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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#840314 | #8712. Flooding Wall | zhassyn# | 0 | 2ms | 9732kb | C++20 | 4.6kb | 2025-01-02 17:02:30 | 2025-01-02 17:02:37 |
Judging History
answer
#include <bits/stdc++.h>
#define pb push_back
#define pf push_front
using namespace std;
#define F first
#define S second
typedef long long ll;
#define pii pair <int, int>
#define pll pair <ll, ll>
typedef long double ld;
const ll N = 2 * 1e5 + 100, M = 4096 + 10, len = 315, inf = 1e18;
const ll mod = 1e9 + 7;
ll um(ll a, ll b){
return (1LL * a * b) % mod;
}
ll subr(ll a, ll b){
return ((1LL * a - b) % mod + mod) % mod;
}
ll a[N], b[N], num[N], n, p[N];
void subtask1(){
ll ans = 0;
for(ll mask = 0; mask < (1 << n); mask++){
for(ll dig = 0; dig < n; dig++){
if((mask & (1 << dig)) > 0) num[dig] = a[dig];
else num[dig] = b[dig];
}
vector <pll> vec;
// for(ll i = 0; i < n; i++){
// cout << num[i] << " ";
// }
// cout << endl;
for(ll i = 0; i < n; i++){
ll res = 0, last = -1, cnt = 0;
while((ll)vec.size() != 0){
pll v = vec.back();
if(v.F <= num[i]){
cnt += v.S;
last = v.F;
res += um(num[i] - v.F, v.S);
vec.pop_back();
} else break;
}
if((ll)vec.size() != 0) ans += res;
else ans = ans + subr(res, um(cnt, num[i] - last));
ans %= mod;
vec.pb({num[i], cnt + 1});
}
//cout << ans << " HERE\n";
}
cout << ans;
}
// pll sf[N], pr[N];
// ll ls[N], rs[N], fen[N], was[N];
// bool wb[N];
// void upd(ll i, ll delta){
// for(; i < N; i = (i | (i+ 1))){
// fen[i] += delta;
// }
// }
// ll get(ll r){
// ll res = 0;
// for(; r >= 0; r = (r & (r + 1)) - 1){
// res += fen[r];
// }
// return res;
// }
// void subtask2(){
// ll ans = 0;
// for(ll i = 0; i < n; i++){
// //cout << i << " INDEX\n";
// set <pll> mn;
// // This shit is not for me
// for(ll j = 1; j <= 1000; j++){
// was[j] = 0;
// wb[j] = 0;
// }
// for(ll j = i + 1; j < n; j++){
// mn.insert({-b[j], j});
// upd(a[j], 1);
// }
// for(ll j = i + 1; j < n; j++){
// mn.erase({-b[j], j});
// upd(a[j], -1);
// ll mini = 0;
// if((int)mn.size() != 0) mini = -mn.begin()->F;
// if(mini > a[j]) sf[j].F = 0;
// else sf[j].F = p[get(a[j]) - was[a[j]]];
//
// if(mini > b[j] || wb[b[j]]) sf[j].S = 0;
// else sf[j].S = p[get(b[j]) - was[b[j]]];
// //cout << sf[j].F << " "<< sf[j].S << endl;
// upd(a[j], 1);
// was[a[j]]++;
// wb[b[j]] = 1;
// mn.insert({-b[j], j});
// }
// for(ll j = i + 1; j < n; j++){
// rs[a[j]] += sf[j].F;
// rs[a[j]] %= mod;
// rs[b[j]] += sf[j].S;
// rs[b[j]] %= mod;
//
// upd(a[j], -1);
// }
//
// mn.clear();
// // bless you/ work please
// for(ll j = 1; j <= 1000; j++){
// was[j] = 0;
// wb[j] = 0;
// }
// for(ll j = i - 1; j >= 0; j--){
// mn.insert({-b[j], j});
// upd(a[j], 1);
// }
// for(ll j = i - 1; j >= 0; j--){
// mn.erase({-b[j], j});
// upd(a[j], -1);
// ll mini = 0;
// if((int)mn.size() != 0) mini = -mn.begin()->F;
// if(mini > a[j]) pr[j].F = 0;
// else pr[j].F = p[get(a[j]) - was[a[j]]];
//
// if(mini > b[j] || wb[b[j]]) pr[j].S = 0;
// else pr[j].S = p[get(b[j]) - was[b[j]]];
// //cout << pr[j].F << " "<< pr[j].S << endl;
// upd(a[j], 1);
// was[a[j]]++;
// wb[b[j]] = true;
// mn.insert({-b[j], j});
// }
// for(ll j = i - 1; j >= 0; j--){
// ls[a[j]] += pr[j].F;
// ls[a[j]] %= mod;
// ls[b[j]] += pr[j].S;
// ls[b[j]] %= mod;
//
// upd(a[j], -1);
// }
// for(ll j = 1; j <= 1000; j++){
// for(ll k = 1; k <= 1000; k++){
// if(a[i] < min(k, j)) ans += um(min(k, j) - a[i], um(rs[j], ls[k]));
// if(b[i] < min(k, j)) ans += um(min(k, j) - b[i], um(rs[j], ls[k]));
// ans %= mod;
// }
// }
// for(ll j = 1; j <= 1000; j++){
// rs[j] = ls[j] = 0;
// }
// //cout << ans << " RESULT\n";
// }
// cout << ans;
// }
ll pref[N];
void subtask5(){
ll cnt = 0, sm = 1, ans = 0;
for(ll i = 1; i <= n; i++){
cnt++;
pref[i] = pref[i - 1] + um(cnt, sm);
pref[i] %= mod;
sm = um(sm, 2LL);
//cout << pref[i] << " ";
}
//cout << endl;
for(ll i = 1; i < n; i++){
ans += pref[n - i - 1];
ans %= mod;
}
cout << ans;
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
cin >> n;
p[0] = 1;
ll mx = 0;
for(ll i = 1; i <= n; i++){
p[i] = um(p[i - 1], 2LL);
}
for(ll i = 0; i < n; i++){
cin >> a[i];
}
for(ll i = 0; i < n; i++){
cin >> b[i];
if(b[i] > a[i]) swap(a[i], b[i]);
mx = max(mx, a[i]);
}
// if(n <= 20){
// subtask1();
// return 0;
// }
if(mx <= 2){
subtask5();
return 0;
}
//subtask2();
return 0;
}
詳細信息
Subtask #1:
score: 0
Wrong Answer
Test #1:
score: 8
Accepted
time: 2ms
memory: 9728kb
input:
4 1 1 1 1 2 2 2 2
output:
6
result:
ok single line: '6'
Test #2:
score: 0
Wrong Answer
time: 1ms
memory: 9668kb
input:
10 1 2 3 4 5 6 7 8 9 10 10 9 8 7 6 5 4 3 2 1
output:
result:
wrong answer 1st lines differ - expected: '21116', found: ''
Subtask #2:
score: 0
Wrong Answer
Test #23:
score: 0
Wrong Answer
time: 0ms
memory: 9732kb
input:
100 948 425 211 688 416 81 356 602 712 954 117 522 797 75 281 491 662 669 78 156 939 526 929 937 916 619 166 777 48 898 449 278 298 714 668 755 679 38 389 602 195 135 672 833 655 541 473 27 596 274 351 353 598 993 837 246 950 99 179 751 481 843 550 195 964 279 806 82 330 599 124 756 649 838 513 625 ...
output:
result:
wrong answer 1st lines differ - expected: '164439470', found: ''
Subtask #3:
score: 0
Skipped
Dependency #2:
0%
Subtask #4:
score: 0
Skipped
Dependency #1:
0%
Subtask #5:
score: 0
Runtime Error
Test #57:
score: 0
Runtime Error
input:
500000 1 1 1 1 2 2 2 1 1 1 1 1 2 2 1 1 2 2 2 2 1 2 1 1 2 1 1 1 1 2 1 2 2 1 1 2 2 2 1 1 2 2 2 2 1 2 2 2 2 1 2 2 2 1 2 2 2 1 2 2 2 2 2 2 2 2 1 1 2 1 2 1 2 2 1 2 2 2 2 2 2 2 1 1 1 2 2 2 1 1 2 1 2 2 1 2 2 1 2 2 2 1 2 2 2 2 2 2 2 2 1 1 1 2 1 2 1 1 2 1 2 1 2 2 1 1 2 1 1 1 1 1 2 2 2 2 2 2 1 2 2 1 1 2 1 2 1...
output:
result:
Subtask #6:
score: 0
Skipped
Dependency #1:
0%