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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#859082#9802. Light Up the GridGodwangWA 22ms3712kbC++237.9kb2025-01-17 14:47:552025-01-17 14:47:56

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你现在查看的是最新测评结果

  • [2025-01-17 14:47:56]
  • 评测
  • 测评结果:WA
  • 用时:22ms
  • 内存:3712kb
  • [2025-01-17 14:47:55]
  • 提交

answer

#include <iostream>
using namespace std;
#include <set>
#include <algorithm>
#include <cmath>
#include <map>
#include <cstdio>
#include <string>
#include <cstring>
#include <string.h>
#include <stdlib.h>
#include <iomanip>
#include <fstream>
#include <stdio.h>
#include <stack>
#include <queue>
#include <ctype.h>
#include <vector>
#include <random>
#include <list>
#define ll long long
#define ull unsigned long long
#define pb push_back
#define rep(i, a, n) for (int i = a; i <= n; i++)
#define per(i, a, n) for (int i = n; i >= a; i--)
#define pii pair<int, int>
#define pli pair<ll, int>
#define pil pair<int, ll>
#define pll pair<ll, ll>
#define lowbit(x) ((x) & (-x))
ll extend_gcd(ll a, ll b, ll &x, ll &y)
{
    if (b == 0)
    {
        x = 1;
        y = 0;
        return a;
    }
    ll d = extend_gcd(b, a % b, y, x);
    y -= a / b * x;
    return d;
}
ll fastpow(ll a, ll n, ll mod)
{
    ll ans = 1;
    a %= mod;
    while (n)
    {
        if (n & 1)
            ans = (ans * a) % mod; //% mod
        a = (a * a) % mod;         //% mod
        n >>= 1;
    }
    return ans;
}

inline void write(__int128 x)
{
    if (x > 9)
    {
        write(x / 10);
    }
    putchar(x % 10 + '0');
}
__int128 sqrt(__int128 m)
{
    __int128 leftt = 0, rightt = ((__int128)1) << 51, ret = -1, mid;
    while (leftt < rightt)
    {
        mid = (leftt + rightt) / 2;
        if (mid * mid > m)
        {
            rightt = mid;
        }
        else
        {
            leftt = mid + 1;
            ret = mid;
        }
    }
    return ret;
}

const double eps = 1e-6;
int sgn(double x)
{
    if (fabs(x) < eps)
    {
        return 0;
    }
    else
        return x < 0 ? -1 : 1;
}

struct Point
{
    double x, y;
    Point()
    {
    }
    Point(double x, double y) : x(x), y(y)
    {
    }
    Point operator+(Point B)
    {
        return Point(x + B.x, y + B.y);
    }
    Point operator-(Point B)
    {
        return Point(x - B.x, y - B.y);
    }
    bool operator==(Point B)
    {
        return sgn(x - B.x) == 0 && sgn(y - B.y) == 0;
    }
    bool operator<(Point B)
    {
        return sgn(x - B.x) < 0 || (sgn(x - B.x) == 0 && sgn(y - B.y) < 0);
    }
};
typedef Point Vector;
double Cross(Vector A, Vector B) // 叉积
{
    return A.x * B.y - A.y * B.x;
}
double Distance(Point A, Point B)
{
    return hypot(A.x - B.x, A.y - B.y);
}
int Convex_hull(Point *p, int n, Point *ch)
{
    n = unique(p, p + n) - p;
    sort(p, p + n);
    int v = 0;

    for (int i = 0; i < n; i++)
    {
        while (v > 1 && sgn(Cross(ch[v - 1] - ch[v - 2], p[i] - ch[v - 1])) <= 0)
        {
            v--;
        }
        ch[v++] = p[i];
    }

    int j = v;

    for (int i = n - 2; i >= 0; i--)
    {
        while (v > j && sgn(Cross(ch[v - 1] - ch[v - 2], p[i] - ch[v - 1])) <= 0)
        {
            v--;
        }
        ch[v++] = p[i];
    }
    if (n > 1)
    {
        v--;
    }
    return v;
}

int kmp(string s, string p)
{
    int ans = 0, lastt = -1;
    int lenp = p.size();
    vector<int> Next(lenp + 3, 0);
    rep(i, 1, lenp - 1)
    {
        int j = Next[i];
        while (j && p[j] != p[i])
        {
            j = Next[j];
        }
        if (p[j] == p[i])
        {
            Next[i + 1] = j + 1;
        }
        else
        {
            Next[i + 1] = 0;
        }
    }
    int lens = s.size();
    int j = 0;
    rep(i, 0, lens - 1)
    {
        while (j && s[i] != p[j])
        {
            j = Next[j];
        }
        if (s[i] == p[j])
        {
            j++;
        }
        if (j == lenp)
        {
            ans++;
        }
    }
    return ans;
}

int dir[4][2] =
    {
        {-1, 0}, {0, 1}, {1, 0}, {0, -1}}; // 左右上下
// int dir[8][2]={
//         {-1, 0}, {0, 1}, {1, 0}, {0, -1},{-1,-1},{-1,1},{1,-1},{1,1}
// };

#define endl '\n' // 交互题请删除本行
const ll inf = 1000000000000000000ll;
const ll mod1 = 998244353ll, P1 = 131, mod2 = 1e9 + 7ll, P2 = 13331;
ll inverse(ll x)
{
    return fastpow(x, mod1 - 2, mod1);
}

const int N = 1e6 + 10, M = 1e6 + 10;

///////////////////////////////////

int tt;
int n;
ll ge, hang, lie, mian;
int a[100][3][3], num[100];
bool vis[100];

///////////////////////////////////

void solve(int x)
{
    rep(i, 1, n)
    {
        if (vis[i])
        {
            continue;
        }
        rep(ii, 1, 2)
        {
            rep(jj, 1, 2)
            {
                if (a[x][ii][jj] == 0)
                {
                    a[i][ii][jj] ^= 1;
                }
            }
        }
    }
}

ll count(int i)
{
    ll ans = 0;
    num[i]=0;
    rep(ii, 1, 2)
    {
        rep(jj, 1, 2)
        {
            num[i] += a[i][ii][jj];
        }
    }
    if(num[i]==0)
    {
        ans+=min({4*ge,2*hang,2*lie,mian});
    }
    else if (num[i] == 1)
    {
        ans += min({3 * ge, lie + ge, hang + ge, mian + ge});
    }
    else if (num[i] == 2)
    {
        if (a[i][1][1] && a[i][2][1] || a[i][1][2] && a[i][2][2])
        {
            ans += min(2 * ge, lie);
        }
        else if (a[i][1][1] && a[i][1][2] || a[i][2][1] && a[i][2][2])
        {
            ans += min(2 * ge, hang);
        }
        else
        {
            ans += min(2 * ge, hang + lie);
        }
    }
    else if(num[i]==3)
    {
        ans += ge;
    }
    return ans;
}

///////////////////////////////////

void init()
{
    rep(i, 1, n)
    {
        num[i] = 0;
        vis[i]=0;
        rep(j, 1, 2)
        {
            rep(ii, 1, 2)
            {
                a[i][j][ii] = 0;
            }
        }
    }
}

///////////////////////////////////

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0); // 交互题请删除本行
  //  freopen("ain.txt", "r", stdin);
  //  freopen("aout.txt", "w", stdout);

    cin >> tt;
    cin >> ge >> hang >> lie >> mian;
    while (tt--)
    {
        ll ans = 0;
        cin >> n;
        init();
        rep(i, 1, n)
        {
            string s;
            cin >> s;
            if (s[0] == '1')
            {
                a[i][1][1] = 1;
                num[i]++;
            }
            if (s[1] == '1')
            {
                a[i][1][2] = 1;
                num[i]++;
            }
            cin >> s;
            if (s[0] == '1')
            {
                a[i][2][1] = 1;
                num[i]++;
            }
            if (s[1] == '1')
            {
                a[i][2][2] = 1;
                num[i]++;
            }
        }
        if (n == 1 && num[1] == 4)
        {
            cout << 2 * min({ge, hang, lie, mian}) << endl;
            continue;
        }
        rep(i, 1, n)//n ci
        {
            ll minn=1e9;
            int id=1;
            //
            //cout<<"lunci"<<i<<endl;
            rep(j,1,n)
            {
                if(vis[j])
                {
                    continue;
                }
                //
               // cout<<j<<" "<<count(j)<<endl;
                //
                if(count(j)<minn)
                {
                    if(i==1&&count(j)==0)
                    {
                        continue;
                    }
                    minn=count(j);
                    id=j;
                }
            }
            vis[id]=1;
            solve(id);
            
            ans+=minn;
            //
         //   cout<<id<<endl;
            // rep(j,1,n)
            // {
            //     rep(ii,1,2)
            //     {
            //         rep(jj,1,2)
            //         {
            //             cout<<a[j][ii][jj];
            //         }
            //         cout<<endl;
            //     }
            // }
        }
        cout << ans << endl;
    }

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3584kb

input:

2 1000 100 10 1
4
10
00

01
00

00
10

00
01
1
11
11

output:

1121
2

result:

ok 2 number(s): "1121 2"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3712kb

input:

2 1 1 1 1
4
10
00

01
00

00
10

00
01
1
11
11

output:

5
2

result:

ok 2 number(s): "5 2"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3584kb

input:

1 1000000 1000000 1000000 1000000
1
11
11

output:

2000000

result:

ok 1 number(s): "2000000"

Test #4:

score: -100
Wrong Answer
time: 22ms
memory: 3712kb

input:

10000 8 2 7 8
8
00
01

00
11

00
10

11
11

10
10

01
10

01
00

10
11
8
11
01

11
00

01
10

11
11

00
01

01
01

01
00

11
10
9
00
00

01
01

10
11

00
01

11
10

11
00

11
11

00
11

01
10
9
11
11

10
00

11
00

11
01

00
10

01
11

00
01

01
01

10
01
11
00
01

01
01

10
10

00
11

11
11

11
10
...

output:

34
32
36
36
40
38
42
38
40
42
36
44
34
37
39
34
29
39
40
40
38
41
46
38
31
40
37
38
34
35
32
42
34
38
42
40
46
34
39
36
29
38
40
40
45
39
44
38
38
40
42
29
43
42
36
42
46
40
41
40
42
40
37
33
34
40
41
37
42
40
36
41
29
34
34
38
36
39
38
38
36
38
35
42
36
34
42
42
38
38
40
40
40
42
44
29
36
40
38
36
...

result:

wrong answer 6th numbers differ - expected: '36', found: '38'