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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#91975 | #6137. Sub-cycle Graph | sycheng# | AC ✓ | 107ms | 87868kb | C++14 | 5.1kb | 2023-03-30 02:30:35 | 2023-03-30 02:30:36 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using LL = long long;
#define int long long
using poly = vector<LL>;
const int mod = 1e9 + 7;
namespace Conv {
#define ld long double
const int _ = 1 << 19 | 1;
const ld pi = acos(-1);
struct comp {
ld x, y; comp(ld _x = 0, ld _y = 0): x(_x), y(_y){}
friend comp operator +(comp p, comp q) {
return comp(p.x + q.x, p.y + q.y);
}
friend comp operator -(comp p, comp q) {
return comp(p.x - q.x, p.y - q.y);
}
friend comp operator *(comp p, comp q) {
return comp(p.x * q.x - p.y * q.y, p.x * q.y + p.y * q.x);
}
friend comp operator /(comp p, ld q) {
return comp(p.x / q, p.y / q);
}
friend comp operator ~(comp p) {
return comp(p.x, -p.y);
}
}A[_], B[_], C[_], D[_];
int N, M, P;
comp w[_];
int dir[_], need;
void init(int len) {
need = 1; while(need < len) need <<= 1;
for (int i = 1; i < need; ++ i) dir[i] = (dir[i >> 1] >> 1) | (i & 1 ? need >> 1 : 0);
for (int i = 1; i < need; i <<= 1) {
w[i] = comp(1, 0); comp wn(cos(pi / i), sin(pi / i));
for (int j = 1; j < i; j ++ ) {
w[i + j] = w[i + j - 1] * wn;
}
}
}
void DFT(comp *A, int t) {
for (int i = 1; i < need; ++ i) {
if(i < dir[i]) swap(A[i], A[dir[i]]);
}
for (int i = 1; i < need; i <<= 1) {
for (int j = 0; j < need; j += i << 1) {
for (int k = 0; k < i; k ++ ) {
comp x = A[j + k], y = A[i + j + k] * w[i + k];
A[j + k] = x + y, A[i + j + k] = x - y;
}
}
}
if(t == -1) {reverse(A + 1, A + need); for (int i = 0; i < need; i ++ ) A[i] = A[i] / need;}
}
void DFT(comp *A, comp *B) {
static comp P[_], Q[_];
for (int i = 0; i < need; i ++ ) P[i] = A[i] + B[i] * comp(0, 1);
DFT(P, 1);
Q[0] = ~P[0];
for (int i = 1; i < need; ++ i) Q[i] = ~P[need - i];
for (int i = 0; i < need; ++ i) {
A[i] = (P[i] + Q[i]) / 2; B[i] = (P[i] - Q[i]) * comp(0, -0.5);
}
}
void IDFT(comp *A, comp *B){
static comp P[_];
for(int i = 0; i < need; ++i) P[i] = A[i] + B[i] * comp(0, 1);
DFT(P, -1);
for(int i = 0; i < need; ++i) {
A[i] = comp(P[i].x, 0); B[i] = comp(P[i].y, 0);
}
}
void Main(int n, int m, int p, int *a, int *b, int *ans){
N = n; M = m; P = p;
for(int i = 0; i < need; ++i) A[i] = B[i] = C[i] = D[i] = comp();
for(int i = 0; i <= N; ++i) {
int x = a[i]; A[i].x = x & 32767; B[i].x = x >> 15;
}
for(int i = 0; i <= M; ++i) {
int x = b[i]; C[i].x = x & 32767; D[i].x = x >> 15;
}
init(N + M + 1); DFT(A, B); DFT(C, D);
static comp A1[_], B1[_], C1[_], D1[_];
for (int i = 0; i < need; i ++ ) {
A1[i] = A[i] * C[i], B1[i] = A[i] * D[i], C1[i] = B[i] * C[i], D1[i] = B[i] * D[i];
}
IDFT(A1, B1); IDFT(C1, D1);
for (int i = 0; i <= N + M; i ++ ) {
ans[i] = ((LL)round(A1[i].x) + (((LL)round(B1[i].x) + (LL)round(C1[i].x)) % P) << 15) + (((LL)round(D1[i].x) % P) << 30) % P;
}
}
};
const int N = 1e5 + 10;
int fac[N], infac[N], inv[N];
int qmi(int a, int b) {
int res = 1;
while(b) {
if(b & 1) res = res * a % mod;
a = a * a % mod;
b >>= 1;
}
return res;
}
void init() {
inv[1] = 1;
for (int i = 2; i < N; i ++ ) inv[i] = mod - inv[mod % i] * (mod / i) % mod;
infac[0] = fac[0] = 1;
for(int i = 1; i < N; i ++ ) fac[i] = fac[i - 1] * i % mod;
infac[N - 1] = qmi(fac[N - 1], mod - 2);
for (int i = N - 2; i >= 0; i -- ) infac[i] = infac[i + 1] * (i + 1) % mod;
}
int C(int a, int b) {
if(b > a) return 0;
return fac[a] * infac[b] % mod * infac[a - b] % mod;
}
void solve() {
LL ans = 0;
int n, m; cin >> n >> m;
if(m > n) {
cout << 0 << endl;
return ;
}
if(n == m) {
cout << fac[n - 1] * inv[2] % mod << endl;
return ;
}
int k = n - m;
int cnt = min(m, n - m);
int INV = 1;
for (int i = 0; i <= cnt; i ++ ) {
ans = (ans + C(k + m - i - 1, m - i) * C(k, i) % mod * INV % mod + mod) % mod;
INV = INV * (mod - inv[2]) % mod;
}
ans = ans * fac[n] % mod * infac[k] % mod;
cout << ans << '\n';
}
signed main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
init();
int T; cin >> T;
while(T -- ) {
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 15ms
memory: 87868kb
input:
3 4 2 4 3 5 3
output:
15 12 90
result:
ok 3 number(s): "15 12 90"
Test #2:
score: 0
Accepted
time: 107ms
memory: 87704kb
input:
17446 3 0 3 1 3 2 3 3 4 0 4 1 4 2 4 3 4 4 5 0 5 1 5 2 5 3 5 4 5 5 6 0 6 1 6 2 6 3 6 4 6 5 6 6 7 0 7 1 7 2 7 3 7 4 7 5 7 6 7 7 8 0 8 1 8 2 8 3 8 4 8 5 8 6 8 7 8 8 9 0 9 1 9 2 9 3 9 4 9 5 9 6 9 7 9 8 9 9 10 0 10 1 10 2 10 3 10 4 10 5 10 6 10 7 10 8 10 9 10 10 11 0 11 1 11 2 11 3 11 4 11 5 11 6 11 7 11...
output:
1 3 3 1 1 6 15 12 3 1 10 45 90 60 12 1 15 105 375 630 360 60 1 21 210 1155 3465 5040 2520 360 1 28 378 2940 13545 35280 45360 20160 2520 1 36 630 6552 42525 170100 393120 453600 181440 20160 1 45 990 13230 114345 643545 2286900 4762800 4989600 1814400 181440 1 55 1485 24750 273735 2047815 10239075 3...
result:
ok 17446 numbers