QOJ.ac
QOJ
The 2nd Universal Cup Finals is coming! Check out our event page, schedule, and competition rules!
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#94103 | #6128. Flippy Sequence | installb# | AC ✓ | 94ms | 9468kb | C++14 | 573b | 2023-04-05 13:25:35 | 2023-04-05 13:25:39 |
Judging History
answer
#include <bits/stdc++.h>
#define rep(i,l,r) for(int i=(l);i<=(r);++i)
#define per(i,r,l) for(int i=(r);i>=(l);--i)
using namespace std;
const int N=1e6+10;
int T,n,f[N];char s[N],t[N];
int main(){
scanf("%d",&T);
while(T--){
scanf("%d%s%s",&n,s+1,t+1);f[n+1]=0;
rep(i,1,n) f[i]=s[i]!=t[i];int cnt=0;
rep(i,1,n) if(f[i]==1&&f[i]!=f[i-1]) ++cnt;
if(cnt==0) printf("%lld\n",1ll*n*(n+1)/2);
else if(cnt==1) printf("%d\n",2*(n-1));
else if(cnt==2) puts("6");
else puts("0");
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 2ms
memory: 3632kb
input:
3 1 1 0 2 00 11 5 01010 00111
output:
0 2 6
result:
ok 3 number(s): "0 2 6"
Test #2:
score: 0
Accepted
time: 94ms
memory: 9468kb
input:
126648 1 0 0 1 1 0 2 01 01 2 01 11 2 10 11 2 11 00 3 011 011 3 010 110 3 011 001 3 111 001 3 001 000 3 101 000 3 011 000 3 111 000 4 1111 1111 4 1110 0110 4 0010 0110 4 1011 0111 4 1001 1011 4 0100 1110 4 0000 0110 4 0111 1001 4 1001 1000 4 1011 0010 4 0001 0100 4 1000 0101 4 0100 0111 4 1101 0110 4...
output:
1 0 3 2 2 2 6 4 4 4 4 6 4 4 10 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 15 8 8 8 8 6 8 8 8 6 6 6 8 6 8 8 8 6 6 6 6 0 6 6 8 6 6 6 8 6 8 8 21 10 10 10 10 6 10 10 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 6 0 0 0 6 0 6 6 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 28 12 12 12 12 6 12 12 1...
result:
ok 126648 numbers