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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#850644#5034. >.<BINYU0 0ms0kbC++143.0kb2025-01-10 10:47:062025-01-10 10:47:12

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你现在查看的是最新测评结果

  • [2025-01-10 10:47:12]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2025-01-10 10:47:06]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pli pair <ll,int> 
const int N = 2e5;
int n,m,k,u,v,w,p,a[N + 5],cnt;
int id[2 * N + 5],fail[2 * N + 5];
int vis[2 * N + 5];
ll dis[2 * N + 5],ans; 
struct edge
{
	int v,w;
	bool operator < (const edge &y)const
	{
		return v < y.v;
	}
};
vector <edge> e[N + 5],now;
set <pair <int,int> > s;
map <int,int> mp[2 * N + 5];
queue <int> q;
struct Segment_Tree
{
	#define ls a[id].l
	#define rs a[id].r
	struct node
	{
		int l,r,val,id;
	}a[60 * N + 5];
	int cntnode;
	int update(int id,int l,int r,int x,int v,int w) 
	{
		a[++cntnode] = a[id];id = cntnode;
		if(l == r)
		{
			if(w != -1)a[id].val = w; 
			return a[id].id = v,id;
		}
		int mid = l + r >> 1;
		if(x <= mid)ls = update(ls,l,mid,x,v,w);
		else rs = update(rs,mid + 1,r,x,v,w);
		return id;
	}
	int query(int id,int l,int r,int x)
	{
		if(l == r)return a[id].id;
		int mid = l + r >> 1;
		if(x <= mid)return query(ls,l,mid,x);
		return query(rs,mid + 1,r,x);
	}
	int get(int id,int l,int r,int u,vector <edge> &ne)
	{
		if(!id)return 0;
		if(l == r)return ne.push_back({a[id].id,a[id].val}),0;
		int mid = l + r >> 1;
		ls = get(ls,l,mid,u,ne);
		rs = get(rs,mid + 1,r,u,ne);
		return 0;
	}
}st;
int rt[2 * N + 5];
void dij(int s)
{
	priority_queue <pli,vector <pli>,greater <pli> > q; 
	memset(dis,0x3f,sizeof(dis));
	dis[s] = 0;q.push({dis[s],s});
	while(!q.empty())
	{
		int u = q.top().second;q.pop();
		if(vis[u])continue;vis[u] = 1;
		now.clear();
		rt[u] = st.get(rt[u],1,n,u,now);
		for(auto v : now)
			if(!vis[v.v]&&dis[u] + v.w < dis[v.v])
				dis[v.v] = dis[u] + v.w,
				q.push({dis[v.v],v.v});
	}
}
int main()
{
	freopen("compete.in","r",stdin);
	freopen("compete.out","w",stdout);
	scanf("%d %d %d",&n,&m,&k);
	for(int i = 1;i <= m;i++)
		scanf("%d %d %d",&u,&v,&w),
		e[u].push_back({v,w}),
		s.insert({u,v});
	int Rt = n + 1;
	for(int i = 1;i <= n;i++)mp[Rt][i] = i,id[i] = i;
	cnt = Rt;
	while(k--)
	{
		scanf("%d",&p);
		for(int i = 1;i <= p;i++)scanf("%d",&a[i]);
		int f = 1;
		for(int i = 2;i <= p;i++)
			if(s.find({a[i - 1],a[i]}) == s.end())
				f = 0;
		if(!f)continue;
		int now = n + 1;
		for(int i = 1;i <= p;i++)
		{
			if(mp[now].find(a[i]) == mp[now].end())
				mp[now][a[i]] = ++cnt,id[cnt] = a[i];
			now = mp[now][a[i]];
		}
		vis[now] = 2;
	}
	for(int i = 1;i <= n;i++)
	{
		for(auto v : e[i])
			rt[i] = st.update(rt[i],1,n,v.v,v.v,v.w);
		fail[i] = Rt,q.push(i);
	}
	while(!q.empty())
	{
		int u = q.front();q.pop();
		if(u > n)rt[u] = rt[fail[u]];
		vis[u] |= vis[fail[u]];
		for(auto now : mp[u])
		{
			int v = now.first,nxt = now.second;
			rt[u] = st.update(rt[u],1,n,v,nxt,-1);
			if(u <= n)fail[nxt] = v;
			else fail[nxt] = st.query(rt[fail[u]],1,n,v);
			q.push(nxt);vis[nxt] |= vis[u];
		}
	}
	dij(1);ans = 1e18;
	for(int i = 1;i <= cnt;i++)
		if(vis[i] != 2&&id[i] == n)ans = min(ans,dis[i]);
	if(ans >= 1e18)puts("-1");
	else cout<<ans;
}

详细

Subtask #1:

score: 0
Dangerous Syscalls

Test #1:

score: 0
Dangerous Syscalls

input:

35 100 0
34 7 447733879
24 20 187005344
14 34 654502303
2 31 865194349
20 33 9517055
33 15 991889891
24 33 395599993
13 16 237525328
9 5 373850826
30 34 391470240
10 7 650077565
26 10 400825980
34 27 189924713
19 27 907609573
20 10 614945312
10 5 960007605
1 7 984076202
32 25 539699728
24 31 2553027...

output:


result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Dangerous Syscalls

Test #11:

score: 0
Dangerous Syscalls

input:

50000 200000 1
7542 37166 116613326
3581 43961 629220971
12873 42953 440313807
31744 5286 697832848
25882 12748 106667302
34760 29676 181570340
41570 9240 885513989
22227 35688 63657981
43180 29194 174058940
8977 41899 48262624
7465 18291 600002514
46925 9281 951474878
2115 31162 373758881
5386 3798...

output:


result:


Subtask #4:

score: 0
Skipped

Dependency #2:

0%