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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#80608 | #5506. Hyperloop | zhouhuanyi | WA | 120ms | 9740kb | C++14 | 3.4kb | 2023-02-24 14:24:25 | 2023-02-24 14:24:27 |
Judging History
answer
#include<iostream>
#include<cstdio>
#include<queue>
#include<algorithm>
#include<vector>
#define N 100000
#define M 100
#define inf 1e9
using namespace std;
int read()
{
char c=0;
int sum=0;
while (c<'0'||c>'9') c=getchar();
while ('0'<=c&&c<='9') sum=sum*10+c-'0',c=getchar();
return sum;
}
struct reads
{
int num,data;
bool operator < (const reads &t)const
{
return data>t.data;
}
};
priority_queue<reads>q;
int T,n,m,tong[N+1],length,dis[N+1],p[N+1],pv[N+1],pvt[N+1],dst[N+1],dp[N+1][M+1];
vector<reads>E[N+1];
vector<int>A;
vector<int>B;
bool used[N+1];
bool cmp(int x,int y)
{
return x>y;
}
bool cmp2(int x,int y)
{
return dis[x]<dis[y];
}
void dijkstra()
{
int top;
dis[1]=0,q.push((reads){1,0});
while (!q.empty())
{
top=q.top().num,q.pop();
if (used[top]) continue;
used[top]=1;
for (int i=0;i<E[top].size();++i)
if (dis[E[top][i].num]>dis[top]+E[top][i].data)
dis[E[top][i].num]=dis[top]+E[top][i].data,q.push((reads){E[top][i].num,dis[E[top][i].num]});
}
return;
}
int main()
{
int x,y,z,op;
T=read();
while (T--)
{
n=read(),m=read(),length=0;
for (int i=1;i<=n;++i)
{
E[i].clear(),dis[i]=inf,used[i]=pv[i]=pvt[i]=dst[i]=0;
for (int j=1;j<=100;++j) dp[i][j]=0;
}
for (int i=1;i<=m;++i) x=read(),y=read(),z=read(),E[x].push_back((reads){y,z}),E[y].push_back((reads){x,z});
dijkstra();
for (int i=1;i<=n;++i) p[i]=i;
sort(p+1,p+n+1,cmp2);
for (int i=2;i<=n;++i)
if (dis[p[i]]<=dis[n])
{
for (int j=0;j<E[p[i]].size();++j)
if (dis[E[p[i]][j].num]+E[p[i]][j].data==dis[p[i]])
{
if (!pv[p[i]])
{
pv[p[i]]=E[p[i]][j].num;
for (int k=1;k<=100;++k) dp[p[i]][k]=dp[E[p[i]][j].num][k];
if (E[p[i]][j].data<=100) pvt[p[i]]=pvt[E[p[i]][j].num],dst[p[i]]=dst[E[p[i]][j].num],dp[p[i]][E[p[i]][j].data]++;
else pv[p[i]]=E[p[i]][j].num,dst[p[i]]=E[p[i]][j].data;
}
else
{
A.clear(),B.clear(),x=p[i];
while (pvt[x]) A.push_back(dst[x]),x=pvt[x];
x=E[p[i]][j].num;
while (pvt[x]) B.push_back(dst[x]),x=pvt[x];
if (E[p[i]][j].data>100) B.push_back(E[p[i]][j].data);
sort(A.begin(),A.end(),cmp),sort(B.begin(),B.end(),cmp),op=-1;
for (int k=0;k<min(A.size(),B.size());++k)
if (A[k]!=B[k])
{
if (A[k]>B[k])
{
op=0;
break;
}
else
{
op=1;
break;
}
}
if (A.size()!=B.size()) op=(A.size()<B.size());
if (op==-1)
{
for (int k=100;k>=1;--k)
if (dp[E[p[i]][j].num][k]+(k==E[p[i]][j].data)!=dp[p[i]][k])
{
if (dp[E[p[i]][j].num][k]+(k==E[p[i]][j].data)>dp[p[i]][k])
{
op=1;
break;
}
else
{
op=0;
break;
}
}
}
if (op==1)
{
pv[p[i]]=E[p[i]][j].num;
for (int k=1;k<=100;++k) dp[p[i]][k]=dp[E[p[i]][j].num][k];
if (E[p[i]][j].data<=100) pvt[p[i]]=pvt[E[p[i]][j].num],dst[p[i]]=dst[E[p[i]][j].num],dp[p[i]][E[p[i]][j].data]++;
else pv[p[i]]=E[p[i]][j].num,dst[p[i]]=E[p[i]][j].data;
}
}
}
}
x=n,tong[++length]=n;
while (x!=1) x=pv[x],tong[++length]=x;
printf("%d\n",length);
for (int i=length;i>=1;--i) printf("%d ",tong[i]);
puts("");
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 3ms
memory: 9156kb
input:
2 4 6 1 2 1 1 3 2 2 3 1 2 4 2 3 4 1 1 4 4 6 11 1 2 9 2 3 12 3 4 3 4 5 5 5 6 10 6 1 22 2 4 9 3 6 1 4 6 5 2 5 2 3 5 8
output:
3 1 2 4 5 1 2 5 3 6
result:
ok correct (2 test cases)
Test #2:
score: -100
Wrong Answer
time: 120ms
memory: 9740kb
input:
600 320 1547 204 81 13768 232 97 9939 97 249 3719 201 109 14322 183 132 40881 142 143 1 275 186 24548 18 236 7907 30 317 11845 131 130 1 311 300 11704 141 92 41925 174 191 32128 119 120 1 184 183 1 310 309 1 283 270 25477 233 141 36076 212 92 13770 307 110 40656 218 137 14033 180 85 41892 200 199 44...
output:
184 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 89 90 91 92 93 94 95 96 97 98 99 100 101 102 10...
result:
wrong answer Contestant's path is not optimal lexicographically (test case 3)