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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#92453 | #4380. Travel plan | Tobo | TL | 0ms | 0kb | C++20 | 3.6kb | 2023-03-30 16:57:30 | 2023-03-30 16:57:48 |
Judging History
answer
#include <bits/stdc++.h>
#define N 200005
#define mod 998244353
using i64 = long long;
using namespace std;
int vis[N], pri[N], tot, mu[N];
vector<int> fac[N], num[N];
int n, m, l;
vector<int> adj[N], T[N];
int dfn[N], low[N], dfstot, cnt;
stack<int> sta;
i64 path[N], f[N], g[N];
void tarjan(int cur)
{
dfn[cur] = low[cur] = ++dfstot;
sta.push(cur);
for (int i : adj[cur])
{
if (!dfn[i])
{
tarjan(i);
low[cur] = min(low[cur], low[i]);
if (low[i] == dfn[cur])
{
cnt++;
int node;
do
{
node = sta.top();
sta.pop();
T[cnt].push_back(node);
T[node].push_back(cnt);
} while (node != i);
T[cur].push_back(cnt);
T[cnt].push_back(cur);
}
}
else
low[cur] = min(low[cur], dfn[i]);
}
}
void dfs(int cur, int fa, int fac)
{
for (int i : T[cur])
{
if (i == fa)
continue;
dfs(i, cur, fac);
}
if (cur <= n)
path[cur] = 1;
else
path[cur] = 0;
for (int i : T[cur])
{
if (i == fa)
continue;
if (cur <= n || T[cur].size() > 2)
g[fac] = (g[fac] + (i64)path[cur] * path[i] % mod) % mod;
if (cur > n && T[cur].size() > 2)
path[cur] = (path[cur] + 2 * path[i] % mod) % mod;
else
path[cur] = (path[cur] + path[i]) % mod;
}
}
void solve()
{
cin >> n >> m >> l;
vector<array<int, 3>> e(m);
for (int i = 0; i < m; i++)
{
cin >> e[i][0] >> e[i][1] >> e[i][2];
for (int j : fac[e[i][2]])
num[j].push_back(i);
}
for (int d = 1; d <= l; d++)
{
for (int i : num[d])
{
adj[e[i][0]].push_back(e[i][1]);
adj[e[i][1]].push_back(e[i][0]);
}
cnt = n;
for (int i : num[d])
{
if (!dfn[e[i][0]])
{
tarjan(e[i][0]);
dfs(e[i][0], 0, d);
}
}
dfstot = 0;
for (int i = n + 1; i <= cnt; i++)
T[i].clear();
while (!sta.empty())
sta.pop();
for (int i : num[d])
{
T[e[i][0]].clear();
T[e[i][1]].clear();
adj[e[i][0]].clear();
adj[e[i][1]].clear();
dfn[e[i][0]] = low[e[i][0]] = 0;
dfn[e[i][1]] = low[e[i][1]] = 0;
}
}
for (int i = 1; i <= l; i++)
for (int j = i; j <= l; j += i)
f[i] = (f[i] + (g[j] * mu[j / i] + mod) % mod) % mod;
for (int i = 2; i <= l; i++)
f[i] ^= f[i - 1];
cout << f[l] << '\n';
fill(f + 1, f + l + 1, 0);
fill(g + 1, g + l + 1, 0);
for (int i = 1; i <= l; i++)
num[i].clear();
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
mu[1] = 1;
for (int i = 2; i <= 1e5; i++)
{
if (!vis[i])
pri[++tot] = i, mu[i] = -1;
for (int j = 1; j <= tot && i * pri[j] <= 1e5; j++)
{
vis[i * pri[j]] = 1;
if (i % pri[j] == 0)
break;
mu[i * pri[j]] = -mu[i];
}
}
for (int i = 1; i <= 1e5; i++)
for (int j = i; j <= 1e5; j += i)
fac[j].push_back(i);
int t = 1;
cin >> t;
while (t--)
solve();
}
詳細信息
Test #1:
score: 0
Time Limit Exceeded
input:
405 3 3 6 1 2 6 2 3 4 3 1 5 5 4 10 1 2 10 1 3 1 2 4 8 4 5 9 100000 133392 100000 1 2 38759 1 3 63879 3 4 70473 1 5 79849 1 6 70562 5 7 83128 3 8 89713 4 9 6190 4 10 44171 7 11 99719 5 12 18707 1 13 33509 3 14 96110 11 15 84651 4 16 17844 3 17 64945 5 18 82684 9 19 94007 16 20 54506 11 21 10076 4 22 ...