        int xx2 = min(o.x2, x2);
        int yy2 = min(o.y2, y2);
        return {xx1, yy1, xx2, yy2};
    }
};

vector<rect> g[M][M];

using num = long long;
const num INF = 1e12;

struct dinic {
    struct edge {
        int form, to;
        num c, f;
    };
    vector<edge> edges;
    vector<int> adj[N];

    void add_edge(int i, int j, num c) {
        edges.push_back({i, j, c, 0}); adj[i].push_back(edges.size() - 1);
        edges.push_back({j, i, 0, 0}); adj[j].push_back(edges.size() - 1);
    }

    int turn, seen[N], dist[N], st[N];
    bool bfs(int s, int t) {
        seen[t] = ++turn;
        dist[t] = 0;
        queue<int> q({t});
        while (q.size()) {
            int u = q.front(); q.pop();
            st[u] = 0;
            for (auto e: adj[u]) {
                int v = edges[e].to;
                if (seen[v] != turn && edges[e ^ 1].c != edges[e ^ 1].f) {
                    seen[v] = turn;
                    dist[v] = dist[u] + 1;
                    q.push(v);
                }
            }
        }
        return seen[s] == turn;
    }
    num dfs(int s, int t, num f) {
        if (s == t || f == 0)
            return f;
        for (int &i = st[s]; i < adj[s].size(); i++) {
            int e = adj[s][i], v = edges[e].to;
            if (seen[v] == turn && dist[v] + 1 == dist[s] && edges[e].c > edges[e].f) {
                if (num nf = dfs(v, t, min(f, edges[e].c - edges[e].f))) {
                    edges[e].f += nf;
                    edges[e ^ 1].f -= nf;
                    return nf;
                }
            }
        }
        return 0;
    }
    num max_flow(int s, int t) {
        num resp = 0;
        while (bfs(s, t)) {
            while (num val = dfs(s, t, INF))
                resp += val;
        }
        return resp;
    }
};

void solve() {
    dinic d;
    for (int i = 0; i < M; i++) {
        for (int j = 0; j < M; j++) {
            g[i][j].clear();
        }
    }
    int m, n; scanf("%d %d", &m, &n);
    for (int i = 0; i < m; i++) {
        int x1, y1, x2, y2;
        scanf("%d %d %d %d", &x1, &y1, &x2, &y2);
        g[x1][y1].push_back({x1, y1, x2, y2, i});
        d.add_edge(i, n + m + 1, 1);
    }
    for (int i = 0; i < n; i++) {
        int x1, y1, x2, y2;
        scanf("%d %d %d %d", &x1, &y1, &x2, &y2);
        rect r = {x1, y1, x2, y2, i};
        d.add_edge(n + m, i + m, 1);
        for (int x = x1 - 4; x <= x1 + 4; x++) {
            if (x < 0) continue;
            for (int y = y1 - 4; y <= y1 + 4; y++) {
                if (y < 0) continue;
                for (auto gg: g[x][y]) {
                    rect ii = r.inter(gg);
                    if (2 * ii.a() >= gg.a()) {
                        d.add_edge(i + m, gg.index, 1);
                    }
                }
            }
        }
    }
    num x = d.max_flow(n + m, n + m + 1);
    printf("%lld\n", x);
}

int main() {
    int t; scanf("%d", &t);
    while (t--)
        solve();
}

详细

Test #1:

score: 100
Accepted
time: 35ms
memory: 102276kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 42ms
memory: 102212kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #3:

score: 0
Accepted
time: 3243ms
memory: 181316kb

input:

5
50000 50000
0 0 4 4
4 0 8 4
8 0 12 4
12 0 16 4
16 0 20 4
20 0 24 4
24 0 28 4
28 0 32 4
32 0 36 4
36 0 40 4
40 0 44 4
44 0 48 4
48 0 52 4
52 0 56 4
56 0 60 4
60 0 64 4
64 0 68 4
68 0 72 4
72 0 76 4
76 0 80 4
80 0 84 4
84 0 88 4
88 0 92 4
92 0 96 4
96 0 100 4
100 0 104 4
104 0 108 4
108 0 112 4
112 ...

output:

50000
50000
0
50000
3150

result:

ok 5 lines

Test #4:

score: 0
Accepted
time: 432ms
memory: 163344kb

input:

5
50000 50000
0 0 1 1
1 0 2 1
2 0 3 1
3 0 4 1
4 0 5 1
5 0 6 1
6 0 7 1
7 0 8 1
8 0 9 1
9 0 10 1
10 0 11 1
11 0 12 1
12 0 13 1
13 0 14 1
14 0 15 1
15 0 16 1
16 0 17 1
17 0 18 1
18 0 19 1
19 0 20 1
20 0 21 1
21 0 22 1
22 0 23 1
23 0 24 1
24 0 25 1
25 0 26 1
26 0 27 1
27 0 28 1
28 0 29 1
29 0 30 1
30 0 ...

output:

50000
25050
12500
16000
8000

result:

ok 5 lines

Test #5:

score: 0
Accepted
time: 397ms
memory: 118288kb

input:

5
50000 50000
0 0 2 4
4 0 7 1
8 0 10 1
12 0 15 3
16 0 19 1
20 0 22 2
24 0 26 4
28 0 30 4
32 0 36 3
36 0 40 1
40 0 44 1
44 0 47 2
48 0 49 3
52 0 54 1
56 0 59 4
60 0 64 3
64 0 68 3
68 0 70 1
72 0 76 4
76 0 80 3
80 0 84 4
84 0 87 2
88 0 90 1
92 0 94 4
96 0 98 1
100 0 104 1
104 0 107 2
108 0 110 4
112 0...

output:

10594
10779
10618
10381
10779

result:

ok 5 lines

Test #6:

score: 0
Accepted
time: 4837ms
memory: 192480kb

input:

5
50000 50000
0 0 4 4
1 0 5 4
2 0 6 4
3 0 7 4
4 0 8 4
5 0 9 4
6 0 10 4
7 0 11 4
8 0 12 4
9 0 13 4
10 0 14 4
11 0 15 4
12 0 16 4
13 0 17 4
14 0 18 4
15 0 19 4
16 0 20 4
17 0 21 4
18 0 22 4
19 0 23 4
20 0 24 4
21 0 25 4
22 0 26 4
23 0 27 4
24 0 28 4
25 0 29 4
26 0 30 4
27 0 31 4
28 0 32 4
29 0 33 4
30...

output:

50000
50000
50000
50000
49600

result:

ok 5 lines

Test #7:

score: 0
Accepted
time: 21ms
memory: 102268kb

input:

1
4 4
1 1 3 3
2 1 4 3
1 2 3 4
2 2 4 4
2 1 4 3
3 2 5 4
1 2 3 4
2 3 4 5

output:

3

result:

ok single line: '3'