#include <bits/stdc++.h>
#define pb push_back
#define x first
#define y second
using namespace std; bool MEM;
using ll=long long; using ld=long double;
using pii=pair<int,int>; using pll=pair<ll,ll>;
using lin=pair<pll,pll>;
const int I=1e9;
const ll J=1e18,N=2e5+7;
ll n,q,st[N],sz;
ld k[N];
pll a[N];
map<ll,ll> mp;
ll operator * (pll x,pll y) { return x.x*y.y-x.y*y.x; }
pll operator * (pll x,ll y) { return {x.x*y,x.y*y}; }
pll operator + (pll x,pll y) { return {x.x+y.x,x.y+y.y}; }
pll operator - (pll x,pll y) { return {x.x-y.x,x.y-y.y}; }
ld gk(pll x) { return x.x?(ld)x.y/(ld)x.x:J; }
ld len(pll x) { return sqrt((ld)x.x*x.x+x.y*x.y); }
ll chk(lin x,lin y) {
	pll xx=x.y-x.x,yy=y.y-y.x,zz=x.y-y.y;
	if (xx*yy==0) return yy*zz==0;
	ld t=(ld)(zz*yy)/(ld)(xx*yy);
	// printf(" (%lld,%lld)-(%lld,%lld) & (%lld,%lld)-(%lld,%lld)  %Lf\n",x.x.x,x.x.y,x.y.x,x.y.y,
	// y.x.x,y.x.y,y.y.x,y.y.y,t);
	return t<1?2:t==1?1:0;
}
ll solve(lin l) {
	if (l.x.x==l.y.x) return mp[l.x.x];
	ld lk=gk(l.y-l.x); ll ret=0;
	ll cl=upper_bound(k+st[0],k+st[1],lk)-k,cr=lower_bound(k+st[1],k+st[2],lk)-1-k;
	ll dl=upper_bound(k+st[1],k+st[2],lk)-k,dr=lower_bound(k+st[2],k+st[3],lk)-1-k;
	// printf("(%lld,%lld)-(%lld,%lld)\n",l.x.x,l.x.y,l.y.x,l.y.y);
	// printf("%lld %lld %lld %lld\n",cl,cr,dl,dr);
	if (cr+1<dl&&(a[dl]-a[cr+1])*(l.x-a[dl])==0) ret++;
	if (dr+1<cl+n&&(a[cl+n]-a[dr+1])*(l.x-a[cl+n])==0) ret++;
	while (cl<=cr) {
		ll mid=cl+cr>>1,w=chk({a[mid],a[mid+1]},l);
		if (w==1) { ret++; break; }
		else if (w==2) cl=mid+1;
		else cr=mid-1;
	}
	while (dl<=dr) {
		ll mid=dl+dr>>1,w=chk({a[mid],a[mid+1]},l);
		if (w==1) { ret++; break; }
		else if (w==2) dl=mid+1;
		else dr=mid-1;
	}
	// printf(" %lld\n",ret);
	return ret;
}
void mian() {
	scanf("%lld%lld",&n,&q);
	for (ll i=0;i<n;i++) scanf("%lld%lld",&a[i].x,&a[i].y),mp[a[i].x]++,a[n+i]=a[i];
	a[n*2]=a[0];
	for (ll i=0;i<n*2;i++) k[i]=gk(a[i+1]-a[i]);
	if (k[0]<k[n-1]) st[sz++]=0;
	for (ll i=1;i<n*2;i++) if (k[i]<k[i-1]) st[sz++]=i;
	// for (ll i=0;i<n*2;i++) printf("%.1Lf ",k[i]); printf("\n");
	// printf("%lld %lld %lld %lld\n",st[0],st[1],st[2],st[3]);
	for (ll opt;q--;) {
		scanf("%lld",&opt);
		pll s,t;
		if (opt==1) {
			scanf("%lld%lld",&s.x,&s.y);
			// ll ans=0;
			// for (ll i=0;i<n;i++) ans+=solve({s,a[i]})==2;
			// cout<<ans/2<<"\n";
			ll flg=1,ans=0;
			for (ll i=0;i<n;i++) if ((a[i+1]-a[i])*(s-a[i])<0) flg=0;
			if (flg) {
				// printf("114514\n");
				for (ll i=0,j=0;i<n;i++) {
					while ((a[(j+1)%n]-a[i])*(s-a[i])>=0&&i!=(j+1)%n) j=(j+1)%n;
					if (i!=j&&(a[j]-a[i])*(s-a[i])==0) ans++;
				}
				ans/=2;
			}
			else {
				ld d=J; ll p=0,pp;
				for (ll i=0;i<n;i++) {
					ld dd=len(a[i]-s);
					if (dd<d) d=dd,p=i;
				}
				for (pp=(p+1)%n;(a[p]-s)*(a[pp]-s)<0;pp=(pp+1)%n);
				if ((a[p]-s)*(a[pp]-s)==0) ans++;
				for (ll i=(p+1)%n,j=pp;;i=(i+1)%n) {
					while ((a[i]-s)*(a[j]-s)>0) j=(j+n-1)%n;
					if (i==j) break;
					if ((a[i]-s)*(a[j]-s)==0) ans++;
				}
				for (ll i=(p+n-1)%n,j=pp;;i=(i+n-1)%n) {
					while ((a[i]-s)*(a[j]-s)<0) j=(j+1)%n;
					if (i==j) break;
					if ((a[i]-s)*(a[j]-s)==0) ans++;
				}
			}
			cout<<ans<<"\n";
		}
		else {
			scanf("%lld%lld%lld%lld",&s.x,&s.y,&t.x,&t.y);
			cout<<solve({s,t})<<"\n";
		}
	}
}
bool ORY; int main() {
	// while (1)
	// int t; for (scanf("%d",&t);t--;)
	mian();
	cerr<<"\n"<<abs(&MEM-&ORY)/1048576<<"MB";
	return 0;
}