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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#93827#5065. Beautiful StringsnukeWA 188ms101176kbC++204.2kb2023-04-03 02:40:252023-04-03 02:40:28

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-04-03 02:40:28]
  • 评测
  • 测评结果:WA
  • 用时:188ms
  • 内存:101176kb
  • [2023-04-03 02:40:25]
  • 提交

answer

#include <bits/stdc++.h>
#define rep(i,n) for(int i = 0; i < (n); ++i)
#define rep1(i,n) for(int i = 1; i <= (n); ++i)
#define drep(i,n) for(int i = (n)-1; i >= 0; --i)
#define srep(i,s,t) for (int i = s; i < (t); ++i)
#define rng(a) a.begin(),a.end()
#define rrng(a) a.rbegin(),a.rend()
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define pob pop_back
#define sz(x) (int)(x).size()
#define pcnt __builtin_popcountll
#define snuke srand((unsigned)clock()+(unsigned)time(NULL));
#define newline puts("")
using namespace std;
template<typename T> using vc = vector<T>;
template<typename T> using vv = vc<vc<T>>;
template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>;
using uint = unsigned; using ull = unsigned long long;
using vi = vc<int>; using vvi = vv<int>; using vvvi = vv<vi>;
using ll = long long; using vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>;
using P = pair<int,int>; using vp = vc<P>; using vvp = vv<P>;
int geti(){int x;scanf("%d",&x);return x;}
vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}
template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}
template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}
template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}
template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}
template<typename T1,typename T2>void operator--(pair<T1,T2>&a,int){a.fi--;a.se--;}
template<typename T1,typename T2>void operator++(pair<T1,T2>&a,int){a.fi++;a.se++;}
template<typename T>void operator--(vc<T>&a,int){for(T&x:a)x--;}
template<typename T>void operator++(vc<T>&a,int){for(T&x:a)x++;}
template<typename T>void operator+=(vc<T>&a,T b){for(T&x:a)x+=b;}
template<typename T>void operator-=(vc<T>&a,T b){for(T&x:a)x-=b;}
template<typename T>void operator*=(vc<T>&a,T b){for(T&x:a)x*=b;}
template<typename T>void operator/=(vc<T>&a,T b){for(T&x:a)x/=b;}
template<typename T>void operator+=(vc<T>&a,const vc<T>&b){a.insert(a.end(),rng(b));}
template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(y<x){x=y;return true;}else return false;}
template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}
template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
template<typename T>void prepend(vc<T>&a,const T&x){a.insert(a.begin(),x);}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#define dame { puts("-1"); return;}
#define yes { puts("Yes"); return;}
#define no { puts("No"); return;}
#define rtn(x) { cout<<(x)<<endl; return;}
#define yn {puts("Yes");}else{puts("No");}
const int MX = 200005;

// Z algorithm
struct Z {
  vi a;
  Z(){}
  Z(const string& s):a(sz(s)) {
    int n = sz(s); a[0] = n;
    for (int i=1,j=0;i<n;) {
      while (i+j<n && s[j]==s[i+j]) ++j;
      a[i] = j;
      int k = !!j;
      while (i+k<n && k+a[k]<j) a[i+k] = a[k], ++k;
      i += k+!j; j -= k;
    }
  }
  inline int operator[](int i) { return a[i];}
};
//

struct Solver {
  void solve() {
    string S;
    cin>>S;
    int n = sz(S);
    vvi ws(n,vi(n));
    ll ans = 0;
    rep(l,n) {
      string s = S.substr(l);
      int m = sz(s);
      Z z(s);
      vi d(m); int x = 0;
      srep(r,1,m) {
        x++;
        d[min(z[r],r-1)]--;
      }
      int num = 0;
      rep(r,m) {
        x += d[r];
        num += ws[l][r];
        ans += x*num;
        if (z[r] >= r-l) ws[l+r][r] = 1;
      }
    }
    cout<<ans<<endl;
  }
};

int main() {
  // cin.tie(nullptr); ios::sync_with_stdio(false);
  int ts = 1;
  scanf("%d",&ts);
  rep1(ti,ts) {
    Solver solver;
    solver.solve();
  }
  return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3520kb

input:

2
114514
0000000

output:

1
3

result:

ok 2 number(s): "1 3"

Test #2:

score: -100
Wrong Answer
time: 188ms
memory: 101176kb

input:

11
79380
2483905227
37902399703986576270
39991723655814713848046032694137883815354365954917
5541883522667841718787744915558298207485830622522715211018760095628594390563630840464643840093757297
56530485554219245862513973750218715585679416120445975390556326891488719311495909340757506478400624741858999...

output:

0
0
2
12
39
254
1523
1501
13984
24676
153296

result:

wrong answer 3rd numbers differ - expected: '0', found: '2'