#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2000005;

vector <pair <int,int> > vec[6];
int win[2],a[10][10],n,k;

void calcwin(){
    for(int i = 1;i <= n;i ++){
        for(int j = 1;j <= n;j ++){
            if(a[i][j]){
                int flg = 1;
                flg = 1; for(int l = 0;l < k;l ++) if(i + l > n || a[i + l][j] != a[i][j]) flg = 0;
                if(flg) win[a[i][j]] = 1;
                flg = 1; for(int l = 0;l < k;l ++) if(j + l > n || a[i][j + l] != a[i][j]) flg = 0;
                if(flg) win[a[i][j]] = 1;
                flg = 1; for(int l = 0;l < k;l ++) if(i + l > n || j + l > n || a[i + l][j + l] != a[i][j]) flg = 0;
                if(flg) win[a[i][j]] = 1;
                flg = 1; for(int l = 0;l < k;l ++) if(i + l > n || j - l < 1 || a[i + l][j - l] != a[i][j]) flg = 0;
                if(flg) win[a[i][j]] = 1;
            }
        }
    }
}

void solve(int id){
    for(int i = 0;i <= 2;i ++) vec[i].clear();
    for(int i = 1;i <= n;i ++){
        for(int j = 1;j <= n;j ++){
            vec[a[i][j]].push_back(make_pair(i,j));
        }
    }
    for(int i = 0;i < vec[3 - id].size();i ++){
        cout << vec[id][i].first << ' ' << vec[id][i].second << '\n';
        cout << vec[3 - id][i].first << ' ' << vec[3 - id][i].second << '\n';
    }
    if(vec[id].size() > vec[3 - id].size()) cout << vec[id][vec[id].size() - 1].first << ' ' << vec[id][vec[id].size() - 1].second << '\n';
}

int main(){
    ios::sync_with_stdio(false);
    int TC;
    cin >> TC;
    while(TC --){
        int cnt[3] = {0};
        cin >> n >> k;
        for(int i = 1;i <= n;i ++){
            for(int j = 1;j <= n;j ++){
                char ch; cin >> ch;
                a[i][j] = 0;
                if(ch == 'o') a[i][j] = 1,cnt[1] ++;
                if(ch == 'x') a[i][j] = 2,cnt[2] ++;
            }
        }
        win[1] = win[2] = 0;
        calcwin();
        // cout << cnt[1] << ' ' << cnt[2] << ' ' << win[1] << ' ' << win[2] << endl;
        if((win[1] && win[2]) || abs(cnt[2] - cnt[1]) > 1 || (!win[1] && !win[2] && cnt[1] + cnt[2] < n * n)){
            // both win, wrong step, nobody win but not end
            cout << "NIE\n";
            continue;
        }
        int flg = 0,cur = (win[1] ? 1 : 2);
        if(!win[1] && !win[2]) cur = (cnt[1] > cnt[2] ? 1 : 2);
        if(win[cur] && cnt[cur] < cnt[3 - cur]){
            cout << "NIE\n";
            continue;
        }
        for(int i = 1;i <= n;i ++){
            for(int j = 1;j <= n;j ++){
                if(a[i][j] == cur){
                    a[i][j] = 0;
                    win[1] = win[2] = 0;
                    calcwin();
                    if(!win[1] && !win[2]){
                        cout << "TAK\n";
                        flg = 1; solve(cnt[cur] == cnt[3 - cur] ? 3 - cur : cur);
                        cout << i << ' ' << j << '\n';
                        break;
                    }
                    a[i][j] = cur;
                }
            }
            if(flg) break;
        }
        if(!flg) cout << "NIE\n";
    }
    return 0;
}