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ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#810928 | #9619. 乘积,欧拉函数,求和 | Nana7 | TL | 111ms | 6292kb | C++14 | 2.1kb | 2024-12-12 13:32:57 | 2024-12-12 13:32:58 |
Judging History
answer
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#define I inline
#define int long long
using namespace std;
const int mod = 998244353;
const int MAXN = 65600;
const int V = 3010;
const int N = 2010;
int a[N],n,pri[N],cnt,f[2][MAXN],mask[V],mul[MAXN],g[2][MAXN];
int pw[22],id[N];
vector<int> v[V];
int qpow(int x,int y) {
if(y==0) return 1;
if(y==1) return x;
int mk=qpow(x,y/2);
return y%2?mk*mk%mod*x%mod:mk*mk%mod;
}
/*
3
1 2 3
*/
I void solve() {
cin>>n;
for(int i=1;i<=n;++i) cin>>a[i];
int lst=0; f[0][0]=1;
for(int i=1;i<=n;++i) {
int now=lst^1,mk=a[i];
for(int j=1;j<=16;++j) {
while(mk%pri[j]==0) mk/=pri[j];
}
if(mk!=1) {
v[mk].push_back(a[i]);
continue;
}
for(int j=0;j<pw[16];++j) f[now][j]=f[lst][j];
for(int j=0;j<pw[16];++j) {
int val=mul[mask[a[i]]-(j&mask[a[i]])];
f[now][j|mask[a[i]]]+=f[lst][j]*val%mod*a[i]%mod;
}
lst^=1;
}
for(int i=1;i<=3000;++i) {
if(!v[i].size()) continue;
for(int j=0;j<pw[16];++j) {
g[0][j]=f[lst][j];
g[1][j]=0;
}
for(auto &t:v[i]) {
//int fac=i,sfac=t/i;
for(int j=pw[16];j>=0;--j) {
int val=mul[mask[t/i]-(j&mask[t/i])];
g[1][j|mask[t/i]]+=g[1][j]*t%mod*val%mod;
g[1][j|mask[t/i]]+=g[0][j]*t%mod*qpow(i,mod-2)%mod*(i-1)%mod*val%mod;
g[1][j|mask[t/i]]%=mod;
}
}
for(int j=0;j<pw[16];++j) {
f[lst][j]=g[0][j]+g[1][j];
f[lst][j]%=mod;
}
}
int ans=0;
for(int i=0;i<pw[16];++i) {
ans+=f[lst][i];
ans%=mod;
}
cout<<ans<<endl;
}
I void init() {
for(int i=2;i*i<=3000;++i) {
bool can=1;
for(int j=2;j*j<=i;++j) {
if(i%j==0) can=0;
}
if(can) pri[++cnt]=i,id[i]=cnt;
}
pw[0]=1;
for(int i=1;i<=16;++i) pw[i]=pw[i-1]<<1;
for(int i=1;i<=3000;++i) {
for(int j=1;j<=16;++j) {
if(i%pri[j]==0) mask[i]|=pw[j-1];
}
}
for(int i=0;i<pw[16];++i) {
mul[i]=1;
for(int j=1;j<=16;++j) {
if(i&pw[j-1]) {
mul[i]*=qpow(pri[j],mod-2)*(pri[j]-1)%mod;
mul[i]%=mod;
}
}
}
}
signed main()
{
init();
solve();
}
Details
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Test #1:
score: 100
Accepted
time: 107ms
memory: 5316kb
input:
5 1 6 8 6 2
output:
892
result:
ok single line: '892'
Test #2:
score: 0
Accepted
time: 111ms
memory: 6292kb
input:
5 3 8 3 7 8
output:
3157
result:
ok single line: '3157'
Test #3:
score: -100
Time Limit Exceeded
input:
2000 79 1 1 1 1 1 1 2803 1 1 1 1 1 1 1609 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2137 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 613 1 499 1 211 1 2927 1 1 1327 1 1 1123 1 907 1 2543 1 1 1 311 2683 1 1 1 1 2963 1 1 1 641 761 1 1 1 1 1 1 1 1 1 1 1 1489 2857 1 1 1 1 1 1 1 1 1 1 1 1 1 967 1 821 1 1 1 1 2143 1861...