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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#850372#9521. Giving Directions in HarbinRafat_KabirAC ✓20ms3796kbC++204.0kb2025-01-10 04:33:382025-01-10 04:33:39

Judging History

你现在查看的是最新测评结果

  • [2025-01-10 04:33:39]
  • 评测
  • 测评结果:AC
  • 用时:20ms
  • 内存:3796kb
  • [2025-01-10 04:33:38]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#include <time.h>
#include <cstdlib>
#include <ctime>
#include <cstdio>
#include <cstring>

using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <iostream>

using namespace __gnu_pbds;
using namespace std;
template <class T>
using Tree =
    tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// to erase in multiset-> less_equal<T> and 
// s.erase(s.find_by_order(s.order_of_key(x)))
// lower_bound(x)=>(cannot use the stl lower_bound function)
// ll idx = s.order_of_key(x)
// if(idx == s.size()) -> no lower_bound
// else lb = *s.find_by_order(idx) // as 0-indexing
// idx-1 will give highest value which is strictly less than x
// for upper_bound->do the same with (x+1)

typedef long long ll;
typedef long double ld;
typedef pair<int,int> p32;
typedef pair<ll,ll> p64;
typedef tuple<ll, ll, ll> t64;
typedef vector<t64> vt64;
typedef vector<vt64> vvt64;
typedef pair<double,double> pdd;
typedef vector<ll> v64;
typedef vector<int> v32;
typedef vector<vector<int> > vv32;
typedef vector<vector<ll> > vv64;
typedef vector<vector<p64> > vvp64;
typedef vector<p64> vp64;
typedef vector<p32> vp32;
typedef vector<vector<p32> > vvp32;
typedef vector<bool> vb;
ll mod =  1e9+7, MOD = 998244353;
double eps = 1e-12;
#define FOR(s, e, i) for(ll i = s; i <= e; i++)
#define ROF(s ,e, i) for(ll i = s; i >= e; i--)
#define F0R(i, e) for(ll i = 0; i < (e); i++)
#define trav(e, a) for(auto &e : a)
#define coutAll(A) for(auto asdafas : A) cout <<  asdafas << " "; cout << "\n";
#define foutAll(A) for(auto asdafas : A) fout <<  asdafas << " "; cout << "\n";
#define cinAll(A) for(auto &asdafas : A) cin >>  asdafas;
#define finAll(A) for(auto &asdafas : A) fin >>  asdafas;
#define minpq priority_queue<ll, v64, greater<ll>>
#define maxpq priority_queue<ll> 
#define ln "\n"
#define dbg(x) cout<<#x<<" = "<<x<<ln
#define mp make_pair
#define mt make_tuple
#define pb push_back
#define fi first
#define se second
ll inf = LLONG_MAX;
#define fast_cin() ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(x) ((ll)(x).size())
#define yes cout<<"yes\n"
#define no cout<<"no\n"
#define Yes cout<<"Yes\n"
#define No cout<<"No\n"
#define YES cout<<"YES\n"
#define NO cout<<"NO\n"
using namespace std;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vector<ll>> vvll;
typedef pair<ll, ll> pll;
typedef pair<ll, ll> pii;
#define MAXN 100000000

void solve(int it)
{
    int n;
    cin >> n;
    string dir;
    v32 dist(n);
    FOR(0, n - 1, i){
        char c;
        int x;
        cin >> c >>x;
        dir += c;
        dist[i] = x;
    }
    vector<pair<char, int>>A;
    char f = dir[0];
    FOR(0, n - 1, i){
        char e = dir[i];
        if(f == e){
            // same direction
            // cout << "Yes\n";
            A.emplace_back('Z', dist[i]);
        }else{
            // change direction
            char nxt;
            if(f == 'S'){
                nxt = e == 'E' ? 'L' : 'R';
            }else if(f == 'N'){
                nxt = e != 'E' ? 'L' : 'R';                
            }else if(f == 'E'){
                nxt = e == 'N' ? 'L' : 'R';
            }else{
                nxt = e != 'N' ? 'L' : 'R';
            }
            A.emplace_back(nxt, -1);
            f = dir[i];
            --i;
        }
        // cout << i+1 << " " << f << "\n";            
    }
    cout << sz(A) << " " << dir[0] << "\n";
    trav(e, A){
        cout << e.fi;
        if(e.se != -1) cout << " " << e.se;
        cout << "\n";
    }
}


int main()
{
    // fast_cin();    
    ll t = 1;
    cin >> t;
    for(int it=1; it<=t; it++)
    {
        //cout << "Case " << it << ": ";
        solve(it);
    }
    return 0;
}

这程序好像有点Bug,我给组数据试试?

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3600kb

input:

1
2
S 2
E 1

output:

3 S
Z 2
L
Z 1

result:

ok ok (1 test case)

Test #2:

score: 0
Accepted
time: 1ms
memory: 3796kb

input:

99
4
E 6
N 1
W 2
S 8
8
W 10
N 1
E 10
S 2
E 2
N 2
W 2
S 1
9
N 5
E 4
N 7
E 6
S 9
E 8
N 4
W 6
N 7
6
N 6
E 6
N 8
W 9
S 7
E 2
8
E 6
S 9
W 5
S 4
W 6
N 4
E 5
N 9
8
N 6
W 10
N 6
W 6
S 6
E 6
S 6
E 10
10
N 7
W 3
N 5
W 5
S 8
W 10
N 6
E 9
N 8
E 8
8
W 9
N 10
E 6
S 10
E 9
S 10
W 6
N 10
4
W 5
N 1
E 5
S 1
4
W 4
S 8...

output:

7 E
Z 6
L
Z 1
L
Z 2
L
Z 8
15 W
Z 10
R
Z 1
R
Z 10
R
Z 2
L
Z 2
L
Z 2
L
Z 2
L
Z 1
17 N
Z 5
R
Z 4
L
Z 7
R
Z 6
R
Z 9
L
Z 8
L
Z 4
L
Z 6
R
Z 7
11 N
Z 6
R
Z 6
L
Z 8
L
Z 9
L
Z 7
L
Z 2
15 E
Z 6
R
Z 9
R
Z 5
L
Z 4
R
Z 6
R
Z 4
R
Z 5
L
Z 9
15 N
Z 6
L
Z 10
R
Z 6
L
Z 6
L
Z 6
L
Z 6
R
Z 6
L
Z 10
19 N
Z 7
L
Z 3
R
Z 5
...

result:

ok ok (99 test cases)

Test #3:

score: 0
Accepted
time: 20ms
memory: 3600kb

input:

10000
1
W 9
1
N 3
10
W 10
N 7
W 5
S 9
W 9
S 8
E 9
S 6
E 5
S 5
2
E 8
S 10
2
N 7
W 5
5
S 4
W 3
S 7
E 4
N 7
8
N 7
E 8
N 3
E 9
S 5
W 5
S 9
W 10
9
W 9
S 6
E 6
N 8
W 5
N 6
W 3
N 8
W 7
3
S 9
W 2
N 10
5
N 6
E 4
N 6
E 10
N 1
10
S 7
W 4
N 3
E 5
S 7
W 8
N 2
E 8
N 4
W 8
8
S 9
W 1
N 4
E 6
N 1
W 8
N 6
W 6
4
W 10
...

output:

1 W
Z 9
1 N
Z 3
19 W
Z 10
R
Z 7
L
Z 5
L
Z 9
R
Z 9
L
Z 8
L
Z 9
R
Z 6
L
Z 5
R
Z 5
3 E
Z 8
R
Z 10
3 N
Z 7
L
Z 5
9 S
Z 4
R
Z 3
L
Z 7
L
Z 4
L
Z 7
15 N
Z 7
R
Z 8
L
Z 3
R
Z 9
R
Z 5
R
Z 5
L
Z 9
R
Z 10
17 W
Z 9
L
Z 6
L
Z 6
L
Z 8
L
Z 5
R
Z 6
L
Z 3
R
Z 8
L
Z 7
5 S
Z 9
R
Z 2
R
Z 10
9 N
Z 6
R
Z 4
L
Z 6
R
Z 10
L
...

result:

ok ok (10000 test cases)

Extra Test:

score: 0
Extra Test Passed