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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#88796#5745. Graph IsomorphismgalaxiasWA 201ms6064kbC++141.8kb2023-03-17 14:37:512023-03-17 14:37:55

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-17 14:37:55]
  • 评测
  • 测评结果:WA
  • 用时:201ms
  • 内存:6064kb
  • [2023-03-17 14:37:51]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
vector<int> G[N];

int a[5][5] , n , m , deg[N] , d[5][5];

int read()
{
	int x;
	scanf("%d" , &x);
	return x;
}

int b[10] = {1 , 1 , 1 , 2 , 2 , 3} , c[10] = {2 , 3 , 4 , 3 , 4 , 4};

bool vis[10];

bool check()
{
	for(int i = 1 ; i <= 4 ; ++ i)
		for(int j = 1 ; j <= 4 ; ++ j)
			d[i][j] = 0;
	for(int i = 0 ; i < 6 ; ++ i)
		if(vis[i]) d[b[i]][c[i]] = d[c[i]][b[i]] = 1;
	int p[5];
	for(int i = 1 ; i <= n ; ++ i)
		p[i] = i;
	do
	{

		bool flag = true;
		for(int i = 1 ; i <= n ; ++ i)
			for(int j = 1 ; j <= n ; ++ j)
				if(a[i][j] ^ d[p[i]][p[j]]) flag = false;
		if(flag)
		{
			// for(int i = 0 ; i < 6 ; ++ i)
			// 	printf("%d " , vis[i]);
			// puts("");
			return true;
		}
	}while(next_permutation(p + 1 , p + 1 + n));
	return false;
}

int dfs(int now)
{
	if(now == 6) return check();
	int ret = 0;
	vis[now] = false; ret = dfs(now + 1);
	vis[now] = true; ret += dfs(now + 1) , vis[now] = false;
	return ret;
}

bool force()
{
	for(int i = 1 ; i <= m ; ++ i)
	{
		int x = read() , y = read();
		a[x][y] = a[y][x] = 1;
	}
	if(n <= 3) return true;
	return dfs(0) <= n;
}

bool solve()
{
	scanf("%d%d", &n, &m);
	if(n <= 4) return force();
	for(int i = 1; i <= n; i ++) deg[i] = 0;
	for(int i = 1; i <= m; i ++)
	{
		int u, v;
		scanf("%d%d", &u, &v);
		deg[u] ++;
		deg[v] ++;
	}
	if(m == 1ll * n * (n - 1) / 2) return true;
	if(m == 0) return true;
	int cnt1 = 0 , cnt2 = 0;
	for(int i = 1 ; i <= n ; ++ i)
		cnt1 += (deg[i] == 1) , cnt2 += (deg[i] == n - 1);
	if((cnt1 == n - 1) && (cnt2 == 1)) return true;
	if((cnt1 == 1) && (cnt2 == n - 1)) return true;
	return false;
}

int main()
{
	int T;
	scanf("%d", &T);
	while(T --)
		if(solve()) puts("YES");
		else puts("NO");
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 5736kb

input:

3
3 3
1 2
2 3
3 1
3 2
1 2
2 3
5 5
1 2
2 3
3 4
4 5
5 1

output:

YES
YES
NO

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: 0
Accepted
time: 15ms
memory: 6064kb

input:

39982
3 2
2 1
3 2
2 1
1 2
2 1
2 1
3 3
3 1
2 3
1 2
2 1
1 2
3 3
3 1
3 2
2 1
2 1
1 2
3 2
1 2
3 1
3 3
2 1
3 1
2 3
2 1
1 2
3 2
2 1
3 2
3 3
2 3
3 1
2 1
3 3
2 1
1 3
2 3
3 3
3 1
3 2
1 2
2 1
2 1
2 1
2 1
3 1
3 1
2 1
2 1
2 1
1 2
3 2
1 3
3 2
3 2
1 2
1 3
3 2
3 2
1 3
2 1
1 2
3 2
3 2
3 1
3 3
2 3
3 1
1 2
2 1
1 2
3 ...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
...

result:

ok 39982 token(s): yes count is 39982, no count is 0

Test #3:

score: -100
Wrong Answer
time: 201ms
memory: 5712kb

input:

33365
3 3
3 1
2 3
2 1
2 1
2 1
4 6
1 2
3 4
4 2
2 3
3 1
4 1
2 1
1 2
2 1
1 2
4 5
1 4
1 2
4 2
3 4
1 3
4 3
4 2
2 1
1 3
3 1
3 2
4 3
1 3
1 2
3 4
3 3
3 2
3 1
2 1
3 1
2 3
3 1
1 3
3 1
2 1
3 2
1 3
3 2
4 5
3 1
4 2
3 4
2 3
2 1
4 2
1 2
3 2
2 1
2 1
3 2
1 2
2 3
3 1
3 2
4 1
3 4
3 1
2 1
4 3
1 2
4 2
3 2
2 1
2 1
4 5
3 ...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
...

result:

wrong answer expected NO, found YES [6th token]