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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#815530#9802. Light Up the Griducup-team1769#TL 0ms3832kbC++142.8kb2024-12-15 15:18:222024-12-15 15:18:32

Judging History

你现在查看的是最新测评结果

  • [2024-12-15 15:18:32]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:3832kb
  • [2024-12-15 15:18:22]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define max_len ((1 << (4)) + 10)
#define status_map(i1, i2, i3, i4) (((i1) * 0x1) | ((i2) * 0x2) | ((i3) * 0x4) | ((i4) * 0x8))

int min_cost[max_len];
int a1, a2, a3, a4;
void init_cost()
{
    memset(min_cost, 0x3f, sizeof(min_cost));
}

void bfs()
{
    // cost, status
    priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> que;
    que.push({0, status_map(1, 1, 1, 1)});
    while (que.size() != 0)
    {
        auto [co, st] = que.top();
        que.pop();
        if(min_cost[st] != 0x3f3f3f3f)
        {
            continue;
        }
        min_cost[st] = co;

        auto mask_status = [&] (int mask_s, int cost_use){
            int new_st = st ^ mask_s;
            que.push({co + cost_use, new_st});
        };
        mask_status(status_map(1, 1, 1, 1), a4);
        
        mask_status(status_map(1, 0, 1, 0), a3);
        mask_status(status_map(0, 1, 0, 1), a3);
        
        mask_status(status_map(1, 1, 0, 0), a2);
        mask_status(status_map(0, 0, 1, 1), a2);

        mask_status(status_map(1, 0, 0, 0), a1);
        mask_status(status_map(0, 1, 0, 0), a1);
        mask_status(status_map(0, 0, 1, 0), a1);
        mask_status(status_map(0, 0, 0, 1), a1);
    }
}

int can_stauts[max_len];
int status_vis[max_len];
int N;
int min_ans = 0x3f3f3f3f;

void dfs(int now_i, int all_mask, int all_cost, int pas_st)
{

    status_vis[now_i] = 1;
    pas_st++;
    all_cost += min_cost[all_mask ^ can_stauts[now_i]];
    all_mask ^= ((all_mask ^ can_stauts[now_i]) ^ status_map(1, 1, 1, 1));

    if(all_cost >= min_ans)
    {
        status_vis[now_i] = 0;
        return;
    }

    if(pas_st == N)
    {
        min_ans = min(min_ans, all_cost);
    }
    else
    {
        for (int i = 0; i < N; i++)
        {
            if(status_vis[i] == 0)
            {
                dfs(i, all_mask, all_cost, pas_st);
            }
        }
    }

    status_vis[now_i] = 0;
}

int get_ans()
{
    for (int i = 0; i < N; i++)
    {
        dfs(i, 0, 0, 0);
    }
    
    return min_ans;
}
#define ch2int(ch) ((ch) - '0')
void sol()
{
    cin >> N;
    for (int i = 0; i < N; i++)
    {
        string s1, s2;
        cin >> s1 >> s2;
        can_stauts[i] = status_map(ch2int(s1[0]), ch2int(s1[1]), ch2int(s2[0]), ch2int(s2[1]));

    }
    if(N == 1 && can_stauts[0] == 0x0f)
    {
        cout << min(2 * a4, min(2 * a3, min(2 * a2, 2 * a1))) << "\n";
        return;
    }
    int ans = get_ans();
    cout << ans << "\n";
}


int main()
{
    // cout << status_map(1, 1, 1, 1) << endl;
    int T;
    cin >> T >> a1 >> a2 >> a3 >> a4;
    init_cost();
    bfs();
    while (T--)
    {
        sol();
    }
    
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3832kb

input:

2 1000 100 10 1
4
10
00

01
00

00
10

00
01
1
11
11

output:

1121
2

result:

ok 2 number(s): "1121 2"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3600kb

input:

2 1 1 1 1
4
10
00

01
00

00
10

00
01
1
11
11

output:

5
2

result:

ok 2 number(s): "5 2"

Test #3:

score: 0
Accepted
time: 0ms
memory: 3608kb

input:

1 1000000 1000000 1000000 1000000
1
11
11

output:

2000000

result:

ok 1 number(s): "2000000"

Test #4:

score: -100
Time Limit Exceeded

input:

10000 8 2 7 8
8
00
01

00
11

00
10

11
11

10
10

01
10

01
00

10
11
8
11
01

11
00

01
10

11
11

00
01

01
01

01
00

11
10
9
00
00

01
01

10
11

00
01

11
10

11
00

11
11

00
11

01
10
9
11
11

10
00

11
00

11
01

00
10

01
11

00
01

01
01

10
01
11
00
01

01
01

10
10

00
11

11
11

11
10
...

output:

32
30
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30
30
30
30
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30
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30
30
30
30
29
29
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25
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25
25
25
...

result: