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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#815011#692. Delete the PointsdadasWA 0ms3784kbC++174.1kb2024-12-15 00:51:192024-12-15 00:51:20

Judging History

This is the latest submission verdict.

  • [2024-12-15 00:51:20]
  • Judged
  • Verdict: WA
  • Time: 0ms
  • Memory: 3784kb
  • [2024-12-15 00:51:19]
  • Submitted

answer

#include <bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
// #define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update>
// #define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>
using namespace std;
void _main();
int main() {
	cin.tie(0);
	ios::sync_with_stdio(false);
	_main();
	return 0;
}
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using vi = std::vector<int>;
using vvi = std::vector<vi>;
using vl = std::vector<ll>;
using vii = std::vector<pair<int, int> >;
using vvl = std::vector<vl>;
using vll = std::vector<pair<ll , ll> >;
using vd = std::vector<double>;
using vvd = std::vector<vd>;
using vs = std::vector<std::string>;
using vvs = std::vector<vs>;
using vb = std::vector<bool>;
using vvb = std::vector<vb>;
using vc = std::vector<char>;
using vvc = std::vector<vc>;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;
using piil = std::pair<pair<int, int>, ll>;
using mii = std::map<int, int>;
using mll = std::map<ll, ll>;
using pql = std::priority_queue<ll>;
using pqi = std::priority_queue<int>;
using pqiil = std::priority_queue<pair<pair<int, int>, ll> >;
using pqii = std::priority_queue<pair<int, int> >;

#define pb push_back
#define ps push
#define eb emplace_back
#define is insert
#define er erase
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define sf(i) sizeof(i)
#define endl "\n"
#define all(v) (v).begin(), (v).end()
#define rep(i, L, R) for(ll i = L;i<=R;i++)
#define pcis precision

template<typename T>
struct infinity {
	static constexpr T max=std::numeric_limits<T>::max();
	static constexpr T min=std::numeric_limits<T>::min();
	static constexpr T value=std::numeric_limits<T>::max()/2;
	static constexpr T mvalue=std::numeric_limits<T>::min()/2;
};
template<typename T>constexpr T INF=infinity<T>::value;
constexpr ll lINF=INF<ll>;
constexpr int iINF = INF<int>;
constexpr ld PI = 3.1415926535897932384626;



void _main() {

	ll N;
	cin >> N;
	pll A[N+1];
	rep(i,1,N) cin >> A[i].f >> A[i].s;

	vl se;

	sort(A+1, A+N+1);
	// x좌표 작은거부터 추가하기

	rep(i,1,N) se.pb(A[i].f);
	sort(all(se));
	se.erase(unique(se.begin(),se.end()),se.end());// 중복도 제거함
	// 매 턴마다 적어도 1개씩 추가됨

	ll left = 0;

	vector<pll> bef;// y좌표가 큰거부터 나온다
	vector<pll> ME;// y좌표가 큰거부터 나온다
	// y큰거 -> x큰거

	vector<pair<pll, pll>> lst;

	for (auto xx : se) {

		// xx좌표를 하나씩 늘려감
		while (left < N && A[left+1].f == xx) {
			left++;
			auto [x,y] = A[left];
			ME.pb({x, y});
		}
		assert(ME.size() >= 1);

		if (bef.size()) {
			auto [x1, y1] = bef[0];
			pll X = ME[0];

			for (auto xx : ME) {
				if (abs(xx.s - y1) < abs(X.s - y1)) {
					// y좌표 차가 제일 가까운 놈을 씀
					X = xx;
				}
			}

			lst.pb({{min(x1, X.f), min(y1, X.s)}, {max(x1, X.f), max(y1, X.s)}});

			vll ME2;
			for (auto xx : ME) {
				if (xx==X)continue;
				ME2.pb(xx);
			}
			swap(ME, ME2);
		}
		bef.clear();

		sort(all(ME));// x좌표 같음 => y좌표 순으로 정렬됨
		ll M = ME.size();
		for (ll i = 0; i+1<M; i+=2) {
			auto [x1, y1] = ME[i];
			auto [x2, y2] = ME[i+1];
			lst.pb({{min(x1, x2), min(y1, y2)}, {max(x1, x2), max(y1, y2)}});
		}

		if (M%2 == 1) {
			bef.pb(ME[M-1]);
		}
		ME.clear();
	}
	
	bool USE[N+1];
	memset(USE, 0, sf(USE));
	assert(lst.size() == N/2);
	for (auto [a, b] : lst) {
		auto [x1, y1] = a;
		auto [x2, y2] = b;

		ll cnt = 0;
		for (ll i = 1; i<=N; i++) {
			if (USE[i])continue;
			auto [x,y] = A[i];
			if (x1 <= x && x <= x2 && y1 <= y && y <= y2) {
				cnt++;
				USE[i] = true;
			}
		}
		assert(cnt == 2);
		assert(x1 <= x2 && y1 <= y2);
	}

	cout << "Yes" << endl;

	for (auto [a, b] : lst) {
		auto [x1, y1] = a;
		auto [x2, y2] = b;
		cout << x1 << ".000 "<< y1 << ".000 " << x2 <<".500 " << y2<<".500" << endl;
	}







}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3784kb

input:

4
1 1
2 2
5 5
6 6

output:

Yes
1.000 1.000 2.500 2.500
5.000 5.000 6.500 6.500

result:

ok OK

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3536kb

input:

4
0 0
1 2
2 1
4 4

output:

Yes
0.000 0.000 1.500 2.500
2.000 1.000 4.500 4.500

result:

wrong answer Not a square in query 1