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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#828851#9573. Social MediaweizhiyonghuWA 31ms13136kbC++142.0kb2024-12-23 21:20:572024-12-23 21:20:57

Judging History

你现在查看的是最新测评结果

  • [2024-12-23 21:20:57]
  • 评测
  • 测评结果:WA
  • 用时:31ms
  • 内存:13136kb
  • [2024-12-23 21:20:57]
  • 提交

answer

#include <bits/stdc++.h>
#define ll long long

using namespace std;
const int N = 2e5 + 10;
int cnt1[N];
map<int, int> cnt2[N];

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    int tc;
    cin >> tc;
    while (tc--) {
        int n, k, m, ans = 0;
        cin >> k >> m >> n;
        for (int i = 1; i <= n; i++) cnt1[i] = 0, cnt2[i].clear();
        map<int, bool> mp;
        for (int i = 1; i <= k; i++) {
            int x;
            cin >> x;
            mp[x] = true;
        }
        for (int i = 1; i <= m; i++) {
            int u, v;
            cin >> u >> v;
            if (mp.count(u) && mp.count(v))
                ans++;
            else if (mp.count(u) && (mp.count(v) == 0))
                cnt1[v]++;
            else if (mp.count(v) && (mp.count(u) == 0))
                cnt1[u]++;
            else if (mp.count(u) == 0 && u == v)
                cnt1[u]++;
            else if (u != v && mp.count(u) == 0 && mp.count(v) == 0)
                cnt2[u][v]++, cnt2[v][u]++;
        }
        int mx1 = 0, mx2 = 0, p1 = -1, p2 = -1;
        for (int i = 1; i <= n; i++)
            if (mp.count(i) == 0 && cnt1[i] > 0) {
                if (mx1 <= cnt1[i])
                    mx2 = mx1, p2 = p1, mx1 = cnt1[i], p1 = i;
                else if (mx2 <= cnt1[i])
                    mx2 = cnt1[i], p2 = i;
            }
        int nw_ans = mx1 + mx2;
        nw_ans += ((p1 != -1 && p2 != -1) ? cnt2[p1][p2] : 0);
        for (int i = 1; i <= n; i++)
            if (!cnt2[i].empty()) {
                auto it = cnt2[i].end();
                it--;
                int nw = 0;
                if ((*it).first == i) {
                    nw += (*it).second;
                    if (it != cnt2[i].begin()) it--;
                }
                nw += (*it).second;
                nw += cnt1[i] + cnt1[(*it).first];
                nw_ans = max(nw_ans, nw);
            }
        cout << nw_ans + ans << "\n";
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 12920kb

input:

5
4 12 7
5 7 3 6
3 6
2 2
1 4
2 4
1 3
7 6
4 1
5 4
1 1
1 1
2 1
3 7
2 7 6
2 4
1 2
3 2
2 5
5 4
2 6
4 6
2 6
1 1 2
1
1 2
2 1 2
1 2
1 2
2 1 100
24 11
11 24

output:

9
5
1
1
1

result:

ok 5 number(s): "9 5 1 1 1"

Test #2:

score: -100
Wrong Answer
time: 31ms
memory: 13136kb

input:

10000
19 12 20
8 12 1 5 11 7 17 13 19 6 3 9 10 15 14 20 4 18 16
4 11
7 1
8 4
16 19
1 13
15 2
16 2
8 7
3 15
11 13
5 20
18 14
17 14 20
2 9 1 12 8 11 10 17 18 16 3 15 5 14 20 13 7
15 10
3 2
5 16
7 8
6 1
6 4
18 16
1 8
4 1
20 6
6 9
4 15
7 5
14 9
1 3 18
9
15 18
17 15
11 14
7 19 7
3 1 2 5 6 4 7
5 1
4 5
3 1...

output:

12
14
1
19
6
4
1
11
19
4
3
10
4
1
4
19
15
2
18
4
17
5
1
2
5
17
3
2
6
15
6
3
6
4
4
7
3
7
4
1
16
15
2
3
6
12
12
7
6
8
8
6
8
11
16
1
4
9
8
14
2
6
19
19
16
8
20
14
8
12
7
9
6
8
2
17
9
5
5
3
6
6
20
8
13
11
10
5
2
6
3
1
8
5
8
11
7
14
10
9
9
11
7
9
5
2
8
14
10
5
3
5
5
10
1
6
9
16
5
3
19
1
4
8
8
10
4
2
1
15...

result:

wrong answer 6th numbers differ - expected: '5', found: '4'