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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#863631#9733. Heavy-light Decomposition2018ljw#WA 1ms2048kbC++14971b2025-01-19 20:23:512025-01-19 20:23:51

Judging History

你现在查看的是最新测评结果

  • [2025-01-19 20:23:51]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:2048kb
  • [2025-01-19 20:23:51]
  • 提交

answer

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<vector>
using namespace std;
struct chn{
	int l,r,len;
}a[100001];
bool operator<(chn x,chn y){
	return x.len<y.len;
}
int n,k,fa[100001];
void solve(){
	int i,j;
	scanf("%d%d",&n,&k);
	for(i=1;i<=k;i++){
		scanf("%d%d",&a[i].l,&a[i].r);
		a[i].len=a[i].r-a[i].l+1;
		for(j=a[i].l+1;j<=a[i].r;j++)fa[j]=j-1;
	}
	sort(a+1,a+k+1);
	if(n==1){
		for(i=1;i<=n;i++)printf("%d ",i-1);
		printf("\n");
		return;
	}
	if(a[1].len==a[k].len){
		printf("IMPOSSIBLE\n");
		return;
	}
	fa[a[k].l]=0;
	if(a[k].len!=a[k-1].len){
		for(i=1;i<k;i++)fa[a[i].l]=a[k].l;
		for(i=1;i<=n;i++)printf("%d ",fa[i]);
		printf("\n");
		return;
	}
	if(a[k].len==a[1].len+1){
		printf("IMPOSSIBLE\n");
		return;
	}
	for(i=2;i<k;i++)fa[a[i].l]=a[k].l;
	fa[a[1].l]=a[k].l+1;
	for(i=1;i<=n;i++)printf("%d ",fa[i]);
	printf("\n");
}
int main(){
	int t;
	scanf("%d",&t);
	while(t--)solve();
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 1664kb

input:

3
12 5
1 5
9 11
7 8
6 6
12 12
4 3
1 1
4 4
2 3
2 2
1 1
2 2

output:

0 1 2 3 4 1 1 7 1 9 10 1 
2 0 2 2 
IMPOSSIBLE

result:

ok Correct. (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 2048kb

input:

10
1 1
1 1
100000 1
1 100000
12 4
1 3
4 6
7 9
10 12
6 3
4 6
2 3
1 1
8999 3
1 3000
3001 6000
6001 8999
14 4
1 3
4 6
7 10
11 14
17 5
1 3
4 6
7 10
11 14
15 17
19999 2
1 9999
10000 19999
1 1
1 1
5 3
1 1
2 3
4 5

output:

0 
IMPOSSIBLE
IMPOSSIBLE
4 4 2 0 4 5 
IMPOSSIBLE
IMPOSSIBLE
IMPOSSIBLE
10000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 7...

result:

wrong answer Case 2, jury find a solution while participant not. (test case 2)