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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#89388#5251. ConstellationsMilk_FengWA 358ms136636kbC++2.2kb2023-03-19 22:04:342023-03-19 22:04:36

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-19 22:04:36]
  • 评测
  • 测评结果:WA
  • 用时:358ms
  • 内存:136636kb
  • [2023-03-19 22:04:34]
  • 提交

answer

#include <bits/stdc++.h>
#include <set> 
using namespace std;

typedef long long LL;
typedef unsigned long long ULL;
//typedef __int128 LLL;

int read() {
    int x = 0, f = 1; char c = getchar();
    while(c < '0' || c > '9') c == '-' ? f = -1: 0, c = getchar();
	while(c >= '0' && c <= '9') x = (x << 1) + (x << 3) + (c ^ '0'), c = getchar();
    return x * f;
}

LL X[5050], Y[5050], sz[5050], dis_[5050][5050];

struct Pair {
    int i, j;
    Pair(int _i, int _j): i(_i), j(_j) {}
    bool operator < (const Pair &o) const {
        int thisnew = max(i, j), thisold = min(i, j);
        int othernew = max(o.i, o.j), otherold = min(o.i, o.j);
        
        LL tmp1 = dis_[i][j] * sz[o.i] * sz[o.j];
        LL tmp2 = dis_[o.i][o.j] * sz[i] * sz[j];
        
        if(tmp1 == tmp2) {
            if(thisold == otherold) return thisnew < othernew;
            else return thisold < otherold;
        }
        else return tmp1 < tmp2;
    }
};

set<Pair> s[4050];
set<int> exist;

signed main() {
    int n = read();
    for(int i = 1; i <= n; ++i) X[i] = read(), Y[i] = read();
    for(int i = 1; i <= n; ++i) {
        for(int j = i + 1; j <= n; ++j) {
            dis_[i][j] = dis_[j][i] = (X[i] - X[j]) * (X[i] - X[j]) + (Y[i] - Y[j]) * (Y[i] - Y[j]);
            s[i].insert(Pair(i, j));
        }
        exist.insert(i);
        sz[i] = 1;
    }
    
    while(exist.size() > 1) {
        if(n > 100) break;
        
        Pair mn = *s[*exist.begin()].begin();
        
        for(int i: exist) {
            if(s[i].empty()) continue;
            Pair pair = *(s[i].begin());
            if(pair < mn) mn = pair;
        }
        int id1 = mn.i, id2 = mn.j;
        
        sz[++n] = sz[id1] + sz[id2];
        for(int i: exist) dis_[i][n] = dis_[n][i] = dis_[i][id1] + dis_[i][id2];
        
        for(int i: exist) if(i < id1) s[i].erase(Pair(i, id1));
        for(int i: exist) if(i < id2) s[i].erase(Pair(i, id2));
        for(int i: exist) if(i != id1 && i != id2) s[i].insert(Pair(i, n));
        
        exist.erase(id1), exist.erase(id2);
        exist.insert(n);
        
        printf("%lld\n", sz[n]);
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3700kb

input:

2
0 0
1 0

output:

2

result:

ok single line: '2'

Test #2:

score: -100
Wrong Answer
time: 358ms
memory: 136636kb

input:

2000
1000 -1000
1000 -999
1000 -998
1000 -997
1000 -996
1000 -995
1000 -994
1000 -993
1000 -992
1000 -991
1000 -990
1000 -989
1000 -988
1000 -987
1000 -986
1000 -985
1000 -984
1000 -983
1000 -982
1000 -981
1000 -980
1000 -979
1000 -978
1000 -977
1000 -976
1000 -975
1000 -974
1000 -973
1000 -972
1000...

output:


result:

wrong answer 1st lines differ - expected: '2', found: ''