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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#88367#5810. Doubly-sorted Grid10circle10 16ms15980kbC++141.8kb2023-03-16 08:52:182023-03-16 08:52:20

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-16 08:52:20]
  • 评测
  • 测评结果:10
  • 用时:16ms
  • 内存:15980kb
  • [2023-03-16 08:52:18]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef vector<int> vint;
int read() {
	int a = 0, b = 0; char c = getchar();
	while (c < '0' || c > '9') b ^= (c == '-'), c = getchar();
	while (c >= '0' && c <= '9') a = a * 10 - 48 + c, c = getchar();
	return b ? -a : a;
}

const int mod = 10007, K = 1 << 20;

int n, m, ans;
char s[12][12];
int dp[2][K], popc[K];
int cu[1024], lb[1024];

int sol(){
	n = read(), m = read(), ans = 0;
	for (int i = 0; i < n; i++) scanf("%s", s[i]);
	for (int i = 0; i < n; i++) for (int j = 0; j < m; j++) if('a' <= s[i][j] && s[i][j] <= 'z') s[i][j] -= 'a';
	int u = n + m, o = 1 << u;
	memset(dp, 0, sizeof dp);
	dp[1][(1 << m) - 1] = 1;
	static vint q;
	q.clear(); for (int j = 0; j < o; ++j) if (popc[j] == m) q.push_back(j);
	for (int i = 0; i < 26; i++) {
		for (int j : q) {
			int c[10] = {}, ct = 0, re = 0, ag = 0;
			for (int k = 1; k < u; k++) {
				re += (j >> k - 1) & 1;
				if(!((j >> k - 1) & 1) && ((j >> k) & 1)) {
					int q = m - re - 1;
					int p = k - re - 1;
					if (s[p][q] != '.' && s[p][q] != i)continue;
					c[ct++] = (1 << k) | (1 << k - 1);
				}
			}
			dp[i & 1][j] = dp[!(i & 1)][j];
			int p = 1 << ct;
			for (int k = 1; k < p; k++) {
				cu[k] = cu[k & k - 1] ^ cu[k & -k];
				if (k == (k & -k)) {
					cu[k] = 0;
					for (int l = 0; l < ct && !cu[k]; l++) if((k >> l) & 1) cu[k] = c[l];
				}
				int q = cu[k] ^ j;
				dp[i & 1][j] += (popc[k] & 1) ? dp[i & 1][q] : mod - dp[i & 1][q];
			}
			dp[i & 1][j] %= mod;
		}
	}
	return dp[1][(1 << m) - 1 << n];
}

int main() {
	for (int i = 1; i < K; ++i) popc[i] = popc[i & i - 1] + 1;
	for (int i = 0; i < 1024; i++) lb[i] = lb[i >> 1] + 1;
	int T = read();
	for (int i = 1; i <= T; i++) {
		printf("Case #%d: %d\n", i, sol());
	}
	return 0;
}

Details

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Subtask #1:

score: 10
Accepted

Test #1:

score: 10
Accepted
time: 16ms
memory: 15980kb

input:

40
4 4
....
....
....
....
4 4
abcd
bcde
cdef
defg
4 4
bbcc
ccde
cdef
deef
4 4
....
....
.r..
..e.
3 4
....
....
...g
1 3
f..
2 2
.b
bb
2 3
...
..f
4 4
....
....
..t.
..d.
3 3
.gn
...
...
4 4
...a
...b
...c
...d
4 4
...b
..bb
.bbb
bbbb
4 4
a...
.b..
..c.
...d
3 3
c..
glw
..w
1 4
....
1 3
d.v
4 2
..
...

output:

Case #1: 7285
Case #2: 1
Case #3: 1
Case #4: 0
Case #5: 718
Case #6: 231
Case #7: 2
Case #8: 686
Case #9: 0
Case #10: 3500
Case #11: 330
Case #12: 14
Case #13: 4096
Case #14: 2756
Case #15: 3737
Case #16: 19
Case #17: 8175
Case #18: 3737
Case #19: 7279
Case #20: 256
Case #21: 23
Case #22: 7569
Case ...

result:

ok 40 lines

Subtask #2:

score: 0
Time Limit Exceeded

Test #2:

score: 0
Time Limit Exceeded

input:

40
5 10
..........
..........
..........
..........
..........
10 10
....a.....
....c.....
....g.....
....j.....
....l.....
....m.....
....n.....
....q.....
....t.....
....v.....
10 10
..........
..........
..........
..........
..........
..........
..........
..........
...ok.....
..........
9 10
...

output:


result: