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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#91241#1900. Octopus Gamerania__WA 2ms3468kbC++142.7kb2023-03-27 20:52:312023-03-27 20:52:32

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-27 20:52:32]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3468kb
  • [2023-03-27 20:52:31]
  • 提交

answer

#include<bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

#define ll long long
#define endl '\n'
using namespace std;
using namespace __gnu_pbds;

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
const int N = 5e5 + 7, P1 = 31, P2 = 37, mod = 1e9 + 7;
void fractionToDecimal(int numr, int denr)
{
    string res; // Initialize result

    // Create a map to store already
    // seen remainders, remainder is used
    // as key and its position in
    // result is stored as value.
    // Note that we need
    // position for cases like 1/6.
    // In this case,the recurring sequence
    // doesn't start from first
    // remainder.
    map<int, int> mp;
    mp.clear();

    // Find first remainder
    int rem = numr % denr;

    // Keep finding remainder until either remainder
    // becomes 0 or repeats
    int cnt =0;
    while ((rem != 0)
           && (mp.find(rem) == mp.end()))
    {
        // Store this remainder
        mp[rem] = res.length();

        // Multiply remainder with 10
        rem = rem * 10;

        // Append rem / denr to result
        int res_part = rem / denr;
        res += to_string(res_part);

        // Update remainder
        cnt++;
        rem = rem % denr;
    }
    if (rem == 0)
    {
        cout << cnt << " " << 0 << endl;
    }
    else
        cout << cnt-res.substr(mp[rem]).size() << " " << res.substr(mp[rem]).size() << endl;
}
void doWork() {
    int x,y;
    cin >> x >> y;
    vector<pair<int,int>> ans;
        
    while(x && y)
    {
        if(abs(x) > abs(y))
        {
            int cur = x / y;
            if(abs(x - (cur + 1) * y) < abs(x - cur * y))
                ++cur;
            if(abs(x - (cur - 1) * y) < abs(x - cur * y))
                --cur;
            x -= cur * y;
            ans.push_back({1,-cur});
        }
        else
        {
            swap(x,y);
            int cur = x / y;
            if(abs(x - (cur + 1) * y) < abs(x - cur * y))
                ++cur;
            if(abs(x - (cur - 1) * y) < abs(x - cur * y))
                --cur;
            x -= cur * y;
            swap(x,y);
            ans.push_back({2,-cur});
        }
    }
    cout << ans.size() << endl;
    for(auto it : ans)
        cout << it.first << " " << it.second << endl;
}

int main() {
    ios::sync_with_stdio(false);
    cout.tie(nullptr);
    cin.tie(nullptr);
//    freopen("bisector.in","r",stdin);
//    freopen("bisector.out","w",stdout);
    int t = 1;
    // cout << primes.size() << endl;
    //cin >> t;
    while (t--) {
        doWork();
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 2ms
memory: 3344kb

input:

-3 9

output:

1
2 3

result:

ok heap reached 0 count in less than 50 steps

Test #2:

score: 0
Accepted
time: 2ms
memory: 3400kb

input:

-27 57

output:

2
2 2
1 9

result:

ok heap reached 0 count in less than 50 steps

Test #3:

score: 0
Accepted
time: 2ms
memory: 3364kb

input:

56 15

output:

3
1 -4
2 4
1 -4

result:

ok heap reached 0 count in less than 50 steps

Test #4:

score: 0
Accepted
time: 0ms
memory: 3360kb

input:

6 -2

output:

1
1 3

result:

ok heap reached 0 count in less than 50 steps

Test #5:

score: 0
Accepted
time: 2ms
memory: 3380kb

input:

-84 57

output:

3
1 1
2 2
1 9

result:

ok heap reached 0 count in less than 50 steps

Test #6:

score: 0
Accepted
time: 0ms
memory: 3356kb

input:

-648 -315

output:

3
1 -2
2 -17
1 -2

result:

ok heap reached 0 count in less than 50 steps

Test #7:

score: 0
Accepted
time: 0ms
memory: 3360kb

input:

4418 -527

output:

6
1 8
2 3
1 -3
2 2
1 4
2 -9

result:

ok heap reached 0 count in less than 50 steps

Test #8:

score: 0
Accepted
time: 2ms
memory: 3360kb

input:

55796 83094

output:

6
2 -1
1 -2
2 -23
1 4
2 -38
1 4

result:

ok heap reached 0 count in less than 50 steps

Test #9:

score: 0
Accepted
time: 2ms
memory: 3352kb

input:

581706 382159

output:

10
1 -2
2 2
1 11
2 -5
1 3
2 -2
1 -3
2 -7
1 4
2 7

result:

ok heap reached 0 count in less than 50 steps

Test #10:

score: 0
Accepted
time: 2ms
memory: 3412kb

input:

-1570717 -5452307

output:

12
2 -3
1 -2
2 -8
1 -5
2 -3
1 10
2 2
1 3
2 -3
1 5
2 -2
1 -3

result:

ok heap reached 0 count in less than 50 steps

Test #11:

score: 0
Accepted
time: 2ms
memory: 3468kb

input:

35296299 62120456

output:

10
2 -2
1 4
2 6
1 55
2 -3
1 11
2 5
1 3
2 -10
1 -5

result:

ok heap reached 0 count in less than 50 steps

Test #12:

score: 0
Accepted
time: 2ms
memory: 3368kb

input:

133453354 276321715

output:

12
2 -2
1 -14
2 -6
1 4
2 -3
1 -3
2 -3
1 3
2 -20
1 5
2 7
1 7

result:

ok heap reached 0 count in less than 50 steps

Test #13:

score: -100
Wrong Answer
time: 2ms
memory: 3388kb

input:

4087302427 739712346

output:

6
1 -65797
2 -28
1 -9
2 14
1 2
2 4

result:

wrong answer absolute count of balls in the heaps must be less than 1000000000000000000