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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#84242#5666. Repetitive ElementsrniyaAC ✓3ms3468kbC++175.0kb2023-03-06 03:10:442023-03-06 03:10:45

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-03-06 03:10:45]
  • 评测
  • 测评结果:AC
  • 用时:3ms
  • 内存:3468kb
  • [2023-03-06 03:10:44]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define ALL(x) (x).begin(), (x).end()
#ifdef LOCAL
#include "debug.hpp"
#else
#define debug(...) void(0)
#endif

template <typename T> istream& operator>>(istream& is, vector<T>& v) {
    for (T& x : v) is >> x;
    return is;
}
template <typename T> ostream& operator<<(ostream& os, const vector<T>& v) {
    for (size_t i = 0; i < v.size(); i++) {
        os << v[i] << (i + 1 == v.size() ? "" : " ");
    }
    return os;
}

template <typename T> T gcd(T x, T y) { return y != 0 ? gcd(y, x % y) : x; }
template <typename T> T lcm(T x, T y) { return x / gcd(x, y) * y; }

int topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }
int topbit(long long t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }
int botbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }
int botbit(long long a) { return a == 0 ? 64 : __builtin_ctzll(a); }
int popcount(signed t) { return __builtin_popcount(t); }
int popcount(long long t) { return __builtin_popcountll(t); }
bool ispow2(int i) { return i && (i & -i) == i; }
long long MSK(int n) { return (1LL << n) - 1; }

template <class T> T ceil(T x, T y) {
    assert(y >= 1);
    return (x > 0 ? (x + y - 1) / y : x / y);
}
template <class T> T floor(T x, T y) {
    assert(y >= 1);
    return (x > 0 ? x / y : (x - y + 1) / y);
}

template <class T1, class T2> inline bool chmin(T1& a, T2 b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template <class T1, class T2> inline bool chmax(T1& a, T2 b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template <typename T> void mkuni(vector<T>& v) {
    sort(v.begin(), v.end());
    v.erase(unique(v.begin(), v.end()), v.end());
}
template <typename T> int lwb(const vector<T>& v, const T& x) { return lower_bound(v.begin(), v.end(), x) - v.begin(); }

const int INF = (1 << 30) - 1;
const long long IINF = (1LL << 60) - 1;
const int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};
const int MOD = 998244353;
// const int MOD = 1000000007;

#include <cassert>
#include <chrono>
#include <random>
#include <string>
#include <vector>

struct RollingHash {
    static inline uint64_t generate_base() {
        std::mt19937_64 mt(std::chrono::steady_clock::now().time_since_epoch().count());
        std::uniform_int_distribution<uint64_t> rand(2, RollingHash::mod - 1);
        return rand(mt);
    }

    RollingHash(uint64_t base = generate_base()) : base(base), power{1} {}

    template <typename T> std::vector<uint64_t> build(const T& s) const {
        int n = s.size();
        std::vector<uint64_t> hash(n + 1);
        hash[0] = 0;
        for (int i = 0; i < n; i++) hash[i + 1] = add(mul(hash[i], base), s[i]);
        return hash;
    }

    template <typename T> uint64_t get(const T& s) const {
        uint64_t res = 0;
        for (const auto& x : s) res = add(mul(res, base), x);
        return res;
    }

    uint64_t query(const std::vector<uint64_t>& hash, int l, int r) {
        assert(0 <= l && l <= r);
        extend(r - l);
        return add(hash[r], mod - mul(hash[l], power[r - l]));
    }

    uint64_t combine(uint64_t h1, uint64_t h2, size_t h2_len) {
        extend(h2_len);
        return add(mul(h1, power[h2_len]), h2);
    }

    int lcp(const std::vector<uint64_t>& a, int l1, int r1, const std::vector<uint64_t>& b, int l2, int r2) {
        int len = std::min(r1 - l1, r2 - l2);
        int lb = 0, ub = len + 1;
        while (ub - lb > 1) {
            int mid = (lb + ub) >> 1;
            (query(a, l1, l1 + mid) == query(b, l2, l2 + mid) ? lb : ub) = mid;
        }
        return lb;
    }

private:
    static constexpr uint64_t mod = (1ULL << 61) - 1;
    const uint64_t base;
    std::vector<uint64_t> power;

    static inline uint64_t add(uint64_t a, uint64_t b) {
        if ((a += b) >= mod) a -= mod;
        return a;
    }

    static inline uint64_t mul(uint64_t a, uint64_t b) {
        __uint128_t c = (__uint128_t)a * b;
        return add(c >> 61, c & mod);
    }

    inline void extend(size_t len) {
        if (power.size() > len) return;
        size_t pre = power.size();
        power.resize(len + 1);
        for (size_t i = pre - 1; i < len; i++) power[i + 1] = mul(power[i], base);
    }
};

void solve() {
    string S;
    cin >> S;

    int n = S.size();
    RollingHash rh;
    auto hash = rh.build(S);
    int L = -1, LEN = 0;
    for (int len = 1; len <= n; len++) {
        map<uint64_t, int> mp;
        for (int i = 0; i + len <= n; i++) {
            if (i - len >= 0) mp[rh.query(hash, i - len, i)] = i - len;
            auto x = rh.query(hash, i, i + len);
            if (mp.count(x) and (LEN < len or mp[x] < L)) L = mp[x], LEN = len;
        }
    }
    string ans = S.substr(L, LEN);

    cout << ans << '\n';
}

int main() {
    cin.tie(0);
    ios::sync_with_stdio(false);
    int T;
    cin >> T;
    for (; T--;) solve();
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 3376kb

input:

5
TATCGATCGAGTTGT
TCCGCGAGCGAGTCTCTCCATT
GTTTCATCATACGAGGCCCCATACGCGCTGG
AGATGGGATCCTTATG
GCCCTTAGGCATGGGATGTCGTTTCTTG

output:

ATCG
GCGA
CATACG
GAT
CTT

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 3ms
memory: 3468kb

input:

50
TTGACAACTTCAGGTTGGCACTCCTTCATTTGGATTTCGGAATAATAGTTTTCTGCTCTGCC
ATCCTATTCGGGGATAGGAGAGATGGGTTGCCGCTATAAAAGCATTTGAACTCCATTTCACTCCGTTGGCTAGGGGTCGCACTG
CCGTAATATAAAGACTCGGAATTCCAATAGCTGCTATTTGCGAGTATGTGACTGAAAACACACCTATAAATATTAGCTGCGTACAAGCTA
ATGGCTGCATGCAGGGTCGACTAGACACACTTTGTCT
TTGAGGATGTCGACGTGTCT...

output:

CTTCA
CATTT
TAGCTGC
TGCA
ACGTG
GCGCCGG
CTCTT
AGTAT
AGAG
ACAG
TAT
TGAC
CTTG
CGTC
TACTGG
GCCGGT
GAA
CAGTA
GCGT
GGTT
CCCT
GAG
TAGAC
GGTGC
GCAGT
TGAG
ATCAA
CCACACA
GAGTC
ATGTA
ATGGTA
TATA
TATGAA
TTCC
CATACG
TACCA
TTAG
GGAATGT
CAGG
GCT
AAG
CTGT
GGAT
TCTTC
AAAAC
ATG
GATAA
TTA
ACATAT
CAAT

result:

ok 50 lines