QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#867539#2936. Simple Collatz SequenceWeaRD276#TL 0ms3840kbC++201.4kb2025-01-23 18:32:552025-01-23 18:32:55

Judging History

This is the latest submission verdict.

  • [2025-01-23 18:32:55]
  • Judged
  • Verdict: TL
  • Time: 0ms
  • Memory: 3840kb
  • [2025-01-23 18:32:55]
  • Submitted

answer

#include <bits/stdc++.h>
using namespace std;

#include  <ext/pb_ds/assoc_container.hpp>
#include  <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

#define sz(x) (int)(x).size()
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb push_back
#define x first
#define y second
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)

typedef long long ll;
typedef double db;
typedef long double LD;
typedef pair<int, int> pii;
typedef pair<db, db> pdd;
typedef pair<ll, ll> pll;

const int MOD = 1000007;

ll add(ll a, ll b)
{
	return a + b >= MOD ? a + b - MOD : a + b;
}

int solve()
{
	int m;
	if (!(cin >> m))
		return 1;
	
	vector<ll> fib{1, 1};
	while (sz(fib) != m)
	{
		int n = sz(fib);
		fib.pb(add(fib[n - 1], fib[n - 2]));
	}
		
	cout << fib.back() << '\n';
	
	return 0;
}

int32_t main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	int TET = 1e9;
	//cin >> TET;
	for (int i = 1; i <= TET; i++)
	{
		if (solve())
		{
			break;
		}
		#ifdef ONPC
			cerr << "_____________________________\n";
		#endif
	}
	#ifdef ONPC
		cerr << "\nfinished in " << clock() * 1.0 / CLOCKS_PER_SEC << " sec\n";
	#endif
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3584kb

input:

6

output:

8

result:

ok single line: '8'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3840kb

input:

12345

output:

540591

result:

ok single line: '540591'

Test #3:

score: -100
Time Limit Exceeded

input:

1

output:


result: