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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#84566 | #4511. Wonderland Chase | Booksnow | 0 | 1814ms | 22628kb | C++14 | 2.2kb | 2023-03-06 15:55:17 | 2023-03-06 15:55:21 |
Judging History
answer
#include <bits/stdc++.h>
#define st first
#define nd second
#define db double
#define re register
#define pb push_back
#define mk make_pair
//#define int long long
#define ldb long double
#define pii pair<int, int>
#define ull unsigned long long
#define mst(a, b) memset(a, b, sizeof(a))
using namespace std;
const int N = 1e5 + 10;
inline int read()
{
int s = 0, w = 1;
char ch = getchar();
while(ch < '0' || ch > '9') { if(ch == '-') w *= -1; ch = getchar(); }
while(ch >= '0' && ch <= '9') s = s * 10 + ch - '0', ch = getchar();
return s * w;
}
int T, n, m, A, Q, ans;
int st, ed, q[N], dir[N], dis[2][N];
bool vis[N], chk[N]; //是否是安全点
vector<int> G[N];
inline void BFS(int s, int op)
{
for(re int i = 1; i <= n; i++) dis[op][i] = -1;
dis[op][s] = 0, st = 1, ed = 0, q[++ed] = s;
while(st <= ed){
int u = q[st]; st++;
for(re int to : G[u])
if(dis[op][to] == -1) dis[op][to] = dis[op][u] + 1, q[++ed] = to;
}
}
inline void DFS(int u)
{
chk[u] = true;
if(G[u].size() == 1) ans = max(ans, dis[1][u]); //找到一个叶子然后不动
for(re int to : G[u])
if(to != Q && !chk[to] && !vis[to]) DFS(to);
}
inline void Sol(int Cas)
{
n = read(), m = read(), A = read(), Q = read();
if(Cas == 11) cout << n << " " << m << " " << A << " " << Q << "\n";
for(re int i = 1; i <= n; i++) G[i].clear(), vis[i] = true, chk[i] = false, dir[i] = 0;
for(re int i = 1, x, y; i <= m; i++){
x = read(), y = read(), G[x].pb(y), G[y].pb(x), dir[x]++, dir[y]++;
if(Cas == 1) cout << x << " " << y << "\n";
}
st = 1, ed = 0;
for(re int i = 1; i <= n; i++) if(dir[i] == 1) q[++ed] = i;
while(st <= ed){
int u = q[st];
st++, vis[u] = false;
for(re int to : G[u]){
if(!vis[to]) continue;
dir[to] -= 1;
if(dir[to] == 1) q[++ed] = to;
}
}
BFS(A, 0), BFS(Q, 1);
if(dis[0][Q] == -1) { printf("Case #%d: SAFE\n", Cas); return; } //不在一个联通块
for(re int i = 1; i <= n; i++)
if(vis[i] && dis[0][i] < dis[1][i]) { printf("Case #%d: SAFE\n", Cas); return; }
ans = 0, DFS(A);
//printf("Case #%d: %d\n", Cas, 2 * ans);
}
signed main()
{
T = read();
for(re int Cas = 1; Cas <= T; Cas++) Sol(Cas);
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 2ms
memory: 7348kb
input:
100 2 1 1 2 1 2 3 3 1 2 1 3 1 2 2 3 6 6 5 1 1 4 5 6 3 4 3 6 2 3 1 2 6 6 2 4 4 5 1 4 2 3 2 5 1 6 5 6 6 6 2 3 1 3 3 4 2 6 2 5 4 5 1 5 6 5 5 3 2 5 3 4 1 2 3 6 4 6 6 5 1 6 1 4 1 2 5 6 3 5 2 4 30 29 11 5 9 21 25 28 14 20 13 30 21 28 5 18 5 23 8 22 10 30 4 8 7 24 16 26 13 26 12 18 22 23 11 16 3 11 2 17 1 ...
output:
1 2 Case #2: SAFE Case #5: SAFE Case #6: SAFE Case #7: SAFE Case #8: SAFE Case #9: SAFE 5 4 5 2 Case #13: SAFE Case #26: SAFE Case #27: SAFE Case #28: SAFE Case #29: SAFE Case #30: SAFE Case #31: SAFE Case #32: SAFE Case #33: SAFE Case #34: SAFE Case #44: SAFE Case #45: SAFE Case #46: SAFE Case #53:...
result:
wrong answer 1st lines differ - expected: 'Case #1: 2', found: '1 2'
Test #2:
score: 0
Wrong Answer
time: 1814ms
memory: 22628kb
input:
100 100000 99999 32832 52005 67463 96972 10280 86580 12146 44520 41541 86634 46936 64223 22701 46291 9093 80967 52512 77386 51062 58931 2092 55026 2096 2384 85102 92986 39914 66949 33370 68952 41576 58836 27668 33997 5843 30705 44415 57721 15188 28706 23340 55082 20335 90872 16029 80328 4656 74633 8...
output:
67463 96972 10280 86580 12146 44520 41541 86634 46936 64223 22701 46291 9093 80967 52512 77386 51062 58931 2092 55026 2096 2384 85102 92986 39914 66949 33370 68952 41576 58836 27668 33997 5843 30705 44415 57721 15188 28706 23340 55082 20335 90872 16029 80328 4656 74633 87 62382 11677 89769 44507 917...
result:
wrong answer 1st lines differ - expected: 'Case #1: SAFE', found: '67463 96972'