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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#876839 | #3501. Jail | Mispertion | 0 | 0ms | 0kb | C++23 | 5.4kb | 2025-01-31 13:50:49 | 2025-01-31 13:50:49 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
using ll = long long;
using ld = long double;
using pii = pair<int, int>;
#define S second
#define F first
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#define mispertion ios_base::sync_with_stdio(0),cin.tie(0)
#define sz(x) (int)x.size()
#define all(x) x.begin(),x.end()
const ld PI = 3.1415926535;
const ld eps = 1e-9;
const int N = 2e5 + 2;
const int M = 1.5e6 + 13;
ll mod = 1e9+7;
const int infi = 1e9;
const ll infl = 1e16;
const int P = 31;
int mult(int a, int b) {
return a * 1LL * b % mod; }
int sum(int a, int b) {
if(a + b >= mod)
return a + b - mod;
if(a + b < 0)
return a + b + mod;
return a + b;
}
ll binpow(ll a, ll n) {
if (n == 0) return 1;
if (n % 2 == 1) {
return binpow(a, n - 1) * a % (mod);
} else {
ll b = binpow(a, n / 2);
return b * b % (mod);
}
}
const int K = 19;
int n, m, s[N], t[N], sz[N], tin[N], tout[N], tick, par[N], h[N], d[N], her[N], cur;
int l[N * 15], r[N * 15], pss[N * 15], pst[N * 15], used[N * 15];
vector<int> g[N], ng[N * 15];
void precalc(int v, int p){
par[v] = p;
sz[v] = 1;
for(auto u : g[v]){
if(u == p) continue;
d[u] = d[v] + 1;
precalc(u, v);
sz[v] += sz[u];
}
for(auto &u : g[v]){
if(u == p) continue;
if(g[v][0] == p || sz[g[v][0]] < sz[u]){
swap(u, g[v][0]);
}
}
}
void dfs(int v, int r){
tin[v] = ++tick;
her[tin[v]] = v;
h[v] = r;
for(auto u : g[v]){
if(u == par[v]) continue;
dfs(u, (u == g[v][0] ? r : u));
}
tout[v] = tick;
}
bool ispar(int p, int v){
return (tin[p] <= tin[v] && tout[v] <= tout[p]);
}
void buildd(int v, int tl, int tr){
if(tl == tr){
pst[her[tl]] = v;
return;
}
int tm = (tl + tr) / 2;
cur++;
l[v] = cur;
buildd(cur, tl, tm);
cur++;
r[v] = cur;
buildd(cur, tm + 1, tr);
ng[v].push_back(l[v]);
ng[v].push_back(r[v]);
}
void buildu(int v, int tl, int tr){
if(tl == tr){
pss[her[tl]] = v;
return;
}
int tm = (tl + tr) / 2;
cur++;
l[v] = cur;
buildu(cur, tl, tm);
cur++;
r[v] = cur;
buildu(cur, tm + 1, tr);
ng[l[v]].push_back(v);
ng[r[v]].push_back(v);
}
void addu(int v, int tl, int tr, int lg, int rg, int x){
if(tl > rg || lg > tr)
return;
if(lg <= tl && tr <= rg){
ng[v].push_back(x);
return;
}
int tm = (tl + tr) / 2;
addu(l[v], tl, tm, lg, rg, x);
addu(r[v], tm + 1, tr, lg, rg, x);
}
void addd(int v, int tl, int tr, int lg, int rg, int x){
if(tl > rg || lg > tr)
return;
if(lg <= tl && tr <= rg){
ng[x].push_back(v);
return;
}
int tm = (tl + tr) / 2;
addd(l[v], tl, tm, lg, rg, x);
addd(r[v], tm + 1, tr, lg, rg, x);
}
int check(int v){
used[v] = 1;
int ret = 1;
for(auto u : ng[v]){
if(used[u] == 1)
return 0;
if(!used[u])
ret &= check(u);
}
used[v] = 2;
return ret;
}
inline void solve() {
cin >> n;
for(int i = 1; i <= n; i++)
g[i].clear(), ng[i].clear();
tick = 0;
for(int i = 1; i < n; i++){
int a, b;
cin >> a >> b;
g[a].push_back(b);
g[b].push_back(a);
}
precalc(1, 1);
dfs(min(n, 50), 1);
cin >> m;
for(int i = 1; i <= m; i++)
cin >> s[i] >> t[i];
cur = m + 1;
int rd = cur;
buildd(rd, 1, n);
cur++;
int ru = cur;
buildu(ru, 1, n);
for(int i = 1; i <= m; i++){
ng[pst[t[i]]].push_back(i);
ng[i].push_back(pss[s[i]]);
int u = s[i], v = t[i];
if(ispar(v, u)){
for(auto e : g[v]){
if(ispar(e, u)){
v = e;
break;
}
}
}else{
v = par[v];
}
while(h[v] != h[u]){
if(d[h[v]] < d[h[u]]){
swap(v, u);
}
addd(rd, 1, n, tin[h[v]], tin[v], i);
v = par[h[v]];
}
if(d[v] < d[u])
swap(u, v);
addd(rd, 1, n, tin[u], tin[v], i);
v = s[i], u = t[i];
if(ispar(v, u)){
for(auto e : g[v]){
if(ispar(e, u)){
v = e;
break;
}
}
}else{
v = par[v];
}
while(h[v] != h[u]){
if(d[h[v]] < d[h[u]]){
swap(v, u);
}
addu(ru, 1, n, tin[h[v]], tin[v], i);
v = par[h[v]];
}
if(d[v] < d[u])
swap(u, v);
addu(ru, 1, n, tin[u], tin[v], i);
}
int ans = 1;
for(int i = 1; i <= cur; i++)
used[i] = 0;
for(int i = 1; i <= cur; i++)
if(!used[i])
ans &= check(i);
for(int i = 1; i <= cur; i++)
ng[i].clear();
cout << (ans ? "Yes\n" : "No\n");
}
signed main() {
mispertion;
int t = 1;
cin >> t;
for(int i = 1; i <= t; i ++){
solve();
}
return 0;
}
詳細信息
Subtask #1:
score: 0
Time Limit Exceeded
Test #1:
score: 0
Time Limit Exceeded
input:
1 2 1 2 2 1 2 2 1
output:
result:
Subtask #2:
score: 0
Time Limit Exceeded
Test #21:
score: 0
Time Limit Exceeded
input:
20 250 1 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 3 23 1 24 24 25 25 26 5 26 1 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 7 42 2 43 43 44 44 45 45 46 4 46 2 47 47 48 48 49 49 50 50 51 51 52 52 53 53 54 54 55 12 55 2 56 56 57 57 58 58 59 59 ...
output:
result:
Subtask #3:
score: 0
Skipped
Dependency #2:
0%
Subtask #4:
score: 0
Skipped
Dependency #3:
0%
Subtask #5:
score: 0
Skipped
Dependency #4:
0%
Subtask #6:
score: 0
Time Limit Exceeded
Test #66:
score: 0
Time Limit Exceeded
input:
1000 10 1 2 2 3 1 4 4 5 4 6 4 7 2 8 8 9 3 10 2 5 4 1 9 10 1 2 1 3 1 4 4 5 4 6 3 7 3 8 2 9 6 10 2 2 9 1 5 10 1 2 2 3 1 4 4 5 4 6 2 7 3 8 2 9 1 10 2 10 2 7 5 10 1 2 1 3 1 4 2 5 1 6 3 7 2 8 7 9 2 10 2 10 5 2 7 10 1 2 1 3 1 4 3 5 5 6 3 7 7 8 1 9 8 10 2 6 7 1 2 10 1 2 1 3 3 4 2 5 4 6 3 7 1 8 4 9 1 10 2 1...
output:
result:
Subtask #7:
score: 0
Skipped
Dependency #1:
0%