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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#835837 | #9926. Flipping Paths | ucup-team055# | RE | 0ms | 3624kb | C++20 | 4.1kb | 2024-12-28 14:58:40 | 2024-12-28 14:58:44 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using ll=long long;
using ld=long double;
const ll ILL=2167167167167167167;
const int INF=2100000000;
#define rep(i,a,b) for (int i=(int)(a);i<(int)(b);i++)
#define all(p) p.begin(),p.end()
template<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;
template<class T> ll LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> ll UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}
template<class T> bool chmin(T &a,T b){if(b<a){a=b;return 1;}else return 0;}
template<class T> bool chmax(T &a,T b){if(a<b){a=b;return 1;}else return 0;}
template<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}
template<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}
bool yneos(bool a,bool upp=0){if(a){cout<<(upp?"YES\n":"Yes\n");}else{cout<<(upp?"NO\n":"No\n");}return a;}
template<class T> void vec_out(vector<T> &p,int ty=0){
if(ty==2){cout<<'{';for(int i=0;i<(int)p.size();i++){if(i){cout<<",";}cout<<'"'<<p[i]<<'"';}cout<<"}\n";}
else{if(ty==1){cout<<p.size()<<"\n";}for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout<<p[i];}cout<<"\n";}}
template<class T> T vec_min(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;}
template<class T> T vec_max(vector<T> &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;}
template<class T> T vec_sum(vector<T> &a){T ans=T(0);for(auto &x:a) ans+=x;return ans;}
int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;}
void solve();
// CITRUS CURIO CITY / FREDERIC
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int t = 1;
cin >> t;
rep(i, 0, t) solve();
}
void solve(){
int N, M;
cin >> N >> M;
vector p(N, vector<int>(M));
vector A(2, vector<int>(N + M - 1));
rep(i, 0, N) rep(j, 0, M){
char c;
cin >> c;
if (c == 'B') p[i][j]++;
A[p[i][j]][i + j] ^= 1;
}
// fin is all 0
int ok = 0;
rep(i, 0, 2){
if (vec_min(A[i]) == vec_max(A[i])){
if (i == 0){
rep(a, 0, N) rep(j, 0, M) p[a][j] ^= 1;
}
ok = 1;
break;
}
}
if (ok == 0){
cout << "NO\n";
return;
}
vector<string> ans;
int x = 0, y = 0;
string tmp;
p[x][y] ^= 1;
auto addx = [&](int a = 1) -> void {
x++;
p[x][y] ^= a;
tmp += 'D';
};
auto addy = [&](int a = 1) -> void {
y++;
p[x][y] ^= a;
tmp += 'R';
};
auto pus = [&]() -> void {
ans.push_back(tmp);
tmp = "";
};
string base;
while (x != N - 1 || y != M - 1){
if (x == N - 1) addy(0);
else if (y == M - 1) addx(0);
else if (x == y) addy(0);
else addx(0);
}
base = tmp;
tmp = "";
// diff = x - y
for (int diff = N - 1; diff > 0; diff--){
x = 0, y = 0;
while (x != N - 1 || y != M - 1){
if (x == N - 1) addy();
else if (y == M - 1) addx();
else if (x - y == diff) addy();
else if (x - y < diff - 1) addx();
else if (p[x + 1][y] == 1) addx();
else addy();
}
pus();
}
for (int diff = 1 - M; diff < -1; diff++){
x = 0, y = 0;
while (x != N - 1 || y != M - 1){
if (x == N - 1) addy();
else if (y == M - 1) addx();
else if (x - y == diff) addx();
else if (x - y > diff + 1) addy();
else if (p[x + 1][y] == 1) addy();
else addx();
}
pus();
}
if (p[0][0]){
ans.push_back(base);
x = 0, y = 0;
p[0][0] ^= 1;
for (auto c : base){
if (c == 'D') x++;
else y++;
p[x][y] ^= 1;
}
}
cout << "YES\n";
cout << ans.size() << "\n";
for (auto z : ans) cout << z << "\n";
rep(i, 0, N) rep(j, 0, M) assert(p[i][j] == 0);
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3624kb
input:
4 3 3 WBB BWB BBW 1 5 WWWWW 2 2 BB BB 4 1 W B B W
output:
YES 4 DDRR RDRD RRDD RDRD YES 3 RRRR RRRR RRRR YES 2 RD RD NO
result:
ok ok (4 test cases)
Test #2:
score: -100
Runtime Error
input:
323 1 2 BB 1 2 BW 1 2 WB 1 2 WW 2 1 B B 2 1 B W 2 1 W B 2 1 W W 1 3 BBB 1 3 BBW 1 3 BWB 1 3 BWW 1 3 WBB 1 3 WBW 1 3 WWB 1 3 WWW 2 2 BB BB 2 2 BB BW 2 2 BB WB 2 2 BB WW 2 2 BW BB 2 2 BW BW 2 2 BW WB 2 2 BW WW 2 2 WB BB 2 2 WB BW 2 2 WB WB 2 2 WB WW 2 2 WW BB 2 2 WW BW 2 2 WW WB 2 2 WW WW 3 1 B B B 3 ...