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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#84420#5668. Cell Nuclei DetectionjeffqiRE 16ms97804kbC++142.3kb2023-03-06 14:49:112023-03-06 14:49:15

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-06 14:49:15]
  • 评测
  • 测评结果:RE
  • 用时:16ms
  • 内存:97804kb
  • [2023-03-06 14:49:11]
  • 提交

answer

#include<bits/stdc++.h>
#define rep(i,a,b) for (int i = (a); i <= (b); ++i)
#define drep(i,a,b) for (int i = (a); i >= (b); --i)
#define grep(i,u) for (int i = head[u],v = e[i].v; i; v = e[i = e[i].nxt].v)
#define LL long long
#define pii pair<int,int>
#define pll pair<LL,LL>
#define fi first
#define se second
#define eb emplace_back
#define mp make_pair
using namespace std;
LL read() {
	LL x = 0,y = 1; char ch = getchar(); while (!isdigit(ch)) {if (ch == '-') y = -y; ch = getchar();}
	while (isdigit(ch)) {x = x*10+ch-'0'; ch = getchar();} return x*y;
}
namespace qiqi {
	const int N = 1e7+5,M = 2005,INF = 0x3f3f3f3f; int n,m,s,t,ecnt,cur[N],head[N],dep[N];
	vector<int> p[M][M]; struct Data {int x0,y0,x1,y1;} a[N]; struct Edge {int v,f,nxt;} e[N];
	void add(int u,int v,int f) {e[++ecnt] = (Edge){v,f,head[u]}; head[u] = ecnt;}
	void f_add(int u,int v,int f) {add(u,v,f); add(v,u,0);}
	bool bfs(int s,int t) {
		rep(i,1,t) {cur[i] = head[i]; dep[i] = 0;}
		queue<int> q; dep[s] = 1; q.push(s);
		while (!q.empty()) {
			int u = q.front(); q.pop();
			grep(i,u) if (!dep[v] && e[i].f) {
				dep[v] = dep[u]+1; q.push(v);
			}
		}
		return dep[t] != 0;
	}
	int dfs(int u,int t,int f) {
		if (!f || u == t) return f; int res = 0,k;
		for (int &i = cur[u],v = e[i].v; i; v = e[i = e[i].nxt].v) {
			if (dep[v] == dep[u]+1 && (k = dfs(v,t,min(f,e[i].f)))) {
				res += k; f -= k; e[i].f -= k; e[i^1].f += k; if (!f) break;
			}
		}
		return res;
	}
	int Dinic(int s,int t) {int res = 0; while (bfs(s,t)) res += dfs(s,t,INF); return res;}
	void main() {
		n = read(); m = read(); s = n+m+1; t = s+1;
		ecnt = 1; rep(i,1,t) head[i] = 0;
		rep(i,1,n) {
			int x0 = read(),y0 = read(),x1 = read(),y1 = read();
			a[i] = (Data){x0,y0,x1,y1}; f_add(s,i,1);
			rep(j,x0,x1) rep(k,y0,y1) p[j][k].eb(i);
		}
		rep(i,n+1,n+m) {
			int x0 = read(),y0 = read(),x1 = read(),y1 = read(); f_add(i,t,1);
			rep(x,x0,x1) rep(y,y0,y1) for (auto j:p[x][y]) {
				if ((min(x1,a[j].x1)-max(x0,a[j].x0)+1)*(min(y1,a[j].y1)-max(y0,a[j].y0)+1)*2 >= (a[j].x1-a[j].x0+1)*(a[j].y1-a[j].y0+1)) f_add(j,i,1);
			}
		}
		rep(i,1,n) rep(j,a[i].x0,a[i].x1) rep(k,a[i].y0,a[i].y1) p[j][k].clear();
		printf("%d\n",Dinic(s,t));
	}
}
int main() {
	int T = read(); while (T--) qiqi::main(); return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 16ms
memory: 97804kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 15ms
memory: 97728kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #3:

score: -100
Runtime Error

input:

5
50000 50000
0 0 4 4
4 0 8 4
8 0 12 4
12 0 16 4
16 0 20 4
20 0 24 4
24 0 28 4
28 0 32 4
32 0 36 4
36 0 40 4
40 0 44 4
44 0 48 4
48 0 52 4
52 0 56 4
56 0 60 4
60 0 64 4
64 0 68 4
68 0 72 4
72 0 76 4
76 0 80 4
80 0 84 4
84 0 88 4
88 0 92 4
92 0 96 4
96 0 100 4
100 0 104 4
104 0 108 4
108 0 112 4
112 ...

output:


result: