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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#84058 | #5668. Cell Nuclei Detection | skittles1412 | AC ✓ | 509ms | 181316kb | C++17 | 3.8kb | 2023-03-05 08:34:15 | 2023-03-05 08:34:21 |
Judging History
answer
#include "bits/extc++.h"
using namespace std;
template <typename T>
void dbgh(const T& t) {
cerr << t << endl;
}
template <typename T, typename... U>
void dbgh(const T& t, const U&... u) {
cerr << t << " | ";
dbgh(u...);
}
#ifdef DEBUG
#define dbg(...) \
cerr << "L" << __LINE__ << " [" << #__VA_ARGS__ << "]" \
<< ": "; \
dbgh(__VA_ARGS__)
#else
#define cerr \
if (false) \
cerr
#define dbg(...)
#endif
#define endl "\n"
#define long int64_t
#define sz(x) int(std::size(x))
namespace kactl {
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
using ll = long;
using pii = pair<int, int>;
using vi = vector<int>;
struct Dinic {
struct Edge {
int to, rev;
ll c, oc;
ll flow() { return max(oc - c, long(0)); } // if you need flows
};
vi lvl, ptr, q;
vector<vector<Edge>> adj;
Dinic(int n) : lvl(n), ptr(n), q(n), adj(n) {}
void addEdge(int a, int b, ll c, ll rcap = 0) {
adj[a].push_back({b, sz(adj[b]), c, c});
adj[b].push_back({a, sz(adj[a]) - 1, rcap, rcap});
}
ll dfs(int v, int t, ll f) {
if (v == t || !f) return f;
for (int& i = ptr[v]; i < sz(adj[v]); i++) {
Edge& e = adj[v][i];
if (lvl[e.to] == lvl[v] + 1)
if (ll p = dfs(e.to, t, min(f, e.c))) {
e.c -= p, adj[e.to][e.rev].c += p;
return p;
}
}
return 0;
}
ll calc(int s, int t) {
ll flow = 0; q[0] = s;
rep(L,0,31) do { // 'int L=30' maybe faster for random data
lvl = ptr = vi(sz(q));
int qi = 0, qe = lvl[s] = 1;
while (qi < qe && !lvl[t]) {
int v = q[qi++];
for (Edge e : adj[v])
if (!lvl[e.to] && e.c >> (30 - L))
q[qe++] = e.to, lvl[e.to] = lvl[v] + 1;
}
while (ll p = dfs(s, t, LLONG_MAX)) flow += p;
} while (lvl[t]);
return flow;
}
bool leftOfMinCut(int a) { return lvl[a] != 0; }
};
#undef rep
#undef all
} // namespace kactl
constexpr int maxa = 2005;
vector<array<int, 3>> arr[maxa][maxa];
void solve() {
for (auto& a : arr) {
for (auto& b : a) {
b.clear();
}
}
int n, q;
cin >> q >> n;
int queries[q][4];
for (auto& [x1, y1, x2, y2] : queries) {
cin >> x1 >> y1 >> x2 >> y2;
}
for (int i = 0; i < n; i++) {
int x1, y1, x2, y2;
cin >> x1 >> y1 >> x2 >> y2;
arr[x1][y1].push_back({x2, y2, i});
}
kactl::Dinic solver(n + q + 2);
int src = n + q, sink = src + 1;
for (int i = 0; i < n; i++) {
solver.addEdge(src, i, 1);
}
for (int i = 0; i < q; i++) {
solver.addEdge(n + i, sink, 1);
}
for (int i = 0; i < q; i++) {
auto& [x1, y1, x2, y2] = queries[i];
for (int x = max(x1 - 3, 0); x < x2; x++) {
for (int y = max(y1 - 3, 0); y < y2; y++) {
for (auto& [x3, y3, j] : arr[x][y]) {
int cx = min(x3, x2) - max(x, x1),
cy = min(y3, y2) - max(y, y1);
if (cx >= 0 && cy >= 0 &&
cx * cy * 2 >= (x2 - x1) * (y2 - y1)) {
solver.addEdge(j, n + i, 1);
}
}
}
}
}
cout << solver.calc(src, sink) << endl;
}
int main() {
cin.tie(nullptr);
cin.exceptions(ios::failbit);
ios_base::sync_with_stdio(false);
int tcs;
cin >> tcs;
while (tcs--) {
solve();
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 39ms
memory: 97652kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 42ms
memory: 97596kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 456ms
memory: 149848kb
input:
5 50000 50000 0 0 4 4 4 0 8 4 8 0 12 4 12 0 16 4 16 0 20 4 20 0 24 4 24 0 28 4 28 0 32 4 32 0 36 4 36 0 40 4 40 0 44 4 44 0 48 4 48 0 52 4 52 0 56 4 56 0 60 4 60 0 64 4 64 0 68 4 68 0 72 4 72 0 76 4 76 0 80 4 80 0 84 4 84 0 88 4 88 0 92 4 92 0 96 4 96 0 100 4 100 0 104 4 104 0 108 4 108 0 112 4 112 ...
output:
50000 50000 0 50000 3150
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 366ms
memory: 181316kb
input:
5 50000 50000 0 0 1 1 1 0 2 1 2 0 3 1 3 0 4 1 4 0 5 1 5 0 6 1 6 0 7 1 7 0 8 1 8 0 9 1 9 0 10 1 10 0 11 1 11 0 12 1 12 0 13 1 13 0 14 1 14 0 15 1 15 0 16 1 16 0 17 1 17 0 18 1 18 0 19 1 19 0 20 1 20 0 21 1 21 0 22 1 22 0 23 1 23 0 24 1 24 0 25 1 25 0 26 1 26 0 27 1 27 0 28 1 28 0 29 1 29 0 30 1 30 0 ...
output:
50000 25050 12500 16000 8000
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 337ms
memory: 111572kb
input:
5 50000 50000 0 0 2 4 4 0 7 1 8 0 10 1 12 0 15 3 16 0 19 1 20 0 22 2 24 0 26 4 28 0 30 4 32 0 36 3 36 0 40 1 40 0 44 1 44 0 47 2 48 0 49 3 52 0 54 1 56 0 59 4 60 0 64 3 64 0 68 3 68 0 70 1 72 0 76 4 76 0 80 3 80 0 84 4 84 0 87 2 88 0 90 1 92 0 94 4 96 0 98 1 100 0 104 1 104 0 107 2 108 0 110 4 112 0...
output:
10594 10779 10618 10381 10779
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 509ms
memory: 145768kb
input:
5 50000 50000 0 0 4 4 1 0 5 4 2 0 6 4 3 0 7 4 4 0 8 4 5 0 9 4 6 0 10 4 7 0 11 4 8 0 12 4 9 0 13 4 10 0 14 4 11 0 15 4 12 0 16 4 13 0 17 4 14 0 18 4 15 0 19 4 16 0 20 4 17 0 21 4 18 0 22 4 19 0 23 4 20 0 24 4 21 0 25 4 22 0 26 4 23 0 27 4 24 0 28 4 25 0 29 4 26 0 30 4 27 0 31 4 28 0 32 4 29 0 33 4 30...
output:
50000 50000 50000 50000 49600
result:
ok 5 lines
Test #7:
score: 0
Accepted
time: 23ms
memory: 97656kb
input:
1 4 4 1 1 3 3 2 1 4 3 1 2 3 4 2 2 4 4 2 1 4 3 3 2 5 4 1 2 3 4 2 3 4 5
output:
3
result:
ok single line: '3'