QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#814056 | #9868. GCD | propane# | TL | 2ms | 7756kb | C++20 | 968b | 2024-12-14 14:54:12 | 2024-12-14 14:54:20 |
Judging History
answer
#include<iostream>
#include<cstring>
#include<vector>
#include<numeric>
using namespace std;
using LL = long long;
const int maxn = 5005;
int f[maxn][maxn];
pair<int, int> pre[maxn][maxn];
LL a, b;
int dp(int x, int y){
if (y > a) return 1e9;
if (x == 0 and b - y == 0) return 0;
if (x == 0 or b - y == 0) return 1;
if (~f[x][y]) return f[x][y];
int ans = 1e9;
LL t = gcd(x, b - y);
ans = min(ans, 1 + dp(x - t, y));
ans = min(ans, 1 + dp(x, y + t));
return f[x][y] = ans;
}
int main(){
#ifdef LOCAL
freopen("data.in", "r", stdin);
freopen("data.out", "w", stdout);
#endif
cin.tie(0);
cout.tie(0);
ios::sync_with_stdio(0);
int T;
cin >> T;
while(T--){
cin >> a >> b;
for(int i = 0; i <= a; i++){
for(int j = 0; j <= a; j++){
f[i][j] = -1;
}
}
cout << dp(a, 0) << '\n';
}
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 7752kb
input:
3 3 4 12 20 114 514
output:
3 4 6
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 2ms
memory: 7756kb
input:
990 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 2 3 2 4 2...
output:
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 3 3 2 3 4 2 ...
result:
ok 990 lines
Test #3:
score: -100
Time Limit Exceeded
input:
2 4859 299556476011016293 4859 911621905353047038