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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#826755#9869. Horizon ScanningTravelerWA 210ms3896kbC++202.3kb2024-12-22 15:54:192024-12-22 15:54:20

Judging History

你现在查看的是最新测评结果

  • [2024-12-22 15:54:20]
  • 评测
  • 测评结果:WA
  • 用时:210ms
  • 内存:3896kb
  • [2024-12-22 15:54:19]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using ld = long double;
#define int long long
using i64 = long long;
struct Point {
    i64 x;
    i64 y;
    Point(i64 x = 0, i64 y = 0) : x(x), y(y) {}
};

bool operator==(const Point &a, const Point &b) {
    return a.x == b.x && a.y == b.y;
}

Point operator+(const Point &a, const Point &b) {
    return Point(a.x + b.x, a.y + b.y);
}

Point operator-(const Point &a, const Point &b) {
    return Point(a.x - b.x, a.y - b.y);
}
ld len(const Point &a) {
    return sqrtl(a.x * a.x + a.y * a.y);
}
//cos
i64 dot(const Point &a, const Point &b) {
    return a.x * b.x + a.y * b.y;
}
//sin
i64 cross(const Point &a, const Point &b) {
    return a.x * b.y - a.y * b.x;
}


void g(ld &a) {
    a = max(a, ld(-0.999999999999999));
    a = min(a, ld(0.999999999999999));
}
const ld PI = 3.1415926536;
ld get(Point a, Point b) {
    int dt = dot(a, b);
    int cro = cross(a, b);
    ld le = len(a) * len(b);
    ld ddt = 1.0 * dt / le;
    ld dcro = 1.0 * cro / le;
    g(ddt);
    g(dcro);
    if(cro > 0) {
        return acos(ddt);
    } else if(cro < 0) {
        return 2.0 * PI - acos(ddt);
    } else {
        if(dt > 0) return 0;
        return PI;
    }
    return 0;
}
Point O = {0, 0};
bool cmp1(Point a, Point b)
{
    return get(O, a) < get(O, b);
}

void solve() {
    int n, k;
    cin >> n >> k;
    vector<Point> a(n);
    for(int i = 0; i < n; i++) {
        cin >> a[i].x >> a[i].y;
        int G = gcd(a[i].x, a[i].y);
        a[i].x /= G;
        a[i].y /= G;
    }
    set<pair<int, int>> st;
    sort(a.begin(), a.end(), cmp1);
    vector<Point> b(2 * n);
    for(int i = 0; i < n; i++) {
        b[i] = b[i + n] = a[i];
    }
    ld ans = 0;
    for(int i = 0; i < n; i++) {
        int j = i + k;
        if(b[i] == b[j]) {
            if(j % n <= i % n) ans = fmax(ans, 2 * PI);
        }
        ans = fmax(ans, get(b[i], b[j]));
    }
    cout << ans << "\n";
}           
    
signed main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
    cout << fixed << setprecision(10);
    int T = 1;
    cin >> T;
    while(T--) solve();

    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3804kb

input:

5
1 1
0 1
8 2
1 0
1 1
0 1
-1 1
-1 0
-1 -1
0 -1
1 -1
4 2
-1 1
0 1
0 2
1 1
4 2
-1000000000 0
-998244353 1
998244353 1
1000000000 0
3 1
0 1
0 2
0 -1

output:

6.2831853072
1.5707963268
5.4977871438
3.1415926983
3.1415926536

result:

ok 5 numbers

Test #2:

score: -100
Wrong Answer
time: 210ms
memory: 3896kb

input:

10000
16 1
-10 -6
-5 -6
-4 9
-2 5
-2 10
1 -7
1 -5
1 6
3 1
4 -9
6 -10
6 -3
6 1
8 -5
8 -4
9 -4
17 4
-9 2
-8 -4
-8 -3
-8 -1
-6 -2
-6 -1
-6 8
-5 -8
-5 10
-4 8
-2 -8
4 -9
4 0
5 -3
8 -5
9 -2
10 10
10 6
-7 2
-4 6
-2 -7
-2 -1
-1 7
1 -9
1 8
3 -4
7 -4
9 -2
14 3
-9 10
-8 -10
-8 -8
-6 -7
-6 -5
-1 -7
-1 -2
0 -1
...

output:

6.2454673547
5.4977871438
5.0417151475
6.0818681988
5.8782935209
6.1099396407
5.5348072597
5.2416357612
6.2831853072
6.2831853072
5.6084443650
5.8000596424
5.8280844986
5.9179838574
6.0857897474
6.2831853072
6.1964469685
5.6659939157
6.1588303127
6.0529657199
6.0445759847
5.8195376982
5.4977871438
6...

result:

wrong answer 1st numbers differ - expected: '1.6929915', found: '6.2454674', error = '2.6890128'