/** gnu specific **/
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
/** contains everything I need in std **/
#include <bits/stdc++.h>

#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define sz(S) ((int)S.size())
#define FOR(i, st_, n) for(int i = st_; i < n; ++i)
#define RFOR(i, n, end_) for(int i = (n)-1; i >= end_; --i)
#define x first
#define y second
#define pb push_back
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef unsigned long long ull;
typedef long double LD;
typedef pair<ull, ull> pull;
using namespace __gnu_pbds;
typedef tree<ll, null_type, less<>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
using namespace std;
#ifdef ONPC
mt19937 rnd(228);
#else
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
#endif


ll f(int p, int st, int prev, bool inc)
{
	if(p==0)
	{
		if(st==0) return 1;
		return 0;
	}
	ll res=0;
	if(inc)
	{
		for(int i=0;st-prev-i>=0;++i)
			res += f(p-1, st-prev-i, prev+i, inc);
		for(int i=prev-1;i >= 0;--i)
			res += f(p-1, st-i, i, false);
	}
	else
	{
		for(int i=prev;i >= 0;--i)
			res += f(p-1, st-i, i, false);
	}
	return res;
}

#define MAX_N 501
ll dp[2][MAX_N][MAX_N][2];

int solve()
{
	int n,m;
	if(!(cin>>n>>m))
		return 1;
	m-=n;
	
	FOR(i,0,MAX_N)FOR(j,0,2)dp[0][0][i][j]=1;

	
	FOR(p,0,n)
	{
		RFOR(st,MAX_N,0)
		{
			FOR(prev,0,MAX_N)
			{
				ll res=0;
				for(int i=0;st-prev-i>=0 && prev+i<MAX_N;++i)
					res += dp[p&1][st-prev-i][prev+i][true];
				
				for(int i=0;i <= prev-1 && i <= st;++i)
					res += dp[p&1][st-i][i][false];

				dp[(p+1)&1][st][prev][true]=res;
			}
			FOR(prev,0,MAX_N)
			{
				ll res=0;
				for(int i=0;i <= prev && st-i >= 0; ++i)
					res += dp[p&1][st-i][i][false];
				dp[(p+1)&1][st][prev][false]=res;
			}
		}
	}

	cout<<dp[n&1][m][0][true]<<'\n';
    return 0;
}

int32_t main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    int TET = 1e9;
    //cin >> TET;
    for (int i = 1; i <= TET; i++)
    {
        if (solve())
        {
            break;
        }
#ifdef ONPC
        cout << "__________________________" << endl;
#endif
    }
#ifdef ONPC
    cerr << endl << "finished in " << clock() * 1.0 / CLOCKS_PER_SEC << " sec" << endl;
#endif
}