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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#863632#9870. ItemsliyelinWA 703ms9724kbC++146.1kb2025-01-19 20:26:162025-01-19 20:26:17

Judging History

你现在查看的是最新测评结果

  • [2025-01-19 20:26:17]
  • 评测
  • 测评结果:WA
  • 用时:703ms
  • 内存:9724kb
  • [2025-01-19 20:26:16]
  • 提交

answer

#include <bits/stdc++.h>
#define FOR(i, l, r) for (int i = (l); i <= (r); ++i)
#define ROF(i, r, l) for (int i = (r); i >= (l); --i)
#define popc(x) __builtin_popcount(x)
#define allc(x) (x).begin(), (x).end()
#define SZ(v) (int)v.size()
#define PII pair<int, int>
#define PB push_back
#define MP make_pair
#define FI first
#define SE second
using namespace std;
using ll = long long;
using ull = unsigned long long;
using ld = long double;
bool Mbe;
template <typename A, typename B>
void chkmax(A &a, B b) {
    a = a > b ? a : b;
}
template <typename A, typename B>
void chkmin(A &a, B b) {
    a = a < b ? a : b;
}
namespace lyl {
    template<int MOD> struct modint {
        int val;
        constexpr modint(int v = 0) noexcept : val(v % MOD) { if (val < 0) val += MOD; }
        constexpr int getmod() const { return MOD; }
        constexpr modint operator - () const noexcept { return val ? MOD - val : 0; }
        constexpr modint operator + (const modint &r) const noexcept { return modint(*this) += r; }
        constexpr modint operator - (const modint &r) const noexcept { return modint(*this) -= r; }
        constexpr modint operator * (const modint &r) const noexcept { return modint(*this) *= r; }
        constexpr modint operator / (const modint &r) const noexcept { return modint(*this) /= r; }
        constexpr modint &operator += (const modint &r) noexcept {
            val += r.val;
            if (val >= MOD) val -= MOD;
            return *this;
        }
        constexpr modint &operator -= (const modint &r) noexcept {
            val -= r.val;
            if (val < 0) val += MOD;
            return *this;
        }
        constexpr modint &operator *= (const modint &r) noexcept {
            val = 1ll * val * r.val % MOD;
            return *this;
        }
        constexpr modint &operator /= (const modint &r) noexcept {
            int a = r.val, b = MOD, u = 1, v = 0;
            while (b) {
                int t = a / b;
                a -= t * b, swap(a, b);
                u -= t * v, swap(u, v);
            }
            val = 1ll * val * u % MOD;
            if (val < 0) val += MOD;
            return *this;
        }
        constexpr bool operator < (const modint &r) const noexcept { return this->val < r.val; }
        constexpr bool operator == (const modint &r) const noexcept { return this->val == r.val; }
        constexpr bool operator != (const modint &r) const noexcept { return this->val != r.val; }
        friend constexpr istream &operator >> (istream &is, modint<MOD> &x) noexcept {
            is >> x.val;
            x.val %= MOD;
            if (x.val < 0) x.val += MOD;
            return is;
        }
        friend constexpr ostream &operator << (ostream &os, const modint<MOD> &x) noexcept { return os << x.val; }
        friend constexpr modint<MOD> modpow(const modint<MOD> &r, ll n) noexcept {
            if (n == 0) return 1;
            if (n < 0) return modpow(modinv(r), -n);
            auto t = modpow(r, n / 2);
            t = t * t;
            if (n & 1) t = t * r;
            return t;
        }
        friend constexpr modint<MOD> modinv(const modint<MOD> &r) noexcept {
            int a = r.val, b = MOD, u = 1, v = 0;
            while (b) {
                int t = a / b;
                a -= t * b, swap(a, b);
                u -= t * v, swap(u, v);
            }
            return modint<MOD>(u);
        }
    };
    const int mod = 998244353;
    using Z = modint<mod>;
    const int N = 4e5 + 5;
    const Z G = 3;
    const Z Gi = (mod + 1) / 3;
    int n, a[N], rev[N];
    ll m;
    void change(Z *f, int n) {
        FOR (i, 0, n - 1) {
            rev[i] = (rev[i >> 1] >> 1) | ((i & 1) * (n >> 1)); 
            if (i < rev[i]) {
                swap(f[i], f[rev[i]]);
            }
        }
    }
    void NTT(Z *f, int n, int inv) {
        change(f, n);
        for (int k = 2; k <= n; k <<= 1) {
            Z wn = modpow(inv == -1 ? Gi : G, (mod - 1) / k);
            for (int i = 0; i < n; i += k) {
                Z w = 1;
                for (int p = i * k; p < i * k + k / 2; ++p) {
                    Z x = f[p], y = w * f[p + k / 2];
                    f[p] = x + y;
                    f[p + k / 2] = x - y;
                    w *= wn;
                }
            }
        }
        if (inv == -1) {
            Z t = modinv((Z)n);
            FOR (i, 0, n - 1) {
                f[i] *= t;
            }
        }
    }
    void mul(Z *f, Z *g, int len) {
        NTT(f, 1, len);
        NTT(g, 1, len);
        FOR (i, 0, len - 1) {
            f[i] *= g[i];
        }
        NTT(f, -1, len);
    }
    Z ans[N], tmp[N];
    void ksm(Z *f, int n, int k) {
        int len = 1;
        while (len <= n) {
            len <<= 1;
        }
        FOR (i, 0, len) {
            ans[i] = 0;
        }
        ans[n >> 1] = 1;
        while (k) {
            if (k & 1) {
                memcpy(tmp, f, sizeof(tmp));
                mul(ans, tmp, len);
            }
            k >>= 1;
            memcpy(tmp, f, sizeof(tmp));
            mul(f, tmp, len);
        }
    }
    Z F[N];
    void solve() {
        memset(F, 0, sizeof(F));
        memset(ans, 0, sizeof(ans));
        cin >> n >> m;
        FOR (i, 1, n) {
            cin >> a[i];
        }
        ll d = m / n;
        FOR (i, 1, n) {
            a[i] -= d;
        }
        m -= d * n;
        FOR (i, 1, n) {
            a[i] += n;
            F[a[i]] += 1;
        }
        ksm(F, n << 1, n);
        FOR (i, 1, n) {
            F[a[i]] = 0;
        }
        if (ans[n + m] != 0) {
            cout << "Yes\n";
        } else {
            cout << "No\n";
        }
    }
}
bool Meb;
int main() {
    // freopen(".in", "r", stdin);
    // freopen(".out", "w", stdout);
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    int T;
    cin >> T;
    while (T--) {
        lyl::solve();
    }
    // cerr << "Space: " << abs(&Meb - &Mbe) / 1024.0 / 1024.0 << "MB\n";
    // cerr << "Time: " << clock() * 1000.0 / CLOCKS_PER_SEC << "ms\n";
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 9676kb

input:

4
5 25
0 0 0 0 5
5 11
4 4 4 5 5
5 0
1 2 3 4 5
5 25
0 1 2 3 4

output:

Yes
No
No
No

result:

ok 4 token(s): yes count is 1, no count is 3

Test #2:

score: -100
Wrong Answer
time: 703ms
memory: 9724kb

input:

1314
1 0
0
1 0
1
1 1
0
1 1
1
2 0
0 0
2 0
0 1
2 0
0 2
2 0
1 0
2 0
1 1
2 0
1 2
2 0
2 0
2 0
2 1
2 0
2 2
2 1
0 0
2 1
0 1
2 1
0 2
2 1
1 0
2 1
1 1
2 1
1 2
2 1
2 0
2 1
2 1
2 1
2 2
2 2
0 0
2 2
0 1
2 2
0 2
2 2
1 0
2 2
1 1
2 2
1 2
2 2
2 0
2 2
2 1
2 2
2 2
2 3
0 0
2 3
0 1
2 3
0 2
2 3
1 0
2 3
1 1
2 3
1 2
2 3
2 0...

output:

Yes
No
No
Yes
Yes
Yes
Yes
Yes
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
Yes
Yes
Yes
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
No
No
Yes
No
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Y...

result:

wrong answer expected YES, found NO [15th token]